我正在将 FOSElasticaBundle 与 symfony2 和教义 2 一起使用。
我很难理解如何从搜索结果中检索实际的教义对象。我的印象是这是默认行为,但我得到了这种结果:
object(Elastica\Result)[1239]
protected '_hit' =>
array (size=5)
'_index' => string 'foodmeup' (length=8)
'_type' => string 'recipes' (length=7)
'_id' => string '2' (length=1)
'_score' => float 2.2963967
'_source' =>
array (size=5)
'name' => string 'Bavaroise vanille' (length=17)
'nickName' => string 'Bavaroise vanille' (length=17)
'content' => null
'userRecipes' =>
array (size=1)
...
'tags' =>
array (size=0)
这是我的 FOSElasticaBundle 配置:
#Elastic Search
fos_elastica:
default_manager: orm
clients:
default: { host: localhost, port: 9200 }
indexes:
search:
client: default
index_name: foodmeup
types:
recipes:
mappings:
name: { type: string, boost: 5}
nickName: { type: string }
content: { type: string }
userRecipes:
type: "nested"
properties:
name: { type: string }
content: { type: string }
tags:
type: "nested"
boost: 5
properties:
name: { type: string }
persistence:
driver: orm
model: AppBundle\Entity\FoodAnalytics\Recipe
repository: AppBundle\Repository\FoodAnalytics\RecipeRepository
provider: ~
finder: ~
listener: ~ # by default, listens to "insert", "update" and "delete"
我的控制器中的代码:
public function searchAction(Request $request)
{
$search = $request->query->get('search');
$finder = $this->get('fos_elastica.index.search.recipes');
$results = $finder->search($search)->getResults();
return array(
'search' => $search,
'results' => $results
);
}
我知道我可以使用自定义存储库方法来获取对象,但是在达到那个点之前,获取对象的默认方法是什么?(这里我想要一个食谱对象,我的模型的一个实例)。
非常感谢 !