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我是 Prolog 的新手。我试图找出一个问题,我需要检查边缘之间是否存在路径。我完成了循环的非循环图形代码,我的代码将进入无限循环。

path(Start, End) :- edge(Start, End).
path(Start, End) :- edge(Start, Z), path(Z, End).

我需要通过定义一个新的谓词来处理这种情况: new_path(Start,End,path) 应该消除无限循环。请让我知道如何进行。

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2 回答 2

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尝试

path(Start, End) :-
   closure(edge, Start, End).

使用这个定义closure/3

于 2014-11-27T23:44:40.767 回答
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您需要使用 prolog 列表作为 LIFO 堆栈,随时跟踪您访问过的节点。这些方面的东西:

path( A , Z , P ) :-           % to find a path from A to Z
  traverse( A , Z , [] , P ) , % take a walk, visiting A to see if we can get to Z, seeding the visited list with the empty string.
  reverse(P,Path)              % once we find a path, let's reverse it, since it's in LIFO order.
  .                            % That's all there is to it, really.

traverse( Z , Z , V , [Z|V] )     % if current node is the destination node, we've arrived.
  .                               % - just push the destination vertice onto the visited list and unify that with the path
traverse( A , Z , V , P ) :-      % Otherwise...
  edge( A , Z ) ,                 % - if the current node is directly connected to the destination node,
  traverse( Z , Z , [A|V] , P)    % - go visit the destination, marking the current node as visited
  .                               %
traverse( A, Z , V , P ) :-       % Otherwise...
  A \= Z,
  edge( A , B ) ,                 % - if the current node is connected to a node
  B \= Z ,                        % - that is not the destination node, and
  unvisited([A|V],B) ,            % - we have not yet visited that node,
  traverse( B , Z , [A|V] , P )   % - go visit the intermediate node, marking the current node as visited.
  .                               % Easy!

unvisited( []    , _ ) .                   % We succeed if the visited list is empty.
unvisited( [A|_] , A ) :- ! , fail .       % We fail deterministically if we find the node in the visited list.
unvisited( [_|L] , A ) :- unvisited(L,A) . % otherwise, we keep looking.
于 2014-11-28T18:52:02.487 回答