1

天，

我的非营利组织使用的 Google Apps 帐户下有多个 Google 群组。其中一些组非常大，使用 Web UI 管理他们的成员非常糟糕。

我希望有人可以帮助我想出一个脚本，该脚本可以将我在 Google Docs 电子表格上维护的列表与组同步，这样当我从工作表中删除某人时，他们就会从组中删除——当有人被添加到工作表中，他们被添加到组中。

我正在查看Directory API，但我不够精明，无法弄清楚如何为我需要的东西构建脚本。旁注，我确实使用了某人在此处发布的使用类似 API 方法的不同脚本，并且我让该特定脚本工作——换句话说，我的帐户现在已正确设置为 API 访问。

也许以编程方式执行此操作的最简单方法是完全删除组的成员资格，然后在每次脚本运行时再次添加每个成员？

预先感谢您的协助。

4

1 回答 1

2

这里有几个函数可以用来完成你想要的。

首先是删除过程。正如 Sandy 评论的那样，创建一个用于标记要删除的成员的列。只要未删除的为空白，您应该可以在这里使用您喜欢的任何内容。您将需要更改变量“标记”以反映该列编号，您还需要对“电子邮件”变量执行相同操作。那是保存用户电子邮件的列。

首先复制您的工作表，并确保在删除行时它们是正确的！

/**
 *Removes members from group that are marked for removal in a specific column
 */
function removeMarkedMembers() {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getSheetByName('Sheet1');  
  var range = sheet.getDataRange();
  var data = range.getValues();

  //Adjust these following variables to match your sheet
  var groupEmail = 'group@email.com';//change to your group email address
  var marked = 7;//number of column used to mark for removal ex. Column A = 1
  var email = 4; //number of column that holds member email address.

  //must adjust columns numbers to zero based array integers
  marked = marked-1;
  email = email-1;

  var rows = [];

  for (var d in data) {
    var rowData = data[d];
    if(rowData[marked] != "" || rowData != null) {
      removeGroupMember(groupEmail, rowData[email]);
      rows.push(new Number(d)+1)
    }
  }

  for (var r in rows) {
    sheet.deleteRow(rows[r])
  }
}


function removeGroupMember(groupEmail, userEmail) {
  userEmail = userEmail.trim();
  AdminDirectory.Members.remove(groupEmail, userEmail);
}

最后还有一些其他的管理组的功能，根据需要使用它们。最好创建一个菜单，您可以从电子表格中调用这些菜单。

/**
 *Adds all email addresses in column to group.
 */
function addAllToGroup() {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getSheetByName('Sheet1');
  var row = sheet.getLastRow();
  var column = 7;
  var range = sheet.getRange(2, column, sheet.getLastRow(), 1)
  var emails = range.getValues();

  for (var e in emails) {
    var email = emails[e]
    if(validateEmail(email)) {
      addGroupMember(email, 'your@groupemailaddress.com');////Must replace with group email address you want them added too.
    }
  }  
}


function addGroupMember(userEmail, groupEmail) {
  var member = {
    email: userEmail,
    role: 'MEMBER'
  };
  AdminDirectory.Members.insert(member, groupEmail);
}

function validateEmail(email) { 
    var re = /^(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
    return re.test(email);
} 

/**
 *Removes all members from a defined group
 */
function removeAllMembers() {
  var groupEmail = 'group@email.com';
  var members = AdminDirectory.Members.list(groupEmail).members;

  for (var m in members) {
    var member = members[m];
    var email = member.email;
    removeGroupMember(groupEmail, email);
  }
}

这应该可以帮助您获得漂亮的成品。

编辑代码以处理评论中报告的错误。 还更新了标记列必须使用“x”来删除标记。最后，要正确处理行的删除，您需要清除它，然后对整个工作表进行排序，否则您将删除错误的行。记得调整你的参数。

/**
 *Removes members from group that are marked for removal in a specific column
 */
function removeMarkedMembers() {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getSheetByName('Sheet1');  
  var range = sheet.getRange(2, 1, sheet.getLastRow()-1, sheet.getLastColumn());
  var data = range.getValues();

  Logger.log(data)

  //Adjust these following variables to match your sheet
  var groupEmail = 'test-group@email.com';//change to your group email address
  var marked = 2;//number of column used to mark for removal ex. Column A = 1
  var email = 1; //number of column that holds member email address.

  //must adjust columns numbers to zero based array integers.
  marked = marked-1;
  email = email-1;

  Logger.log(marked+' : '+email)

  var rows = [];

  for (var d in data) {
    var rowData = data[d];
    if(validateEmail(rowData[email]) && rowData[marked] == "x") {
      Logger.log('marked')
      removeGroupMember(groupEmail, rowData[email]);
      rows.push(new Number(d)+2)
    }
  }

  for (var r in rows) {
    var row = rows[r];
    sheet.getRange(row, 1, 1, sheet.getLastColumn()).clear();
  }
 range.sort(1);
}


function removeGroupMember(groupEmail, userEmail) {
  Logger.log(userEmail)
  userEmail = userEmail.trim();
  AdminDirectory.Members.remove(groupEmail, userEmail);
}

/**
 *Adds all email addresses in column to group.
 */
function addAllToGroup() {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getSheetByName('Sheet1');
  var row = sheet.getLastRow();
  var column = 1;
  var range = sheet.getRange(2, column, sheet.getLastRow(), 1)
  var emails = range.getValues();

  for (var e in emails) {
    var email = emails[e]
    if(validateEmail(email)) {
      addGroupMember(email, 'test-group@email.com');////Must replace with group email address you want them added too.
    }
  }  
}


function addGroupMember(userEmail, groupEmail) {
  var member = {
    email: userEmail,
    role: 'MEMBER'
  };
  var members = AdminDirectory.Members.list(groupEmail).members
  for (var m in members) {
    if(members[m].email == userEmail) {
      return 'Member already exist';
    }
  }
  AdminDirectory.Members.insert(member, groupEmail);
}

function validateEmail(email) { 
    var re = /^(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
    return re.test(email);
} 

/**
 *Removes all members from a defined group
 */
function removeAllMembers() {
  var groupEmail = 'test-group@email.com';
  var members = AdminDirectory.Members.list(groupEmail).members;

  for (var m in members) {
    var member = members[m];
    var email = member.email;
    removeGroupMember(groupEmail, email);
  }
}
于 2015-01-03T18:07:41.983 回答