2

如何在 button_click() 中的 asp.net(vb) 中单击另一个按钮后使链接按钮可见

它说错误为“对象引用未设置为对象的实例”。

我已经在我的代码中做到了

Protected Sub InsertButton_Click(ByVal sender As Object, ByVal e As System.EventArgs)

    Dim receipt As LinkButton = FormView1.FindControl("LinkButton1")

   ' receipt.Enabled = "true"
   ' receipt.EnableTheming = "true"
   ' receipt.EnableViewState = "true"
    receipt.Visible = "true"

结束子

4

2 回答 2

1

像这样删除表单名称：

Dim receipt As LinkButton = FindControl("LinkButton1")
If (Not receipt Is Nothing)
   ' receipt.Enabled = "true"
   ' receipt.EnableTheming = "true"
   ' receipt.EnableViewState = "true"
    receipt.Visible = "true"
End if
于 2010-05-14T15:29:56.257 回答
0

或者像这样...

    LinkButton1.Visible = "true"
于 2010-05-14T15:39:35.807 回答