我正在尝试使用 CanvasJS 和 PHP 创建一个范围面积图以从数据库加载数据。
我创建了 php,它从数据库返回值。这是php:
<?php
header('Content-Type: application/json');
$con = mysqli_connect("127.0.0.1","root","pwd1","db");
// Check connection
if (mysqli_connect_errno($con))
{
echo "Failed to connect to DataBase: " . mysqli_connect_error();
}else
{
$data_points = array();
$result = mysqli_query($con, "select (CalYear+1) as CalYear, concat('[',REPLACE(Year1PercWC,',','.'),',',REPLACE(Year1PercBC,',','.'),']') as ResultSet, concat('Sessies: ',calyear) as Help FROM table where cat='1' and (CalYear+1)<year(now())");
while($row = mysqli_fetch_array($result))
{
$point = array("x" => $row['CalYear'] , "y" => $row['ResultSet'],"name" => $row['Help']);
array_push($data_points, $point);
}
echo json_encode($data_points);
}
mysqli_close($con);
?>
结果:
[{"x":"2007","y":"[35.94,35.94]","name":"Sessies: 2006"},{"x":"2008","y":"[27.67, 27.67]","name":"Sessies: 2007"},...,...]
问题是 x 和 y 值(=字符串值)中的引号。CanvasJS 只需要数字来创建图表。所以输出应该是这样的:
[{"x":2007,"y":[35.94,35.94],"name":"Sessies 2006"},{"x":2008,"y":[27.67,27.67],"name":" Sessies 2007"},...,...]
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml" >
<head>
<title></title>
<script type="text/javascript" src="jquery-1.11.2.min.js"></script>
<script type="text/javascript" src="jquery.canvasjs.min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$.getJSON("TestGraf.php", function (result) {
var chart = new CanvasJS.Chart("chartContainer", {
axisX: {
intervalType: "number",
title: "Year",
interval: 1,
valueFormatString: "#"
},
data: [
{
type: "rangeArea",
dataPoints: result
[{"x":2007,"y":[35.94,35.94],"name":"Sessies 2006"},{"x":2008,"y":[27.67,27.67],"name":"Sessies 2007"}] -- This is working fine
}
]
});
chart.render();
});
});
</script>
</head>
<body>
<div id="chartContainer" style="width: 800px; height: 380px;"></div>
</body>
</html>
我确信必须有一种方法来调整我的 php,以便 x 和 y 作为数字而不是字符串传递,但我真的是 php 新手(有史以来第一次)并且找不到解决方案,尤其是对于第二部分(y)。
谁能告诉我要对 php 和/或 html 文件进行哪些调整?
谢谢,