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我想在字符串中获取客户端的到达日期并将其作为参数传递给 strToCal 方法，此方法返回具有该日期的日历对象，但它不起作用，id 得到解析异常错误：

static String pattern = "yyyy-MM-dd HH:mm:ss";
System.out.println("enter arrival date ("+ pattern +"):\n" );
c.setArrDate(strToCal(sc.next(),c));
System.out.println("enter departure date ("+ pattern +"):\n");
c.setResTilDate(strToCal(sc.next(),c));

static Calendar strToCal(String s, Client c) throws ParseException {
    try{
        DateFormat df = new SimpleDateFormat(pattern);
        Calendar cal  = Calendar.getInstance();
        cal.setTime(df.parse(s));
        return cal;
    } catch(ParseException e){
        System.out.println("somethings wrong");
        return null;
    }
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1 回答 1

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替换sc.next()为sc.nextLine();

因为sc.next()将在第一个空格处拆分，并且您的输入字符串的模式不正确。

编辑我试过这段代码：

public class Test4 {
    static String pattern = "yyyy-MM-dd HH:mm:ss";

    public static void main(String[] args) {
        Calendar c = Calendar.getInstance();
        final Scanner input = new Scanner(System.in);
        System.out.println("input date: ");
        String a = input.nextLine();
        c = strToCal(a);
        System.out.println(c.getTime());
    }


    static Calendar strToCal(String s) {
        try {
            DateFormat df = new SimpleDateFormat(pattern);
            Calendar cal = Calendar.getInstance();
            cal.setTime(df.parse(s));
            return cal;
        } catch (ParseException e) {
            e.printStackTrace();
            return null;
        }
    }
}

与next()：

input date:
2014-05-16 13:30:00
java.text.ParseException: Unparseable date: "2014-05-16"
        at java.text.DateFormat.parse(Unknown Source)

与nextLine()：

input date:
2014-05-16 13:30:00
Fri May 16 13:30:00 EEST 2014
于 2014-12-08T09:33:35.827 回答