5

我是初学者，所以如果这是微不足道的，请原谅我的无知。

我有一个未知长度的 javascript 对象，每个属性的值都是一个数组（对我来说也是未知长度）。例如：

var obj = {"varA":[1,2,3],
           "varB":['good','bad'],
           "varC":[0,100],
           "varD":['low','med','high']
          }

我想遍历每个属性并为每个属性值组合创建一个新对象。如果我知道我可以强制使用 for 循环的属性数量，但是有没有办法在不知道要硬编码多少循环的情况下进行枚举？

我基本上想做这种事情：

var oblist = [];
for (a in varA){
 for (b in varB){
  for (c in varC){
   for (d in varD){
    oblist.push({"varA":varA[a], "varB":varB[b], "varC":varC[c], "varD":varD[d]});
   }
  }
 }
}

这样 oblist 将包含以下对象：

{"varA":1, "varB":"good", "varC":0, "varD":"low"}
{"varA":1, "varB":"good", "varC":0, "varD":"med"}
...
{"varA":3, "varB":"bad", "varC":100, "varD":"high"}

谢谢！

编辑：看我不是在寻求 for 循环或索引语法帮助。我在问如果我不知道对象中的属性数量该怎么办（例如 varA、varB、varC、varD、varE，我知道我可以拥有 varZZ），所以我不能只是很难-code 4 for 循环。有没有办法使用 obj[Object.keys(obj)[i]].length 设置它？

4

2 回答 2

1 

var obj = {"varA":[1,2,3],
           "varB":['good','bad'],
           "varC":[0,100],
           "varD":['low','med','high']
          }
 
// flatten the object into an array so it's easier to work with
var obj2list = function(obj) {
  var list = [];
  for (var key in obj) {
    if (obj.hasOwnProperty(key)) {
      list.push({
        name: key,
        val: obj[key]
      });
    }
  }
  return list;
};
 
// implement your favorite version of clone...this isn't particular fast
var cloneObj = function(obj) {
  return JSON.parse(JSON.stringify(obj));
}
 
var iterateAndPopulateCombo = function(currentObj, listToIterate, result) {
  if (listToIterate.length == 0) {
    result.push(currentObj);
  } else {
    listToIterate[0].val.forEach(function(d) {
      var newObj = cloneObj(currentObj);
      newObj[listToIterate[0].name] = d;
      iterateAndPopulateCombo(newObj, listToIterate.slice(1), result);
    })
  }
}
 
var list = obj2list(obj);
var result = [];
iterateAndPopulateCombo({}, list, result);
console.log(JSON.stringify(result));
document.body.appendChild(document.createTextNode(JSON.stringify(result)));

于 2015-01-10T00:18:36.340 回答
1

您需要的组合是cartesian productobj 中所有数组的组合，这是一个显示它的小提琴：

http://jsfiddle.net/sifriday/qmyxhhny/2/

而且代码...

// I think the combo you're after is known as cartesian product
// Here's a function to do it, from:
// http://stackoverflow.com/questions/12303989/cartesian-product-of-multiple-arrays-in-javascript
// It needs Underscore.js
function cartesianProductOf() {
    return _.reduce(arguments, function(a, b) {
        return _.flatten(_.map(a, function(x) {
            return _.map(b, function(y) {
                return x.concat([y]);
            });
        }), true);
    }, [ [] ]);
};

// Here's your object
var obj = {"varA":[1,2,3],
           "varB":['good','bad'],
           "varC":[0,100],
           "varD":['low','med','high']
          }

// Now I extract the arrays from your object
var idx, jdx, keys = Object.keys(obj), arrays = [], result1 = [], result2 = []
for (idx in keys) {
    var key = keys[idx]
    var arr = obj[key]
    arrays.push(arr)
}

// We can calculate the combos of the obj, but this isn't annotated. 
result1 = cartesianProductOf.apply(null, arrays)

// Now turn these back into annotated objects.
for (idx in result1) {
    var tmp = result1[idx], obj = {}
    for (jdx in tmp) {
       obj[keys[jdx]] = tmp[jdx]
    }
    result2.push(obj)
}

// Done!
console.log(result2)

通过一些努力，我认为这可以整理出来；您可能可以确保注释发生在笛卡尔积中。

于 2015-01-10T00:20:57.467 回答