15

我从这里得到了我的更改的问题。我有以下代码：

from nltk.corpus import stopwords
>>> def content_text(text):
    stopwords = nltk.corpus.stopwords.words('english')
    content = [w for w in text if w.lower() in stopwords]
    return content

如何打印文本中出现频率最高的 10 个单词，其中 1)包括和 2)不包括停用词？

4

3 回答 3

22

nltk中有一个FreqDist函数

import nltk
allWords = nltk.tokenize.word_tokenize(text)
allWordDist = nltk.FreqDist(w.lower() for w in allWords)

stopwords = nltk.corpus.stopwords.words('english')
allWordExceptStopDist = nltk.FreqDist(w.lower() for w in allWords if w not in stopwords)

提取 10 个最常见的：

mostCommon= allWordDist.most_common(10).keys()
于 2015-02-08T11:15:06.910 回答
5

不确定is stopwords函数中的，我想它需要，in 但你可以使用 Counterdictmost_common(10)来获得 10 个最频繁的：

from collections import Counter
from string import punctuation


def content_text(text):
    stopwords = set(nltk.corpus.stopwords.words('english')) # 0(1) lookups
    with_stp = Counter()
    without_stp  = Counter()
    with open(text) as f:
        for line in f:
            spl = line.split()
            # update count off all words in the line that are in stopwrods
            with_stp.update(w.lower().rstrip(punctuation) for w in spl if w.lower() in stopwords)
               # update count off all words in the line that are not in stopwords
            without_stp.update(w.lower().rstrip(punctuation)  for w in spl if w  not in stopwords)
    # return a list with top ten most common words from each 
    return [x for x in with_stp.most_common(10)],[y for y in without_stp.most_common(10)]
wth_stop, wthout_stop = content_text(...)

如果您传入一个 nltk 文件对象，只需对其进行迭代：

def content_text(text):
    stopwords = set(nltk.corpus.stopwords.words('english'))
    with_stp = Counter()
    without_stp  = Counter()
    for word in text:
        # update count off all words in the line that are in stopwords
        word = word.lower()
        if word in stopwords:
             with_stp.update([word])
        else:
           # update count off all words in the line that are not in stopwords
            without_stp.update([word])
    # return a list with top ten most common words from each
    return [k for k,_ in with_stp.most_common(10)],[y for y,_ in without_stp.most_common(10)]

print(content_text(nltk.corpus.inaugural.words('2009-Obama.txt')))

nltk 方法包括标点符号，因此可能不是您想要的。

于 2015-02-08T10:32:00.743 回答
1

你可以试试这个：

for word, frequency in allWordsDist.most_common(10):
    print('%s;%d' % (word, frequency)).encode('utf-8')
于 2016-04-28T06:51:43.730 回答