1

我有一组数据，其中包含有关客户的信息以及他们花了多少钱，每个客户只出现一次：

customer<-c("Andy","Bobby","Oscar","Oliver","Jane","Cathy","Emma","Chris")
age<-c(25,34,20,35,23,35,34,22)
gender<-c("male","male","male","male","female","female","female","female")
moneyspent<-c(100,100,200,200,400,400,500,200)

data<-data.frame(customer=customer,age=age,gender=gender,moneyspent=moneyspent)

如果我想计算男性和女性客户平均花费的金额，我可以使用tapply：

tapply(moneyspent,gender,mean)

这使：

female   male 
  375    150

但是，我现在想找出性别和年龄组的平均花费，我的目标是：

 Male Age 20-30      Female Age 20-30      Male Age 30-40      Female Age 30-40
    150                     300                 150                   450

我怎样才能修改 tapply 代码以便它给出这些结果？

谢谢你

4

2 回答 2

2

您可能需要使用cut

mat <- tapply(moneyspent, list(gender, age=cut(age, breaks=c(20,30,40), 
                include.lowest=TRUE)), mean)

nm1 <- outer(rownames(mat), colnames(mat), FUN=paste)
setNames(c(mat), nm1)
#female [20,30]   male [20,30] female (30,40]   male (30,40] 
#       300            150            450            150

其他选项包括

library(dplyr)
data %>% 
     group_by(gender, age=cut(age, breaks=c(20,30,40), 
              include.lowest=TRUE)) %>% 
     summarise(moneyspent=mean(moneyspent))

或者

 library(data.table)
 setDT(data)[, list(moneyspent=mean(moneyspent)),
     by=list(gender, age=cut(age, breaks= c(20,30,40), include.lowest=TRUE))]
于 2014-12-10T18:03:33.210 回答
0

使用 plyr 包

library(plyr)

ddply(data,.(gender, age=cut(age, breaks=c(20,30,40), 
                  include.lowest=TRUE)), summarize, moneyspent=mean(moneyspent))

也会给出同样的结果。

注意： Summari z e 和 Summari s e 执行相同的功能。

警告：加载plyr掩盖了dplyr！detach plyr在再次使用类似功能之前，您需Summarize要这样做。

于 2019-02-18T19:18:54.560 回答