51

给定一个方法签名:

public bool AreTheSame<T>(Expression<Func<T, object>> exp1, Expression<Func<T, object>> exp2)

如果两个表达式相同,最有效的说法是什么?这只需要对简单的表达式起作用,我的意思是所有“支持”的都是简单的 MemberExpressions,例如 c => c.ID。

一个示例调用可能是:

AreTheSame<User>(u1 => u1.ID, u2 => u2.ID); --> would return true
4

5 回答 5

51

更新:由于对我的解决方案感兴趣,我更新了代码,使其支持数组、新运算符和其他内容,并以更优雅的方式比较 AST。

这是 Marc 代码的改进版本,现在可以作为nuget 包使用:

public static class LambdaCompare
{
    public static bool Eq<TSource, TValue>(
        Expression<Func<TSource, TValue>> x,
        Expression<Func<TSource, TValue>> y)
    {
        return ExpressionsEqual(x, y, null, null);
    }

    public static bool Eq<TSource1, TSource2, TValue>(
        Expression<Func<TSource1, TSource2, TValue>> x,
        Expression<Func<TSource1, TSource2, TValue>> y)
    {
        return ExpressionsEqual(x, y, null, null);
    }

    public static Expression<Func<Expression<Func<TSource, TValue>>, bool>> Eq<TSource, TValue>(Expression<Func<TSource, TValue>> y)
    {
        return x => ExpressionsEqual(x, y, null, null);
    }

    private static bool ExpressionsEqual(Expression x, Expression y, LambdaExpression rootX, LambdaExpression rootY)
    {
        if (ReferenceEquals(x, y)) return true;
        if (x == null || y == null) return false;

        var valueX = TryCalculateConstant(x);
        var valueY = TryCalculateConstant(y);

        if (valueX.IsDefined && valueY.IsDefined)
            return ValuesEqual(valueX.Value, valueY.Value);

        if (x.NodeType != y.NodeType
            || x.Type != y.Type)
        {
            if (IsAnonymousType(x.Type) && IsAnonymousType(y.Type))
                throw new NotImplementedException("Comparison of Anonymous Types is not supported");
            return false;
        }

        if (x is LambdaExpression)
        {
            var lx = (LambdaExpression)x;
            var ly = (LambdaExpression)y;
            var paramsX = lx.Parameters;
            var paramsY = ly.Parameters;
            return CollectionsEqual(paramsX, paramsY, lx, ly) && ExpressionsEqual(lx.Body, ly.Body, lx, ly);
        }
        if (x is MemberExpression)
        {
            var mex = (MemberExpression)x;
            var mey = (MemberExpression)y;
            return Equals(mex.Member, mey.Member) && ExpressionsEqual(mex.Expression, mey.Expression, rootX, rootY);
        }
        if (x is BinaryExpression)
        {
            var bx = (BinaryExpression)x;
            var by = (BinaryExpression)y;
            return bx.Method == @by.Method && ExpressionsEqual(bx.Left, @by.Left, rootX, rootY) &&
                   ExpressionsEqual(bx.Right, @by.Right, rootX, rootY);
        }
        if (x is UnaryExpression)
        {
            var ux = (UnaryExpression)x;
            var uy = (UnaryExpression)y;
            return ux.Method == uy.Method && ExpressionsEqual(ux.Operand, uy.Operand, rootX, rootY);
        }
        if (x is ParameterExpression)
        {
            var px = (ParameterExpression)x;
            var py = (ParameterExpression)y;
            return rootX.Parameters.IndexOf(px) == rootY.Parameters.IndexOf(py);
        }
        if (x is MethodCallExpression)
        {
            var cx = (MethodCallExpression)x;
            var cy = (MethodCallExpression)y;
            return cx.Method == cy.Method
                   && ExpressionsEqual(cx.Object, cy.Object, rootX, rootY)
                   && CollectionsEqual(cx.Arguments, cy.Arguments, rootX, rootY);
        }
        if (x is MemberInitExpression)
        {
            var mix = (MemberInitExpression)x;
            var miy = (MemberInitExpression)y;
            return ExpressionsEqual(mix.NewExpression, miy.NewExpression, rootX, rootY)
                   && MemberInitsEqual(mix.Bindings, miy.Bindings, rootX, rootY);
        }
        if (x is NewArrayExpression)
        {
            var nx = (NewArrayExpression)x;
            var ny = (NewArrayExpression)y;
            return CollectionsEqual(nx.Expressions, ny.Expressions, rootX, rootY);
        }
        if (x is NewExpression)
        {
            var nx = (NewExpression)x;
            var ny = (NewExpression)y;
            return
                Equals(nx.Constructor, ny.Constructor)
                && CollectionsEqual(nx.Arguments, ny.Arguments, rootX, rootY)
                && (nx.Members == null && ny.Members == null
                    || nx.Members != null && ny.Members != null && CollectionsEqual(nx.Members, ny.Members));
        }
        if (x is ConditionalExpression)
        {
            var cx = (ConditionalExpression)x;
            var cy = (ConditionalExpression)y;
            return
                ExpressionsEqual(cx.Test, cy.Test, rootX, rootY)
                && ExpressionsEqual(cx.IfFalse, cy.IfFalse, rootX, rootY)
                && ExpressionsEqual(cx.IfTrue, cy.IfTrue, rootX, rootY);
        }

