ios - 使用 Alamofire 在正文中使用简单字符串的 POST 请求

Question

如何在我的 iOS 应用程序中使用 Alamofire 在 HTTP 正文中发送带有简单字符串的 POST 请求？

默认情况下，Alamofire 需要请求参数：

Alamofire.request(.POST, "http://mywebsite.com/post-request", parameters: ["foo": "bar"])

这些参数包含键值对。但我不想在 HTTP 正文中发送带有键值字符串的请求。

我的意思是这样的：

Alamofire.request(.POST, "http://mywebsite.com/post-request", body: "myBodyString")

score 91 · Accepted Answer

您的示例Alamofire.request(.POST, "http://mywebsite.com/post-request", parameters: ["foo": "bar"])已包含“foo=bar”字符串作为其主体。但是如果你真的想要自定义格式的字符串。你可以这样做：

Alamofire.request(.POST, "http://mywebsite.com/post-request", parameters: [:], encoding: .Custom({
            (convertible, params) in
            var mutableRequest = convertible.URLRequest.copy() as NSMutableURLRequest
            mutableRequest.HTTPBody = "myBodyString".dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)
            return (mutableRequest, nil)
        }))

注意：parameters不应该nil

更新（Alamofire 4.0，Swift 3.0）：

在 Alamofire 4.0 API 发生了变化。因此，对于自定义编码，我们需要符合ParameterEncoding协议的值/对象。

extension String: ParameterEncoding {

    public func encode(_ urlRequest: URLRequestConvertible, with parameters: Parameters?) throws -> URLRequest {
        var request = try urlRequest.asURLRequest()
        request.httpBody = data(using: .utf8, allowLossyConversion: false)
        return request
    }

}

Alamofire.request("http://mywebsite.com/post-request", method: .post, parameters: [:], encoding: "myBody", headers: [:])

score 73 · Accepted Answer

你可以这样做：

我创建了一个单独的请求 Alamofire 对象。
将字符串转换为数据

将数据放入 httpBody

var request = URLRequest(url: URL(string: url)!)
request.httpMethod = HTTPMethod.post.rawValue
request.setValue("application/json", forHTTPHeaderField: "Content-Type")

let pjson = attendences.toJSONString(prettyPrint: false)
let data = (pjson?.data(using: .utf8))! as Data

request.httpBody = data

Alamofire.request(request).responseJSON { (response) in


    print(response)

}

score 16 · Accepted Answer

如果你使用 Alamofire，将encodingtype 设置为URLEncoding.httpBody

有了它，您可以在 httpbody 中将数据作为字符串发送，尽管您在代码中将其定义为 json。

它对我有用..

更新了 Badr Filali 的问题：

var url = "http://..."
let _headers : HTTPHeaders = ["Content-Type":"application/x-www-form-urlencoded"]
let params : Parameters = ["grant_type":"password","username":"mail","password":"pass"]

let url =  NSURL(string:"url" as String)

request(url, method: .post, parameters: params, encoding: URLEncoding.httpBody, headers: _headers).responseJSON(
    completionHandler: { response in response
        let jsonResponse = response.result.value as! NSDictionary
        
        if jsonResponse["access_token"] != nil
        {
            access_token = String(describing: jsonResponse["accesstoken"]!)
        }
    })

score 8 · Accepted Answer

我修改了@Silmaril 的答案以扩展 Alamofire 的经理。此解决方案使用 EVReflection 直接序列化对象：

//Extend Alamofire so it can do POSTs with a JSON body from passed object
extension Alamofire.Manager {
    public class func request(
        method: Alamofire.Method,
        _ URLString: URLStringConvertible,
          bodyObject: EVObject)
        -> Request
    {
        return Manager.sharedInstance.request(
            method,
            URLString,
            parameters: [:],
            encoding: .Custom({ (convertible, params) in
                let mutableRequest = convertible.URLRequest.copy() as! NSMutableURLRequest
                mutableRequest.HTTPBody = bodyObject.toJsonString().dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)
                return (mutableRequest, nil)
            })
        )
    }
}

然后你可以像这样使用它：

Alamofire.Manager.request(.POST, endpointUrlString, bodyObject: myObjectToPost)

score 8 · Accepted Answer

基于Illya Krit的回答

细节

Xcode 版本 10.2.1 (10E1001)
斯威夫特 5
阿拉莫菲尔 4.8.2

解决方案

import Alamofire

struct BodyStringEncoding: ParameterEncoding {

    private let body: String

    init(body: String) { self.body = body }

    func encode(_ urlRequest: URLRequestConvertible, with parameters: Parameters?) throws -> URLRequest {
        guard var urlRequest = urlRequest.urlRequest else { throw Errors.emptyURLRequest }
        guard let data = body.data(using: .utf8) else { throw Errors.encodingProblem }
        urlRequest.httpBody = data
        return urlRequest
    }
}

extension BodyStringEncoding {
    enum Errors: Error {
        case emptyURLRequest
        case encodingProblem
    }
}

extension BodyStringEncoding.Errors: LocalizedError {
    var errorDescription: String? {
        switch self {
            case .emptyURLRequest: return "Empty url request"
            case .encodingProblem: return "Encoding problem"
        }
    }
}

