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我一直在学习 python 掌握了基础知识

为了变得更好，我一直在尝试创建一个程序来打开存档文件，而不是创建只是打开。

我可以轻松地创建和打开 7z 文件，但是当使用 7zip 创建存档时它不会打开它，任何人都知道为什么以及如何打开由 7zip 创建的文件

  data = b"Insert Data Here"
  with lzma.open("file.7z", "w") as f:
    f.write(data)


  with lzma.LZMAFile("file.7z") as f:
        fc =f.read()
        print(fc)

追溯

Traceback (most recent call last):
  File "<string>", line 420, in run_nodebug
  File "C:\Users\<name>\Documents\Py\decompression.py", line 20, in <module>
    main()
  File "C:\Users\<name>\Documents\Py\decompression.py", line 15, in main
    fc =f.read()
  File "C:\Python33\lib\lzma.py", line 291, in read
    return self._read_all()
  File "C:\Python33\lib\lzma.py", line 244, in _read_all
    while self._fill_buffer():
  File "C:\Python33\lib\lzma.py", line 238, in _fill_buffer
    self._buffer = self._decompressor.decompress(rawblock)
_lzma.LZMAError: Input format not supported by decoder
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