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我有示例应用程序来学习绑定服务。它在启动时设置通知。如果我通过单击通知启动应用程序 N 次，那么我也需要单击“返回”按钮 N 次以关闭应用程序并停止服务，这当然是用户预期的错误行为。单击“返回”应停止应用程序。来自http://developer.android.com/guide/components/bound-services.html的 Android 开发人员指南：“多个客户端可以同时连接到服务。但是，系统仅在第一个客户端绑定时调用服务的 onBind() 方法来检索 IBinder。然后系统将相同的 IBinder 传递给绑定的任何其他客户端，而无需调用onBind() 再次。当最后一个客户端与服务解除绑定时，系统会销毁该服务（除非该服务也由 startService() 启动）。所以，我假设每次点击通知都会绑定另一个客户端，然后需要依次解除绑定。我怎样才能摆脱这种不受欢迎的行为？

相关代码：

public class MainActivity extends Activity {
private LocalService mBoundService;
boolean mIsBound = false;

...........

@Override
protected void onStart() {
    super.onStart();
    if (!mIsBound)
        doBindService();
};

.............
@Override
public boolean onOptionsItemSelected(MenuItem item) {
    int id = item.getItemId();
    if (id == R.id.action_settings) {
        if (mIsBound) {
            int num = mBoundService.getRandomNumber();
            Toast.makeText(this, "number: " + num, Toast.LENGTH_SHORT).show();
        }
    }
    return super.onOptionsItemSelected(item);
}

private ServiceConnection mConnection = new ServiceConnection() {
    public void onServiceConnected(ComponentName className, IBinder service) {
     mBoundService = ((LocalService.LocalBinder) service).getService();
        // Tell the user about this for our demo.
        Toast.makeText(MainActivity.this, R.string.local_service_connected,
                Toast.LENGTH_SHORT).show();
    }

........... 
void doBindService() {
    // Establish a connection with the service.  We use an explicit
    // class name because we want a specific service implementation that
    // we know will be running in our own process (and thus won't be
    // supporting component replacement by other applications).
    bindService(new Intent(MainActivity.this, 
            LocalService.class), mConnection, Context.BIND_AUTO_CREATE);
    mIsBound = true;
}

    }
}
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