我一直在试图找出一种方法来获得某种能够在 Python 2.7 下返回 Windows 中符号链接的真正抽象路径的能力。（我无法升级到 3.x，因为 Maya/3ds max 等大多数 DCC 不使用该版本的 Python）
我查看了 sid0 ntfs utils（它的 islink() 函数有效，但 readlink() 函数由于某种原因总是为我返回一个空的 unicode 字符串）和 juntalis ntfs 库（不幸的是，我无法访问工作），以及有人发布的有用脚本：
import os, ctypes, struct
from ctypes import windll, wintypes
FSCTL_GET_REPARSE_POINT = 0x900a8
FILE_ATTRIBUTE_READONLY = 0x0001
FILE_ATTRIBUTE_HIDDEN = 0x0002
FILE_ATTRIBUTE_DIRECTORY = 0x0010
FILE_ATTRIBUTE_NORMAL = 0x0080
FILE_ATTRIBUTE_REPARSE_POINT = 0x0400
GENERIC_READ = 0x80000000
GENERIC_WRITE = 0x40000000
OPEN_EXISTING = 3
FILE_READ_ATTRIBUTES = 0x80
FILE_FLAG_OPEN_REPARSE_POINT = 0x00200000
INVALID_HANDLE_VALUE = wintypes.HANDLE(-1).value
INVALID_FILE_ATTRIBUTES = 0xFFFFFFFF
FILE_FLAG_OPEN_REPARSE_POINT = 2097152
FILE_FLAG_BACKUP_SEMANTICS = 33554432
# FILE_FLAG_OPEN_REPARSE_POINT | FILE_FLAG_BACKUP_SEMANTI
FILE_FLAG_REPARSE_BACKUP = 35651584
GetFileAttributes = windll.kernel32.GetFileAttributesW
_CreateFileW = windll.kernel32.CreateFileW
_DevIoCtl = windll.kernel32.DeviceIoControl
_DevIoCtl.argtypes = [
wintypes.HANDLE, #HANDLE hDevice
wintypes.DWORD, #DWORD dwIoControlCode
wintypes.LPVOID, #LPVOID lpInBuffer
wintypes.DWORD, #DWORD nInBufferSize
wintypes.LPVOID, #LPVOID lpOutBuffer
wintypes.DWORD, #DWORD nOutBufferSize
ctypes.POINTER(wintypes.DWORD), #LPDWORD lpBytesReturned
wintypes.LPVOID] #LPOVERLAPPED lpOverlapped
_DevIoCtl.restype = wintypes.BOOL
def islink(path):
# assert os.path.isdir(path), path
if GetFileAttributes(path) & FILE_ATTRIBUTE_REPARSE_POINT:
return True
else:
return False
def DeviceIoControl(hDevice, ioControlCode, input, output):
# DeviceIoControl Function
# http://msdn.microsoft.com/en-us/library/aa363216(v=vs.85).aspx
if input:
input_size = len(input)
else:
input_size = 0
if isinstance(output, int):
output = ctypes.create_string_buffer(output)
output_size = len(output)
assert isinstance(output, ctypes.Array)
bytesReturned = wintypes.DWORD()
status = _DevIoCtl(hDevice, ioControlCode, input,
input_size, output, output_size, bytesReturned, None)
print "status(%d)" % status
if status != 0:
return output[:bytesReturned.value]
else:
return None
def CreateFile(path, access, sharemode, creation, flags):
return _CreateFileW(path, access, sharemode, None, creation, flags, None)
SymbolicLinkReparseFormat = "LHHHHHHL"
SymbolicLinkReparseSize = struct.calcsize(SymbolicLinkReparseFormat);
def readlink(path):
""" Windows readlink implementation. """
# This wouldn't return true if the file didn't exist, as far as I know.
assert islink(path)
# assert type(path) == unicode
# Open the file correctly depending on the string type.
hfile = CreateFile(path, GENERIC_READ, 0, OPEN_EXISTING,
FILE_FLAG_REPARSE_BACKUP)
# MAXIMUM_REPARSE_DATA_BUFFER_SIZE = 16384 = (16*1024)
buffer = DeviceIoControl(hfile, FSCTL_GET_REPARSE_POINT, None, 16384)
windll.CloseHandle(hfile)
# Minimum possible length (assuming length of the target is bigger than 0)
if not buffer or len(buffer) < 9:
return None
# Only handle SymbolicLinkReparseBuffer
(tag, dataLength, reserver, SubstituteNameOffset, SubstituteNameLength,
PrintNameOffset, PrintNameLength,
Flags) = struct.unpack(SymbolicLinkReparseFormat,
buffer[:SymbolicLinkReparseSize])
print tag, dataLength, reserver, SubstituteNameOffset, SubstituteNameLength
start = SubstituteNameOffset + SymbolicLinkReparseSize
actualPath = buffer[start : start + SubstituteNameLength].decode("utf-16")
# This utf-16 string is null terminated
index = actualPath.find(u"\0")
assert index > 0
if index > 0:
actualPath = actualPath[:index]
if actualPath.startswith(u"?\\"):
return actualPath[2:]
else:
return actualPath
但是，大多数时候我尝试过的各种解决方案最终都会给我：
[错误 126] 找不到指定的模块
即使我能够导入 ctypes 并执行诸如导入 cdll 之类的操作：
libc = cdll.msvcrt
libc.printf
<_FuncPtr object at 0x0000000002A9F388>
一般来说，我对 Python 和 ctypes 的这一部分非常陌生，因此非常感谢任何有关在此处处理符号链接的指针！