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我正在为我玩的游戏制作聊天机器人，机器人本身运行良好，现在我需要做的是让机器人自动添加它收到的任何请求。

我不知道该怎么做，做一些谷歌搜索我发现有人说 def add_friend(self, user): self._send(xmpp.Presence(to=user, typ='subscribed')) self._send(xmpp.Presence(to=user, typ='subscribe')) return True

会做的伎俩，但我不知道如何在我的代码中实现它。

这是我使用 Python 的消息传递系统的代码基础：

import xmpp

conn = xmpp.Client("domain here..")
if not conn.connect(server=("<server here>", 5223)):
    print "connect failed."
    exit()

if not conn.auth("USER ID", "PASS HERE", "xiff"):
    print "auth failed."
    exit()

roster = None

def message_handler(conn, msg):
    user = roster.getName(str(msg.getFrom()))
    text = msg.getBody()

    print "[%s] %s" % (user, text)

    reply = msg.buildReply("[ECHO] %s" % (text))
    reply.setType("chat")
    conn.send(reply)

conn.RegisterHandler("message", message_handler)
conn.sendInitPresence(requestRoster=1)
roster = conn.getRoster()

while conn.isConnected():
    try:
        conn.Process(10)
    except KeyboardInterrupt:
        break

当用户尝试添加机器人时，会显示以下内容：

<iq to="sum64756669@pvp.net" from="sum64756669@pvp.net/xiff" id="2861886931" type="error">
  <query xmlns="jabber:iq:riotgames:roster">
  <item jid="sum50971931@pvp.net" name="Top Mid Lane NA" subscription="pending_in" />
  </query>
  <error code="501" type="cancel">
  <feature-not-implemented xmlns="urn:ietf:params:xml:ns:xmpp-stanzas" />
  <text xmlns="urn:ietf:params:xml:ns:xmpp-stanzas">The feature requested is not implemented by the recipient or server and therefore cannot be processed.</text>
  </error>
  </iq>
DEBUG: socket       got   <presence to='sum64756669@pvp.net/xiff' from='sum50971931@pvp.net' name='Top Mid Lane NA' type='subscribe'>
  <priority>0</priority>
  </presence>

任何想法，我已经坚持了几天！

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1 回答 1

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您应该实施存在处理程序以接受订阅：

def presence(conn, event):
    if event.getType() == 'subscribe':
        conn.send(xmpp.Presence(to=event.getFrom(), typ='subscribed'))

conn.RegisterHandler('presence', presence)
于 2015-12-20T09:35:28.237 回答