我正在尝试学习 python-watchdog,但我有点困惑为什么我设置的作业不止一次运行。所以,这是我的设置:
#handler.py
import os
from watchdog.events import FileSystemEventHandler
from actions import run_something
def getext(filename):
return os.path.splitext(filename)[-1].lower()
class ChangeHandler(FileSystemEventHandler):
def on_any_event(self, event):
if event.is_directory:
return
if getext(event.src_path) == '.done':
run_something()
else:
print "event not directory.. exiting..."
pass
观察者的设置如下:
#observer.py
import os
import time
from watchdog.observers import Observer
from handler import ChangeHandler
BASEDIR = "/path/to/some/directory/bin"
def main():
while 1:
event_handler = ChangeHandler()
observer = Observer()
observer.schedule(event_handler, BASEDIR, recursive=True)
observer.start()
try:
while True:
time.sleep(1)
except KeyboardInterrupt:
observer.stop()
observer.join()
if __name__ == '__main__':
main()
最后,像这样的动作:
#actions.py
import os
import subprocess
def run_something():
output = subprocess.check_output(['./run.sh'])
print output
return None
..where./run.sh
只是我想在.done
找到带有扩展名的文件时运行的 shell 脚本/path/to/some/directory/bin
#run.sh
#!/bin/bash
echo "Job Start: $(date)"
rm -rf /path/to/some/directory/bin/job.done # remove the .done file
echo "Job Done: $(date)"
但是,当我发出 apython observer.py
然后执行 a touch job.done
on 时/path/to/some/directory/bin
,我看到我的 shell 脚本./run.sh
运行了 3 次而不是 1 次。
我很困惑为什么这会运行三次而不是一次(我确实删除了job.done
我的 bash 脚本中的文件)