用法

Alamofire.request(url, method: .post, parameters: nil, encoding: BodyStringEncoding(body: text), headers: headers).responseJSON { response in
     print(response)
}

score 5 · Accepted Answer

如果您想在请求中将字符串作为原始正文发布

return Alamofire.request(.POST, "http://mywebsite.com/post-request" , parameters: [:], encoding: .Custom({
            (convertible, params) in
            let mutableRequest = convertible.URLRequest.copy() as! NSMutableURLRequest

            let data = ("myBodyString" as NSString).dataUsingEncoding(NSUTF8StringEncoding)
            mutableRequest.HTTPBody = data
            return (mutableRequest, nil)
        }))

score 5 · Accepted Answer

我已经为字符串中的数组完成了它。此解决方案针对正文中的字符串进行了调整。

Alamofire 4 的“原生”方式：

struct JSONStringArrayEncoding: ParameterEncoding {
    private let myString: String

    init(string: String) {
        self.myString = string
    }

    func encode(_ urlRequest: URLRequestConvertible, with parameters: Parameters?) throws -> URLRequest {
        var urlRequest = urlRequest.urlRequest

        let data = myString.data(using: .utf8)!

        if urlRequest?.value(forHTTPHeaderField: "Content-Type") == nil {
            urlRequest?.setValue("application/json", forHTTPHeaderField: "Content-Type")
        }

        urlRequest?.httpBody = data

        return urlRequest!
    }
}

然后通过以下方式提出您的要求：

Alamofire.request("your url string", method: .post, parameters: [:], encoding: JSONStringArrayEncoding.init(string: "My string for body"), headers: [:])

score 4 · Accepted Answer

我使用@afrodev 的答案作为参考。在我的情况下，我将函数的参数作为必须在请求中发布的字符串。所以，这里是代码：

func defineOriginalLanguage(ofText: String) {
    let text =  ofText
    let stringURL = basicURL + "identify?version=2018-05-01"
    let url = URL(string: stringURL)

    var request = URLRequest(url: url!)
    request.httpMethod = HTTPMethod.post.rawValue
    request.setValue("text/plain", forHTTPHeaderField: "Content-Type")
    request.httpBody = text.data(using: .utf8)

    Alamofire.request(request)
        .responseJSON { response in
            print(response)
    }
}

score 2 · Accepted Answer

func paramsFromJSON(json: String) -> [String : AnyObject]?
{
    let objectData: NSData = (json.dataUsingEncoding(NSUTF8StringEncoding))!
    var jsonDict: [ String : AnyObject]!
    do {
        jsonDict = try NSJSONSerialization.JSONObjectWithData(objectData, options: .MutableContainers) as! [ String : AnyObject]
        return jsonDict
    } catch {
        print("JSON serialization failed:  \(error)")
        return nil
    }
}

let json = Mapper().toJSONString(loginJSON, prettyPrint: false)

Alamofire.request(.POST, url + "/login", parameters: paramsFromJSON(json!), encoding: .JSON)

score 2 · Accepted Answer

let parameters = ["foo": "bar"]
              
    // All three of these calls are equivalent
    AF.request("https://httpbin.org/post", method: .post, parameters: parameters)
    AF.request("https://httpbin.org/post", method: .post, parameters: parameters, encoder: URLEncodedFormParameterEncoder.default)
    AF.request("https://httpbin.org/post", method: .post, parameters: parameters, encoder: URLEncodedFormParameterEncoder(destination: .httpBody))

score 2 · Accepted Answer

我的情况，使用内容类型发布alamofire：“Content-Type”：“application/x-www-form-urlencoded”，我不得不更改alampfire发布请求的编码

从：JSONENCODING.DEFAULT 到：URLEncoding.httpBody

这里：

let url = ServicesURls.register_token()
    let body = [
        "UserName": "Minus28",
        "grant_type": "password",
        "Password": "1a29fcd1-2adb-4eaa-9abf-b86607f87085",
         "DeviceNumber": "e9c156d2ab5421e5",
          "AppNotificationKey": "test-test-test",
        "RegistrationEmail": email,
        "RegistrationPassword": password,
        "RegistrationType": 2
        ] as [String : Any]


    Alamofire.request(url, method: .post, parameters: body, encoding: URLEncoding.httpBody , headers: setUpHeaders()).log().responseJSON { (response) in

score -3 · Accepted Answer

Xcode 8.X，斯威夫特 3.X

易于使用；

 let params:NSMutableDictionary? = ["foo": "bar"];
            let ulr =  NSURL(string:"http://mywebsite.com/post-request" as String)
            let request = NSMutableURLRequest(url: ulr! as URL)
            request.httpMethod = "POST"
            request.setValue("application/json", forHTTPHeaderField: "Content-Type")
            let data = try! JSONSerialization.data(withJSONObject: params!, options: JSONSerialization.WritingOptions.prettyPrinted)

            let json = NSString(data: data, encoding: String.Encoding.utf8.rawValue)
            if let json = json {
                print(json)
            }
            request.httpBody = json!.data(using: String.Encoding.utf8.rawValue);


            Alamofire.request(request as! URLRequestConvertible)
                .responseJSON { response in
                    // do whatever you want here
                   print(response.request)  
                   print(response.response) 
                   print(response.data) 
                   print(response.result)

            }

ios - 使用 Alamofire 在正文中使用简单字符串的 POST 请求

12 回答 12

细节

解决方案

用法

Related

Reference