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我正在尝试在我的 iOS 应用程序中实现一种方法，以使用 Feedly API 将文章标记为已读。但是，我不断收到错误响应：

{
    "errorCode": 400,
    "errorId": "sandbox-he.2015010906.2770040",
    "errorMessage": "no data"
}

这是方法：

- (void)markRead:(NSString*)articleID {
    NSLog(@"Artidle ID is: %@", articleID);

    NSUserDefaults *standardUserDefaults = [NSUserDefaults standardUserDefaults];
    NSString *accessToken = [standardUserDefaults objectForKey:@"AccessToken"];

    NSString *feedUrl = [NSURL URLWithString:@"https://sandbox.feedly.com/v3/markers"];

    NSError *error = nil;

    NSString *post =[[NSString alloc] initWithFormat:@"action=markAsRead&type=entries&entryIds=%@",articleID];
    NSLog(@"PostData: %@",post);

    NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
    [request setURL:feedUrl];
    [request setHTTPMethod:@"POST"];
    [request setValue:@"application/json" forHTTPHeaderField:@"Content-type"];
    [request setHTTPBody:postData];
    [request addValue:accessToken forHTTPHeaderField:@"Authorization"];

    //[NSURLRequest setAllowsAnyHTTPSCertificate:YES forHost:[url host]];

    NSError *errror = [[NSError alloc] init];
    NSHTTPURLResponse *response = nil;
    NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&errror];

    NSLog(@"Response code: %ld", (long)[response statusCode]);

    if ([response statusCode] >= 200 && [response statusCode] < 300)
    {
        NSLog(@"Success marking this as read.");

    } else {
        if (error) NSLog(@"Error: %@", errror);
        NSLog(@"No success marking this as read.");
    }

}

Feedly API 描述它需要这个作为输入：

{
   "entryIds": [
       "TSxGHgRh4oAiHxRU9TgPrpYvYVBPjipkmUVSHGYCTY0=_14499073085:c034:d32dab1f",
       "TSxGHgRh4oAiHxRU9TgPrpYvYVBPjipkmUVSHGYCTY0=_1449255d60a:22c3491:9c6d71ab"
   ],
   "action": "markAsRead",
   "type": "entries"
}

在我看来，我将其作为输入提供，所以我实际上期望得到适当的回应。但是，我不断得到400并且似乎无法弄清楚我做错了什么。我已经为此绞尽脑汁好几个小时了。

4

1 回答 1

1

尝试使用以下代码创建数据，而不是使用您当前的身体数据：

NSDictionary *bodyDict = [NSDictionary dictionaryWithObjectsAndKeys:@[articleID],@"entryIds",
                          @"markAsRead",@"action",
                          @"entries",@"type", nil];

NSError *error;
NSData *postdata = [NSJSONSerialization dataWithJSONObject:bodyDict options:0 error:&error];
[request setHTTPBody:postData];

这会将正文作为 JSON 对象发送。

action=markAsRead&type=entries&entryIds=%@当使用 GET 请求方法调用 Web 方法时，通常使用像您所做的那样发送参数（使用）。查看POST 与 GET以获得更好的理解。

于 2015-01-09T15:07:00.480 回答