-2

我希望用户能够创建数量不定的问题。一旦用户创建了一个问题,我希望出现另一个问题(问题 2),依此类推..

我该怎么办?

谢谢

4

4 回答 4

0

这或多或少是我使用纯 JavaScript 会做的事情(请参阅评论以获取解释)

// Create a copy of a blank Question node
question_template = document.getElementById("questions").firstElementChild.cloneNode(true);
// A nice cloning wrapper
new_question = function(){return question_template.cloneNode(true);};
// Something to do when the user is finished putting in questions
alrt = function(){
    alert(Array.prototype.map.call(document.getElementById(
      "questions").getElementsByTagName("input"),
      function(elt){return elt.value;}));
};
// Hook for when text is placed in textbox
addnew = function(){
    // Remove the event listener (If you don't do this, then on every
    //   keystroke a new box will be created
    document.getElementById("questions").lastElementChild.oninput = function(event){};
    // Add a new line
    document.getElementById("questions").appendChild(document.createElement("br"));
    // Add a new question box
    document.getElementById("questions").appendChild(new_question());
};
<div id="questions">
<input type="text" oninput="addnew()"/>
</div>
<input type="button" value="Done" onclick="alrt()"/>

更新:我刚刚在主帖的评论部分看到了你的阐述。你可以用这样的东西来实现它:

// Create a copy of a blank Question node
question_template = document.getElementById("questions").firstElementChild.cloneNode(true);
// A nice cloning wrapper
new_question = function(){return question_template.cloneNode(true);};
// Something to do when the user is finished putting in questions
alrt = function(){
    alert(Array.prototype.map.call(document.getElementById(
      "questions").getElementsByTagName("input"),
      function(elt){return elt.value;}));
};
// Hook for when text is placed in textbox
addnew = function(){
    // Add a new line
    document.getElementById("questions").appendChild(document.createElement("br"));
    // Add a new question box
    document.getElementById("questions").appendChild(new_question());
};
<div id="questions">
    <input type="text"/>
    </div>
<input type="button" value="Add Another" onclick="addnew()"/>
    <input type="button" value="Done" onclick="alrt()"/>

这可以通过大多数input具有正确事件的元素来实现。W3 Schools 有一个很好的参考资料,如果你需要的话。

于 2014-12-24T18:44:11.157 回答
0

我会做类似的事情:

function addClone() {
    var cloned = document.getElementById('test').cloneNode(true); //clone the element
    document.body.appendChild(cloned); //add the cloned element to the page
}
<div id='test'>iadwjoam</div>
<input type="checkbox" id="xxx" name="xxx" onchange="addClone()" />

cloneNode()- https://developer.mozilla.org/en-US/docs/Web/API/Node.cloneNode

于 2014-12-24T17:55:54.620 回答
0

你可以试试这样的

HTML

<div class="input-container">
  <input class="question" placeholder="Question" type="text"/>
</div>

<div class="add-option">+</div>

JS

//click the '+' sign
$(".add-option").click(function(){

   //find the first input and clone it then append it to the container
   $(".input-container input:first").clone().appendTo(".input-container");

   //clear any value from the next input had there been any added
   $(".input-container input:last").val("");
});

小提琴

更新

我省略了有关复选框的部分,从 UI 的角度来看,我认为您不需要复选框来完成此操作,不确定它是否暗示“已完成,我想继​​续”,但这由您决定。这是一个新的小提琴

HTML

<div class="input-container">
  <input class="question" placeholder="Question" type="text"/>
</div>

<div class="add-option"><input type="checkbox"/></div>

JS

//click the checkbox
$(".add-option input[type=checkbox]").click(function(){

 //find the first input and clone it then append it to the container
 $(".input-container input:first").clone().appendTo(".input-container");

 //clear any value from the next input had there been any added
 $(".input-container input:last").val("");

 //reset the checkbox
 $(this).prop("checked", false);
});

新小提琴

于 2014-12-24T17:58:39.883 回答
0

在javascript中你可以这样做

var i = 0;

function addMore() {
  i++;
  var parentDiv = document.createElement("div");

  var childLabel = document.createElement("label");
  childLabel.appendChild(document.createTextNode("Enter Value " + i));

  var childTextBox = document.createElement("input");
  childTextBox.type = "text";
  childTextBox.id = "txtInput" + i;

  var childCheckBox = document.createElement("input");
  childCheckBox.type = "checkbox";
  childCheckBox.onchange = addMore;

  parentDiv.appendChild(childLabel);
  parentDiv.appendChild(childTextBox);
  parentDiv.appendChild(childCheckBox);
  document.body.appendChild(parentDiv);

}
<div>
  Add Items
  <input type="checkbox" onchange="addMore()">
</div>

希望这有帮助

于 2014-12-24T18:38:58.437 回答