        throw new NotImplementedException(x.ToString());
    }

    private static Boolean IsAnonymousType(Type type)
    {
        Boolean hasCompilerGeneratedAttribute = type.GetCustomAttributes(typeof(CompilerGeneratedAttribute), false).Any();
        Boolean nameContainsAnonymousType = type.FullName.Contains("AnonymousType");
        Boolean isAnonymousType = hasCompilerGeneratedAttribute && nameContainsAnonymousType;

        return isAnonymousType;
    }

    private static bool MemberInitsEqual(ICollection<MemberBinding> bx, ICollection<MemberBinding> by, LambdaExpression rootX, LambdaExpression rootY)
    {
        if (bx.Count != by.Count)
        {
            return false;
        }

        if (bx.Concat(by).Any(b => b.BindingType != MemberBindingType.Assignment))
            throw new NotImplementedException("Only MemberBindingType.Assignment is supported");

        return
            bx.Cast<MemberAssignment>().OrderBy(b => b.Member.Name).Select((b, i) => new { Expr = b.Expression, b.Member, Index = i })
            .Join(
                  by.Cast<MemberAssignment>().OrderBy(b => b.Member.Name).Select((b, i) => new { Expr = b.Expression, b.Member, Index = i }),
                  o => o.Index, o => o.Index, (xe, ye) => new { XExpr = xe.Expr, XMember = xe.Member, YExpr = ye.Expr, YMember = ye.Member })
                   .All(o => Equals(o.XMember, o.YMember) && ExpressionsEqual(o.XExpr, o.YExpr, rootX, rootY));
    }

    private static bool ValuesEqual(object x, object y)
    {
        if (ReferenceEquals(x, y))
            return true;
        if (x is ICollection && y is ICollection)
            return CollectionsEqual((ICollection)x, (ICollection)y);

        return Equals(x, y);
    }

    private static ConstantValue TryCalculateConstant(Expression e)
    {
        if (e is ConstantExpression)
            return new ConstantValue(true, ((ConstantExpression)e).Value);
        if (e is MemberExpression)
        {
            var me = (MemberExpression)e;
            var parentValue = TryCalculateConstant(me.Expression);
            if (parentValue.IsDefined)
            {
                var result =
                    me.Member is FieldInfo
                        ? ((FieldInfo)me.Member).GetValue(parentValue.Value)
                        : ((PropertyInfo)me.Member).GetValue(parentValue.Value);
                return new ConstantValue(true, result);
            }
        }
        if (e is NewArrayExpression)
        {
            var ae = ((NewArrayExpression)e);
            var result = ae.Expressions.Select(TryCalculateConstant);
            if (result.All(i => i.IsDefined))
                return new ConstantValue(true, result.Select(i => i.Value).ToArray());
        }
        if (e is ConditionalExpression)
        {
            var ce = (ConditionalExpression)e;
            var evaluatedTest = TryCalculateConstant(ce.Test);
            if (evaluatedTest.IsDefined)
            {
                return TryCalculateConstant(Equals(evaluatedTest.Value, true) ? ce.IfTrue : ce.IfFalse);
            }
        }

        return default(ConstantValue);
    }

    private static bool CollectionsEqual(IEnumerable<Expression> x, IEnumerable<Expression> y, LambdaExpression rootX, LambdaExpression rootY)
    {
        return x.Count() == y.Count()
               && x.Select((e, i) => new { Expr = e, Index = i })
                   .Join(y.Select((e, i) => new { Expr = e, Index = i }),
                         o => o.Index, o => o.Index, (xe, ye) => new { X = xe.Expr, Y = ye.Expr })
                   .All(o => ExpressionsEqual(o.X, o.Y, rootX, rootY));
    }

