python - Django restframework - 如何将两个查询集按优先级组合到序列化？

Question

这是我的原始查询： Movie.objects.filter(releaseday__gte=past_month.date(),releaseday__lte=today.date(),movie__movietime__gte=today).extra({'vrank': 'CASE WHEN hotrank=0 THEN 4 WHEN hotrank >=4 THEN 4 ELSE hotrank END'}).distinct().order_by('vrank','-releaseday')

但结果有重复。
我看文件，它说问题是使用order_by()和distinct()一起

queryset1所以现在我需要queryset2按顺序组合。先显示结果queryset1，
然后queryset2 请帮帮我，谢谢

视图.py：

class MovieList(MovieMixin, generics.ListAPIView):
    serializer_class = MovieSerializer

    def get(self, request, *args, **kwargs):
        if request.GET.get("top"):
            self.top(top)
        return super(MovieList, self).get(request, *args, **kwargs)

    def top(self,top):    
        queryset1 = Movie.objects.filter(releaseday__gte=past_month.date(),releaseday__lte=today.date(),movie__movietime__gte=today,hotrank__lte=3).exclude(hotrank=0).distinct().order_by('hotrank')
        queryset2 = Movie.objects.filter(releaseday__gte=past_month.date(),releaseday__lte=today.date(),movie__movietime__gte=today).exclude(hotrank__lte=3,hotrank__gte=1).distinct().order_by('-releaseday')

        self.queryset =( queryset1 | queryset2 )

Answer 1

你可以尝试使用这个

from itertools import chain
....
self.queryset = sorted(chain(queryset1, queryset2),
    key=lambda instance: instance.releaseday)

这将结合 queryset1 和 queryset2 ，然后按值对它们进行排序realaseday。