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嗨，我正在使用 rails 插件acts-as-taggable-on，我正在尝试查找名称匹配并部分匹配给定查询的前 5 个最常用的标签。

当我做User.skill_counts.order('count DESC').limit(5).where('name LIKE ?', params[:query])

这将返回以下错误：

ActiveRecord::StatementInvalid: SQLite3::SQLException: ambiguous column name: name: SELECT     tags.*, COUNT(*) AS count FROM       "tags" INNER JOIN users ON users.id = taggings.taggable_id LEFT OUTER JOIN taggings ON tags.id = taggings.tag_id AND taggings.context = 'skills' WHERE     (taggings.taggable_type = 'User') AND (taggings.taggable_id IN(SELECT     users.id FROM       "users")) AND (name LIKE 'asd') GROUP BY  tags.id, tags.name HAVING    COUNT(*) > 0 ORDER BY  count DESC LIMIT 5

但是当我这样做时User.skill_counts.first.name

这返回

"alliteration"

我将不胜感激在这件事上的任何帮助。

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1 回答 1

4

旅游查询应该是这样的

SELECT  tags.*, COUNT(*) AS count FROM  "tags" 
         INNER JOIN users ON users.id = taggings.taggable_id 
         LEFT OUTER JOIN taggings ON tags.id = taggings.tag_id AND taggings.context = 'skills'
         WHERE  (taggings.taggable_type = 'User') AND 
                (taggings.taggable_id IN(SELECT users.id FROM "users")) AND 
               (tags.name LIKE 'asd') 
         GROUP BY  tags.id, tags.name HAVING COUNT(*) > 0 
         ORDER BY  count DESC 
         LIMIT 5

为此尝试以下

User.skill_counts.order('count DESC').limit(5).where('tags.name LIKE ?', params[:query])
于 2010-05-12T07:05:30.117 回答