    private static bool CollectionsEqual(ICollection x, ICollection y)
    {
        return x.Count == y.Count
               && x.Cast<object>().Select((e, i) => new { Expr = e, Index = i })
                   .Join(y.Cast<object>().Select((e, i) => new { Expr = e, Index = i }),
                         o => o.Index, o => o.Index, (xe, ye) => new { X = xe.Expr, Y = ye.Expr })
                   .All(o => Equals(o.X, o.Y));
    }

    private struct ConstantValue
    {
        public ConstantValue(bool isDefined, object value)
            : this()
        {
            IsDefined = isDefined;
            Value = value;
        }

        public bool IsDefined { get; private set; }

        public object Value { get; private set; }
    }
}

请注意,它不比较完整的 AST。相反,它折叠常量表达式并比较它们的值而不是它们的 AST。当 lambda 具有对局部变量的引用时,它对于模拟验证很有用。在他的例子中,变量是通过它的值来比较的。

单元测试:

[TestClass]
public class Tests
{
    [TestMethod]
    public void BasicConst()
    {
        var f1 = GetBasicExpr1();
        var f2 = GetBasicExpr2();
        Assert.IsTrue(LambdaCompare.Eq(f1, f2));
    }

    [TestMethod]
    public void PropAndMethodCall()
    {
        var f1 = GetPropAndMethodExpr1();
        var f2 = GetPropAndMethodExpr2();
        Assert.IsTrue(LambdaCompare.Eq(f1, f2));
    }

    [TestMethod]
    public void MemberInitWithConditional()
    {
        var f1 = GetMemberInitExpr1();
        var f2 = GetMemberInitExpr2();
        Assert.IsTrue(LambdaCompare.Eq(f1, f2));
    }

    [TestMethod]
    public void AnonymousType()
    {
        var f1 = GetAnonymousExpr1();
        var f2 = GetAnonymousExpr2();
        Assert.Inconclusive("Anonymous Types are not supported");
    }

    private static Expression<Func<int, string, string>> GetBasicExpr2()
    {
        var const2 = "some const value";
        var const3 = "{0}{1}{2}{3}";
        return (i, s) =>
            string.Format(const3, (i + 25).ToString(CultureInfo.InvariantCulture), i + s, const2.ToUpper(), 25);
    }

    private static Expression<Func<int, string, string>> GetBasicExpr1()
    {
        var const1 = 25;
        return (first, second) =>
            string.Format("{0}{1}{2}{3}", (first + const1).ToString(CultureInfo.InvariantCulture), first + second,
                "some const value".ToUpper(), const1);
    }

    private static Expression<Func<Uri, bool>> GetPropAndMethodExpr2()
    {
        return u => Uri.IsWellFormedUriString(u.ToString(), UriKind.Absolute);
    }

    private static Expression<Func<Uri, bool>> GetPropAndMethodExpr1()
    {
        return arg1 => Uri.IsWellFormedUriString(arg1.ToString(), UriKind.Absolute);
    }

    private static Expression<Func<Uri, UriBuilder>> GetMemberInitExpr2()
    {
        var isSecure = true;
        return u => new UriBuilder(u) { Host = string.IsNullOrEmpty(u.Host) ? "abc" : "def" , Port = isSecure ? 443 : 80 };
    }

    private static Expression<Func<Uri, UriBuilder>> GetMemberInitExpr1()
    {
        var port = 443;
        return x => new UriBuilder(x) { Port = port, Host = string.IsNullOrEmpty(x.Host) ? "abc" : "def" };
    }

    private static Expression<Func<Uri, object>> GetAnonymousExpr2()
    {
        return u => new { u.Host , Port = 443, Addr = u.AbsolutePath };
    }

    private static Expression<Func<Uri, object>> GetAnonymousExpr1()
    {
        return x => new { Port = 443, x.Host, Addr = x.AbsolutePath };
    }
}
于 2014-07-02T10:06:33.260 回答
39

嗯......我猜你必须解析树,检查每个节点类型和成员。我举个例子...

using System;
using System.Linq.Expressions;
class Test {
    public string Foo { get; set; }
    public string Bar { get; set; }
    static void Main()
    {
        bool test1 = FuncTest<Test>.FuncEqual(x => x.Bar, y => y.Bar),
            test2 = FuncTest<Test>.FuncEqual(x => x.Foo, y => y.Bar);
    }

