1

我有一张表，上面有班次历史和 emp id。

我正在使用此查询通过指定要计数的范围来检索员工列表及其总班次：

SELECT ope_id, count(ope_id)
FROM operator_shift
WHERE ope_shift_date >=to_date( '01-MAR-10','dd-mon-yy') and ope_shift_date
<= to_date('31-MAR-10','dd-mon-yy')
GROUP BY OPE_ID

这使

   OPE_ID      COUNT(OPE_ID)
     1            14
     2             7
     3             6
     4             6
     5             2
     6             5
     7             2
     8             1
     9             2
    10             4

选择了 10 行。

如何选择指定范围日期下班次最多的员工？

4

3 回答 3

1

假设您的 Oracle 版本足够新以支持公用表表达式：

With ShiftCounts As
    (
    SELECT ope_id, count(ope_id) ShiftCount
        , ROW_NUMBER() OVER( ORDER BY Count(ope_id) Desc ) ShiftRank
    FROM operator_shift
    WHERE ope_shift_date >=to_date( '01-MAR-10','dd-mon-yy') 
        and ope_shift_date <= to_date('31-MAR-10','dd-mon-yy')
    GROUP BY OPE_ID 
    )
Select ope_id, ShiftCount
From ShiftCounts
Where ShiftRank = 1
于 2010-04-26T20:49:41.530 回答
0

可能是这样的：

SELECT TOP 1 ope_id, Count(ope_id)
FROM operator_shift
WHERE ope_shift_date >=to_date( '01-MAR-10','dd-mon-yy') and ope_shift_date
<= to_date('31-MAR-10','dd-mon-yy')
GROUP BY OPE_ID 
ORDER BY Count(ope_id) DESC
于 2010-04-26T20:42:32.727 回答
0

采用：

SELECT t.ope_id,
       t.num
  FROM (SELECT os.ope_id, 
               COUNT(os.ope_id) AS num
          FROM OPERATOR_SHIFT os
         WHERE os.ope_shift_date BETWEEN TO_DATE('01-MAR-10','dd-mon-yy') 
                                     AND TO_DATE('31-MAR-10','dd-mon-yy')
      GROUP BY os.ope_id
      ORDER BY num DESC) t
 WHERE ROWNUM = 1

参考：

于 2010-04-26T20:50:00.797 回答