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我将 8x8 输入提供给基于 MKL 的离散余弦变换 (DCT) 代码：

“fileinput.txt” 输入：

255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255

以下代码的 DCT 输出为：

32385      -727.349243  -619.955444 -458.675903 -267.323547 -74.151535  92.318069   207.505844
764.404419  717.50531   602.316772  435.846893  242.6754    51.322887   -109.956779 -217.350159
-762.619629 -706.582764 -583.869446 -412.598663 -218.058334 -28.972321  126.74057   226.088898
759.648132  694.603516  564.651367  388.979492  193.525208  7.147152    -142.635284 -233.70639
-755.498901 -681.59967  -544.712891 -365.049927 -169.138    14.096443   157.598663  240.180206
750.180115  667.597656  524.094971  340.860809  144.948898  -34.714363  -171.600922 -245.499771
-743.705566 -652.633789 -502.85144  -316.473694 -121.019257 54.652824   184.604614  249.648224
736.088623  636.739502  481.026154  291.940552  97.400169   -73.870857  -196.583725 -252.620102

预期输出：

16320      8.331551    -8.493903    8.775995    -9.19324    9.772106    -10.552611  11.595706
8.332954    0.004307    -0.004317   0.004504    -0.00472    0.004989    -0.005391   0.00592
-8.494178   -0.004317   0.004454    -0.004576   0.004765    -0.005109   0.005472    -0.006031
8.776941    0.004504    -0.004545   0.004746    -0.004965   0.005248    -0.005666   0.006251
-9.193484   -0.004659   0.004811    -0.00495    0.005198    -0.005507   0.005955    -0.006519
9.771847    0.005035    -0.005079   0.005241    -0.005522   0.005852    -0.006314   0.00696
-10.552428  -0.005383   0.005533    -0.005627   0.00591    -0.006314    0.006844    -0.007483
11.59587    0.005882    -0.00605    0.006274    -0.006557   0.006974    -0.007506   0.008264

代码：

#include <time.h>
#include <stdlib.h>
#include "mkl.h"
#include "iostream"
using namespace std;

int main(int argc, char* argv[]){
    float *dpar;
    float *out;
    MKL_INT *ipar;
    MKL_INT tt_type,stat,n_1,nn;
    FILE *fp;

    fp = fopen( "D:\\fileinput.txt","r" );


    if(fp == NULL){
        cout<<"file not created properly"<<endl;
    }
    printf("\n===== DCT CODE ======== \n");
    DFTI_DESCRIPTOR_HANDLE handle = 0;
    int n = 64;//8x8 matrix;
    nn = (MKL_INT)n;
    tt_type = MKL_COSINE_TRANSFORM;

    n_1 = nn + 1 ;
    out = (float*)malloc((n+1)*sizeof(float));
    dpar= (float*)malloc((5*n_1/2+2)*sizeof(float));
    ipar= (MKL_INT*)malloc((128)*sizeof(int));
    s_init_trig_transform(&n_1,&tt_type,ipar,dpar,&stat);
    for (int srcSize =0 ;srcSize< n ; srcSize++)
    {
        fscanf(fp,"%f\n",&out[srcSize]);
    }
    fclose(fp);
    if (stat != 0)
    {
        printf("\n============================================================================\n");
        printf("FFTW2MKL FATAL ERROR: MKL TT initialization has failed with status=%d\n",(MKL_INT)stat);
        printf("Please refer to the Trigonometric Transform Routines Section of MKL Manual\n");
        printf("to find what went wrong...\n");
        printf("============================================================================\n");
        return NULL;
    }
    ipar[10] = 1;    //nx, that is, the number of intervals along the x-axis, in the Cartesian case.
    ipar[11] = 1;    //ny, that is, the number of intervals along the x-axis, in the Cartesian case.
    ipar[14] = n_1;  //specifies the internal partitioning of the dpar array.
    ipar[15] = 1;    //value of ipar[14]+1,Specifies the internal partitioning of the dpar array.
    s_commit_trig_transform(out,&handle,ipar,dpar,&stat);
    if (stat != 0)
    {
        printf("\n============================================================================\n");
        printf("FFTW2MKL FATAL ERROR: MKL TT commit step has failed with status=%d\n",(MKL_INT)stat);
        printf("Please refer to the Trigonometric Transform Routines Section of MKL Manual\n");
        printf("to find what went wrong...\n");
        printf("============================================================================\n");
        return NULL;
    }
    s_forward_trig_transform(out,&handle,ipar,dpar,&stat);
    if (stat != 0)
    {
        printf("\n============================================================================\n");
        printf("FFTW2MKL FATAL ERROR: MKL TT commit step has failed with status=%d\n",(MKL_INT)stat);
        printf("Please refer to the Trigonometric Transform Routines Section of MKL Manual\n");
        printf("to find what went wrong...\n");
        printf("============================================================================\n");
        return NULL;
    }

    free_trig_transform(&handle,ipar,&stat);
    printf("\n===== DCT GOT OVER ======== \n");


    return 0;

}

你能指导我找出我在代码中做的错误吗

4

1 回答 1

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更多的是一个问题而不是一个答案。这4行正确吗？

ipar[10] = 1;    //nx, that is, the number of intervals along the x-axis,
ipar[11] = 1;    //ny, that is, the number of intervals along the x-axis,
ipar[14] = n_1;  //specifies the internal partitioning of the dpar array.
ipar[15] = 1;    //value of ipar[14]+1,Specifies the ... of the dpar array.

在前两种情况下，间隔数真的是 1 吗？

在第四种情况下，注释说那ipar[15]是 的值ipar[14]+1 = n_1 + 1 = nn + 2 = n + 2 = 66，尽管我们不知道 in 发生了n_1什么s_init_trig_transform()。

于 2014-12-24T18:45:36.713 回答