4

下面是我一直在做的一个纸牌游戏。我遇到了似乎无法通过的基本封锁。

在这部分代码中，我无法找到一种方法将来自我的数组的数字转换为它们对应的面孔和西装。

Console.WriteLine("A " + deck[Game.DrawCard(deck), 0] + " of " + deck[Game.DrawCard(deck), 1] + " was drawn from the deck and then placed on top");

我可以模糊地想象一条使用一长串变量和 if 语句的路线，但我真的怀疑没有明显且更简单的方法。

其余代码如下所示

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace CribbageInCSharp
{
    class Program
    {
        static void Main(string[] args)
        {
            //Variables//
            int currentPlayer;
            short score1 = 0;
            short score2 = 0;
            short round = 1;
            int[,] deck = new int[52, 2];

            Console.WriteLine("Welcome" + "\r" + "\r" + "Enter Number of Players (Only 2 player mode works right now)");
            while ((Console.ReadLine() != "2"))
            {
                Console.WriteLine("Only two player is working right now \n Make sure you are entering a number between 1-3 \n");
            }
            //A flip is made to determine who goes first//
            currentPlayer = Game.CoinFlip();
            Console.WriteLine("A coin was flipped and it was determined that player " + currentPlayer + " will go first \n");
            //Game.PrintDeck(deck);
            //Now the game is started//
            do
            {
                Console.WriteLine("Shuffling and dealing cards...");
                System.Threading.Thread.Sleep(5000);
                Game.InitDeck(deck);
                Console.WriteLine("Round " + round + "\n");
                //Cutting the Deck now that discarding has been done//
                Console.WriteLine("Cutting the deck... \n");
                System.Threading.Thread.Sleep(2000);
                Console.WriteLine("A " + deck[Game.DrawCard(deck), 0] + " of " + deck[Game.DrawCard(deck), 1] + " was drawn from the deck and then placed on top");    //Insert a swtich statement to convert pairs of numbers into actual cards
                //Player 2's turn is started now that the cut is over//
                Console.WriteLine("");

                //pick up here

                Console.WriteLine("Player " + currentPlayer + " ");


                round++;
            } while ((score1 < 121) && (score2 < 121));  //Loops until either score exceeds 121 points//
        }
    }

    class Game  //Used for functions neccesary to the function of the game that are not neccesarily dependant on turn order and do not create win conditions.
    {
        public static int CoinFlip()    //Flips to see who goes first, results are between 1-2
        {
            var rnd = new Random(DateTime.Now.Millisecond);
            int firstPlayer = rnd.Next(1, 3);
            return (firstPlayer);
        }
        public static void InitDeck(int[,] deck) // First column 11==Jack, 12==queen, 13==king && Second Column 0==diamonds, 1==clubs, 2==spades, 3==hearts
        {
            //Initiallizing the first column==Faces
            for (int i = 0; i < 4; i++)
            {
                deck[i, 0] = 13;
                deck[(i + 4), 0] = 12;
                deck[(i + 8), 0] = 11;
                deck[(i + 12), 0] = 10;
                deck[(i + 16), 0] = 9;
                deck[(i + 20), 0] = 8;
                deck[(i + 24), 0] = 7;
                deck[(i + 28), 0] = 6;
                deck[(i + 32), 0] = 5;
                deck[(i + 36), 0] = 4;
                deck[(i + 40), 0] = 3;
                deck[(i + 44), 0] = 2;
                deck[(i + 48), 0] = 1;
            }
            //Initiallizing second column==Suit
            for (int i = 0; i < 4; i++)
            {
                deck[i, 1] = i;
                deck[(i + 4), 1] = i;
                deck[(i + 8), 1] = i;
                deck[(i + 12), 1] = i;
                deck[(i + 16), 1] = i;
                deck[(i + 20), 1] = i;
                deck[(i + 24), 1] = i;
                deck[(i + 28), 1] = i;
                deck[(i + 32), 1] = i;
                deck[(i + 36), 1] = i;
                deck[(i + 40), 1] = i;
                deck[(i + 44), 1] = i;
                deck[(i + 48), 1] = i;
            }
        }
        public static void PrintDeck(int[,] deck)
        {
            for (int i = 0; i < 52; i++)
            {
                Console.WriteLine(deck[i, 0] + "F");
                Console.WriteLine(deck[i, 1] + "S");
            }
            Console.ReadLine();
        }
        public static int DrawCard(int[,] deck) //Draws a card from the deck, ignoring Cards already drawn this turn. IF THERE ARE ANY ERRORS COME HERE AND CHECK THIS FIRST
        {
            var rnd = new Random(DateTime.Now.Millisecond);
            int o = rnd.Next(0, 51);
            while (deck[o,0]==0)
            {
                System.Threading.Thread.Sleep(1000);
                rnd = new Random(DateTime.Now.Millisecond);
                o = rnd.Next(0, 51);
            }
            int drawnCard = o;
            deck[o, 0] = 0;

            return (drawnCard);
        }

    }
}

我也有一种感觉，纸牌阵列可能不是最明智的决定，而不是列表，但我并不积极。

我真的很抱歉。虽然对其他人来说似乎很明显我的主题已经被涵盖，但我对 C# 的有限理解不允许我解释我在过去一个小时左右出现的任何帖子中的任何答案。我正在尝试通过控制台窗口编写一个简单的游戏来学习 C#，因为这就是我学习 C++ 的方式。

提前感谢任何人的帮助。我真的很感激！

4

3 回答 3

7

首先，我会将洗好的牌存储在 aList中，甚至更好的 aQueue中。这使您可以从牌组中“挑选”一张牌。

为了获得卡片和套件，我将创建两个枚举：

public enum Rank
{
   Ace,
   Two,
   Three,
   ...
}

public enum Suits
{
   Hearts,
   Spades,
   ...
}

现在你定义你的牌，这样 0 = aH，1 = 2H，13 = aS，等等。

现在你可以这样做：

public Rank GetRankForCard(int card)
{
     return (Rank)(card % 13);
}

public Suit GetSuitForCard(int card)
{
    return (Suit)(card / 13);
}

%（模数）运算符在这里非常有用。最后一点，cribbage不是一个简单的游戏来实现（我自己在 WPF 中做过），祝你好运！

于 2014-12-19T19:15:56.687 回答
2

我在评论中得到了什么：

Dictionary<int, string> Cards = new Dictionary<int, string>
{
     {1, "Ace" },
     {2, "Two"}
     //etc
};

Dictionary<int, string> Suits = new Dictionary<int, string>
{
     {1, "Hearts"},
     {2, "Clubs"}
     //etc
};

并像这样使用它：

Console.WriteLine("A {0} of {1} was drawn from the deck and then placed on top",                
                     Cards[deck[Game.DrawCard(deck), 0]], 
                     Suits[deck[Game.DrawCard(deck), 0]]);

当您需要组合字符串时，最好使用格式化的字符串，而不是字符串连接。性能和可读性都更好。

于 2014-12-19T19:20:07.723 回答
0

您可以使用 switch 语句，例如：

string suit = String.Empty;

switch(SuitIndex)
{
   case 1:
   suit = "Diamonds";
   break;

   case 2:
   suit = "Clubs";
   break;

   case 3:
   suit = "Hearts";
   break;

   case 4:
   suit = "Spades";
   break;
}
于 2014-12-19T19:22:11.933 回答