1

如果有效负载中的值不在架构中,我可以使用滤锅引发错误吗?因此,只允许列入白名单的字段?

这是一个示例:

# coding=utf-8
from colander import MappingSchema, String, Length
from colander import SchemaNode


class SamplePayload(MappingSchema):
    name = SchemaNode(String())
    foo  = SchemaNode(Int())


class Sample(MappingSchema):
    type = SchemaNode(String(), validator=Length(max=32))
    payload = SamplePayload()

# This json should not be accepted (and should yield something like: Unknown field in payload: bar

{  
   "type":"foo",
   "payload":{  
      "name":"a name",
      "foo":123,
      "bar":false
   }
}
4

1 回答 1

3

是的,请参阅的文档colander.Mapping

当反序列化期间 cstruct 中存在未知键时,创建映射colander.Mapping(unknown='raise') 将导致引发异常。colander.Invalid

根据tracker 中的 issue 116 ,将其应用于 Schema 对象的方法是覆盖该schema_type方法:

class StrictMappingSchema(MappingSchema):
    def schema_type(self, **kw):
        return colander.Mapping(unknown='raise')

class SamplePayload(StrictMappingSchema):
    name = SchemaNode(String())
    foo  = SchemaNode(Int())
于 2015-01-07T09:32:39.563 回答