我目前正在开发一个简单的 SpringMVC 应用程序。我最近开始使用 Spring-security。用户及其各自的角色保存在数据库中。我当前的任务是实现“注册用户”表单。我正在使用一个简单的 .jsp 和 spring 表单。用户可以有 2 个角色：ROLE_USER 和 ROLE_ADMIN，并且默认选中 ROLE_USER。
这是我的 AppUser 和 AppUserRoles 模型。
应用用户.java：
import java.util.HashSet;
import java.util.Set;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.Id;
import javax.persistence.OneToMany;
import javax.persistence.Table;
import javax.validation.constraints.Size;
import org.hibernate.validator.constraints.NotEmpty;
@Entity
@Table(name="appusers")
public class AppUser {
@Id
@Column(name="USERNAME", unique = true, nullable = false, length = 45)
@NotEmpty(message="Username field cannot be empty")
private String username;
@Column(name="PASSWORD", nullable = false, length = 60)
@NotEmpty(message="Password field cannot be empty")
@Size(min=6,max=10,message="Password must be between 6 and 10 letters")
private String password;
@NotEmpty(message="The user must have at least one defined role")
@OneToMany(fetch = FetchType.LAZY, mappedBy = "appUser")
private Set<AppUserRole> userRole = new HashSet<AppUserRole>(0);
public AppUser() {
super();
}
public AppUser(String username, String password) {
super();
this.username = username;
this.password = password;
}
public AppUser(String username, String password, Set<AppUserRole> userRole) {
super();
this.username = username;
this.password = password;
this.userRole = userRole;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public Set<AppUserRole> getUserRole() {
return userRole;
}
public void setUserRole(Set<AppUserRole> userRole) {
this.userRole = userRole;
}
}
应用用户角色.java
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.Table;
@Entity
@Table(name="appuser_roles")
public class AppUserRole {
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(name = "USER_ROLE_ID", unique = true, nullable = false)
private Integer userRoleId;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "username", nullable = false)
private AppUser appUser;
@Column(name = "ROLE", nullable = false, length = 45)
private String role;
public AppUserRole() {
super();
}
public AppUserRole(AppUser appuser, String role) {
super();
this.appUser = appuser;
this.role = role;
}
public Integer getUserRoleId() {
return userRoleId;
}
public void setUserRoleId(Integer userRoleId) {
this.userRoleId = userRoleId;
}
public AppUser getAppuser() {
return appUser;
}
public void setAppuser(AppUser appuser) {
this.appUser = appuser;
}
public String getRole() {
return role;
}
public void setRole(String role) {
this.role = role;
}
}
包含 registerUser() 方法的 AppUserDAOImpl.java 片段：
@Override
public void registerUser(AppUser appUser) {
sessionFactory.getCurrentSession().persist(appUser);
logger.info(appUser.getUsername() + " persisted");
}
与注册表单相关的 UserController.java 片段：
@RequestMapping(value="/register")
public String goRegister(Model model) {
model.addAttribute("AppUser", new AppUser());
return "register";
}
@RequestMapping(value= "/registeruser_action", method = RequestMethod.POST)
public String addUser(@ModelAttribute("AppUser") @Valid AppUser appUser, BindingResult result){
if(result.hasErrors()){
return "register";
}
appUserDetailsService.registerUser(appUser);
return "redirect:/menu";
}
register.jsp 片段的实际形式：
<sf:form commandName="AppUser" action="registeruser_action" method="POST" >
<div>
Username:<br>
<sf:input type="text" path="username"/>
<sf:errors path="username" cssClass="errors"/>
</div>
<div>
Password<br>
<sf:input type="text" path="password"/>
<sf:errors path="password" cssClass="errors"/>
</div>
<div>
User role:<br>
<sf:checkbox path="userRole" value="ROLE_USER"
disabled="true" checked="true" /> User <br>
<sf:checkbox path="userRole" value="ROLE_ADMIN"/> Admin <br>
<sf:errors path="userRole" cssClass="errors"/>
</div>
<br>
<input type="submit" value="Submit">
</sf:form>
具体来说，我想要做什么但似乎无法在互联网上弄清楚或找到：我希望将复选框选择添加到我的 AppUser.java 模型中设置的 userRole 中，然后将它们持久化。问题是，我之前在我的项目中已经将表单输入映射到对象字段，但从未映射到集合。我内心的乐观主义者非常希望我可以通过将复选框映射到 spring 表单中的 userRole 路径来做到这一点，也许 java 和 spring 会“自动”理解它应该将它们添加到该集合中。我内心的现实主义者有点知道这不是那么简单。老实说，我知道这很简单，但我似乎无法找到解决方案。希望在这里找到解决方案。
PS：我只发布了我认为对这个问题很重要的内容。例如，服务层似乎是额外的。将根据需要发布额外的信息/代码。
编辑： 好的，我按照akshay的建议在构造函数中添加了ROLE_USER。尝试注册新用户时产生的异常让我意识到我完全错了。我正在尝试将 String 分配给 Set 对象。userRole 是 Set 类型，ROLE_USER 是一个字符串。该集合包含 AppUserRole 对象，该对象应包含用户名和相应的角色字符串。基本上，现在的问题是：如何将包含用户名和相应角色的新对象直接从 spring 表单添加到 userRole 集中？