我在 C# 中遇到了 monotorrent 的问题。它丢弃对等点,因为握手中对等点的 ID 不等于给定的跟踪器。
有问题的代码块如下所示:
if (id.Peer.PeerId != message.PeerId)
{
Logger.Log(id.Connection, "HandShake.Handle - Invalid peerid");
//Here is my debug:
string hex = BitConverter.ToString(Encoding.Default.GetBytes(id.Peer.PeerId));
Console.WriteLine("1: {0}", hex);
string hex1 = BitConverter.ToString(Encoding.Default.GetBytes(message.PeerId));
Console.WriteLine("2: {0}", hex1);
if (hex == hex1)
{
Console.WriteLine("hex eq");
}
if (id.Peer.PeerId.Equals(message.PeerId))
{
Console.WriteLine("string eq");
}
throw new TorrentException("Supplied PeerID didn't match the one the tracker gave us");
}
它返回如下内容:
1: 2D-42-54-37-39-32-30-2D-78-3F-3F-3F-12-4C-24-3F-71-3F-3E-68
2: 2D-42-54-37-39-32-30-2D-78-3F-3F-3F-12-4C-24-3F-71-3F-3E-68
hex eq
1: 2D-42-54-37-39-32-30-2D-78-3F-3F-3F-12-4C-24-3F-71-3F-3E-68
2: 2D-42-54-37-39-32-30-2D-78-3F-3F-3F-12-4C-24-3F-71-3F-3E-68
hex eq
为什么十六进制完全相同的字符串不被视为相等?
更新:跟踪器返回响应以通知在 CP1251 中编码的请求(获取对等点)。这会导致问题吗?
Update2: 我认为原因是 som 编码标志。我添加了这个:
var str = System.Text.Encoding.Default.GetString(Encoding.Default.GetBytes(id.Peer.PeerId));
var str1 = System.Text.Encoding.Default.GetString(Encoding.Default.GetBytes(message.PeerId));
if (id.Peer.PeerId.Equals(message.PeerId))
{
Console.WriteLine("string eq");
}
if (str.Equals(str1))
{
Console.WriteLine("str eq str1");
}
得到了这个:
1: 2D-55-54-33-34-32-30-2D-7E-7D-01-4B-3F-79-3F-3F-3F-1A-73-3F
2: 2D-55-54-33-34-32-30-2D-7E-7D-01-4B-3F-79-3F-3F-3F-1A-73-3F
hex eq
str eq str1
1: 2D-55-54-33-33-32-30-2D-5F-76-11-3F-3F-6E-3F-0A-3F-54-62-3F
2: 2D-55-54-33-33-32-30-2D-5F-76-11-3F-3F-6E-3F-0A-3F-54-62-3F
hex eq
str eq str1
很有意思!