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我正在使用 Coinbase API，请访问此处以了解有关此 API 的更多信息。

所以，我正在运行这个程序，你可以看一下，但它说：

{"success":false,"errors":["Required parameter missing: account"]}

这是我的程序：

import java.io.IOException;
import java.security.InvalidKeyException;
import java.security.NoSuchAlgorithmException;

import javax.crypto.Mac;
import javax.crypto.spec.SecretKeySpec;

import org.apache.commons.codec.binary.Hex;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.client.methods.HttpRequestBase;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.HttpClientBuilder;
import org.apache.http.util.EntityUtils;

import com.coinbase.api.Coinbase;
import com.coinbase.api.CoinbaseBuilder;

public class TransactionExample {

    static String API_KEY = "MY API KEY";

    static String API_SECRET = "MY API SECRET";

    public static String getHttp(String url, String body)
            throws InvalidKeyException, NoSuchAlgorithmException,
            ClientProtocolException, IOException {

        String nonce = String.valueOf(System.currentTimeMillis());
        String message = nonce + url + (body != null ? body : "");

        Mac mac = Mac.getInstance("HmacSHA256");
        mac.init(new SecretKeySpec(API_SECRET.getBytes(), "HmacSHA256"));
        String signature = new String(Hex.encodeHex(mac.doFinal(message.getBytes())));

        HttpRequestBase request;
        if (body == null || body.length() == 0)
            request = new HttpGet(url);
        else {
            HttpPost post = new HttpPost(url);
            post.setEntity(new StringEntity(body));
            request = post;
        }
        request.setHeader("ACCESS_KEY", API_KEY);
        request.setHeader("ACCESS_SIGNATURE", signature);
        request.setHeader("ACCESS_NONCE", nonce);

        HttpClient httpClient = HttpClientBuilder.create().build();
        HttpResponse response = httpClient.execute(request);

        HttpEntity entity = response.getEntity();
        if (entity != null)
            return EntityUtils.toString(entity);
        return null;
    }
    
    public static void main(String[] args) throws InvalidKeyException, NoSuchAlgorithmException, ClientProtocolException, IOException{
        
        System.out.println(getHttp("https://api.coinbase.com/v1/accounts", "{'account':{'name':'Savings Wallet'}}")); 
    }
}

请帮忙！

当然，我们将不胜感激！

4

1 回答 1

-1

您需要在此处将占位符文本替换为您的实际 API 密钥：

 static String API_KEY = "MY API KEY";

 static String API_SECRET = "MY API SECRET";

你可以在https://www.coinbase.com/settings/api获得它们。

不过，如果您刚刚开始，我建议您先使用Sandbox API 进行测试以避免任何安全风险。如果您的 API 密钥有权从您的帐户购买/出售或汇款，任何拥有它们的人都可以这样做。

使用 Sandbox API 时，您需要将 URL 从 更改https://api.coinbase.com/v1/accounts为https://api.sandbox.coinbase.com/v1/accounts.

此外，我们还发布了我们的 API 的 v2，它更加出色，但需要对这个脚本进行一些其他修改。

于 2015-08-20T13:16:08.730 回答