jq - 使用 jq 从跨多个对象的键返回单个最小日期值

Question

我有一组对象如下，我试图从所有对象中获取一个日期值。

所需的输出是：

"2014-12-16T08:59:08.000+0100"

数据集是：

[
  {
    "key": "AB-12345",
    "type": "Fault",
    "typeid": "19",
    "status": "Open",
    "summary": "I'm a big bad fault",
    "closedDate": null,
    "flag": null
  },
  {
    "key": "AB-12346",
    "type": "Bug",
    "typeid": "19",
    "status": "Open",
    "summary": "I'm a big bad bug",
    "closedDate": "2014-12-16T08:59:08.000+0100",
    "flag": null
  },
  {
    "key": "AB-12347",
    "type": "Feature",
    "typeid": "19",
    "status": "Open",
    "summary": "I'm a big bad feature",
    "closedDate": "2014-12-17T08:27:07.000+0100",
    "flag": null
  }
 ]

我已经设法使用：

.[] | {"closedDate": .closedDate} | select(.closedDate > 0)

这会让我：

{
  "closedDate": "2014-12-16T08:59:08.000+0100"
}
{
  "closedDate": "2014-12-17T08:27:07.000+0100"
}

但我想不出一种使用方法或select实现这一点。max_bymin_by

我在jq 1.4

Answer 1

将每个条目映射到closedDate过滤掉的非值，然后得到最小值。

map(.closedDate | values) | min