}
// this only exists to make it easier to call, i.e. so that I can use FuncTest<T> with
// generic-type-inference; if you use the doubly-generic method, you need to specify
// both arguments, which is a pain...
static class FuncTest<TSource>
{
    public static bool FuncEqual<TValue>(
        Expression<Func<TSource, TValue>> x,
        Expression<Func<TSource, TValue>> y)
    {
        return FuncTest.FuncEqual<TSource, TValue>(x, y);
    }
}
static class FuncTest {
    public static bool FuncEqual<TSource, TValue>(
        Expression<Func<TSource,TValue>> x,
        Expression<Func<TSource,TValue>> y)
    {
        return ExpressionEqual(x, y);
    }
    private static bool ExpressionEqual(Expression x, Expression y)
    {
        // deal with the simple cases first...
        if (ReferenceEquals(x, y)) return true;
        if (x == null || y == null) return false;
        if (   x.NodeType != y.NodeType
            || x.Type != y.Type ) return false;

        switch (x.NodeType)
        {
            case ExpressionType.Lambda:
                return ExpressionEqual(((LambdaExpression)x).Body, ((LambdaExpression)y).Body);
            case ExpressionType.MemberAccess:
                MemberExpression mex = (MemberExpression)x, mey = (MemberExpression)y;
                return mex.Member == mey.Member; // should really test down-stream expression
            default:
                throw new NotImplementedException(x.NodeType.ToString());
        }
    }
}
于 2008-11-12T10:36:44.133 回答
4

一个规范的解决方案会很棒。与此同时,我创建了一个IEqualityComparer<Expression>版本。这是一个相当冗长的实现,所以我为它创建了一个要点

它旨在成为一个全面的抽象语法树比较器。为此,它会比较每种表达式类型,包括 C# 尚不支持的表达式,例如TryandSwitchBlock。由于我对它们的了解有限,它唯一不比较的类型是Goto,和。LabelLoopDebugInfo

您可以指定是否以及如何比较参数和 lambda 的名称,以及如何处理ConstantExpression.

它按上下文位置跟踪参数。支持 lambda 内的 Lambda 和 catch 块变量参数。

于 2015-06-16T18:15:01.207 回答
2

我知道这是一个老问题,但我推出了自己的表达式树相等比较器 - https://github.com/yesmarket/yesmarket.Linq.Expressions

该实现大量使用 ExpressionVisitor 类来确定两个表达式树是否相等。当遍历表达式树中的节点时,会比较各个节点是否相等。

于 2016-05-29T02:52:09.120 回答
0

我认为,当您使用高效 lambda 集合Lambdas时,您将获得最大的效率——我的意思是基于列的集合,它只能由一个或多个选定的列枚举,通过分别在每列上实现来实现这一点——让我们称之为 第一步;)IEnumerable

这只是我想在某一天做的想法。目前我没有任何线索,但我想很多人会同意我的观点,即通过单个变量列表检查值与检查对象列表中的某些属性相比,就像证明自己一样。

下一步从函数式编程中获得更多信息:使用 sorted-list 、 hash-table 或任何其他搜索效率高的集合作为表示集合

class LambdaReadyColumn<int> : HashTable<int> 

另一个第三步用一些指针连接列之间的项目,而不是将列在引擎盖下:

class LambdaReadyColumn<int> : IEnumabrable<int> 

将数据保存在更接近:

class LambdaReadyColumn<LambdaReadyColumnItem<T, int>> : IEnumabrable<int> 
//with example constructor like: 
public LambdaReadyColumn<LambdaReadyColumnItem<T, int>>(Hash, LambdaReadyColumnItem, LambdaReadyColumnItem, T, int); 

在哪里:

  • CollectionItem - 对同一 T 项的左右列项的引用
  • 哈希 - 使搜索更快
  • int - 表示列的类型
  • T -列集合中的第四步Select(T)整个 LambdaReadyCollection 很容易理解,只是为了使返回的项目描述符更快,但也避免为具有许多属性的项目向左/向右遍历少量引用。

最后,通过所有步骤,我们收集了双重数据:基于行和基于集合的额外大量参考数据。当然,基于行的 HashTable 可以只保留基于数据和基于列的引用,但是构建每个集合以从语句返回将使用大量引用。

要实现它,您需要根据语言使用反射、动态类型或其他高级技术。

于 2020-04-20T06:47:17.730 回答