1

这是我的 http 获取代码，这里 console.log(data) 正在打印整个 php 代码而不是回显语句。请帮助我，我无法弄清楚发生了什么。我正在制作一个离子角度应用程序。

角码

// define angular module/app
var formApp = angular.module('formApp', [])
// create angular controller and pass in $scope and $http
.controller('formController', function ($scope, $http) {
    // create a blank object to hold our form information
    // $scope will allow this to pass between controller and view
    $scope.formData = {};
    // process the form
    $scope.processForm = function() {
        $http({
            method  : 'GET',
            url     : 'process.php',
            data    : $.param($scope.formData),  // pass in data as strings
            headers : { 'Content-Type': 'application/x-www-form-urlencoded' }  // set the headers so angular passing info as form data (not request payload)
        })
            .success(function(data) {
                console.log(data);
                if (!data.success) {
                    // if not successful, bind errors to error variables
                    $scope.errorName = data.errors.name;
                    $scope.errorSuperhero = data.errors.superheroAlias;
                } else {
                    // if successful, bind success message to message
                    $scope.message = data.message;
                }
            });
    };
});

PHP 代码

<?php
$errors         = array();      // array to hold validation errors
$data           = array();      // array to pass back data
// validate the variables ======================================================
if (empty($_POST['name']))
    $errors['name'] = 'Name is required.';
if (empty($_POST['superheroAlias']))
    $errors['superheroAlias'] = 'Superhero alias is required.';
// return a response ===========================================================
// response if there are errors
if ( ! empty($errors)) {
    // if there are items in our errors array, return those errors
    $data['success'] = false;
    $data['errors']  = $errors;
} else {
    // if there are no errors, return a message
    $data['success'] = true;
    $data['message'] = 'Success!';
}
// return all our data to an AJAX call
echo json_encode($data);

控制台输出/Ajax 响应

<?php
$errors         = array();      // array to hold validation errors
$data           = array();      // array to pass back data
// validate the variables ======================================================
if (empty($_POST['name']))
    $errors['name'] = 'Name is required.';
if (empty($_POST['superheroAlias']))
    $errors['superheroAlias'] = 'Superhero alias is required.';
// return a response ===========================================================
// response if there are errors
if ( ! empty($errors)) {
    // if there are items in our errors array, return those errors
    $data['success'] = false;
    $data['errors']  = $errors;
} else {
    // if there are no errors, return a message
    $data['success'] = true;
    $data['message'] = 'Success!';
}
// return all our data to an AJAX call
echo json_encode($data);

如您所见，它发送的是整个 php 代码而不是回显语句。

4

1 回答 1

0

我知道这个线程很旧，但如果您写下如下规则，请尝试检查您的 .htaccess 文件：

默认使用 PHP5.4

AddHandler 应用程序/x-httpd-php54 .php

摆脱它。我犯了这个错误。

于 2015-06-23T23:25:30.433 回答