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我正在尝试将我的代码编译成原始二进制文件，并按照其他 SO 帖子（如this和this）的建议，我尝试了 objdump：

$ gcc -c foo.c
$ objcopy -O binary foo.o foo.bin

然后我试图确保这是否有效：

$ objdump -d foo.o

foo.o:     file format elf64-x86-64


Disassembly of section .text:

0000000000000000 <main>:
   0:   55                      push   %rbp
   1:   48 89 e5                mov    %rsp,%rbp
   4:   48 83 ec 10             sub    $0x10,%rsp
   8:   89 7d fc                mov    %edi,-0x4(%rbp)
   b:   48 89 75 f0             mov    %rsi,-0x10(%rbp)
   f:   bf 00 00 00 00          mov    $0x0,%edi
  14:   b8 00 00 00 00          mov    $0x0,%eax
  19:   e8 00 00 00 00          callq  1e <main+0x1e>
  1e:   b8 00 00 00 00          mov    $0x0,%eax
  23:   c9                      leaveq 
  24:   c3                      ret

$ hexdump -C foo.bin

00000000  14 00 00 00 00 00 00 00  01 7a 52 00 01 78 10 01  |.........zR..x..|
00000010  1b 0c 07 08 90 01 00 00  1c 00 00 00 1c 00 00 00  |................|
00000020  00 00 00 00 25 00 00 00  00 41 0e 10 86 02 43 0d  |....%....A....C.|
00000030  06 60 0c 07 08 00 00 00                           |.`......|
00000038

显然有些不对劲。我用 gcc 交叉编译的结果对此进行了检查，结果很明显不正确。

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1 回答 1

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你可以-j .text传给objcopy.

于 2017-01-18T08:31:41.113 回答