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我在 MongoDB 中有一个事件集合，其中包含一些 HTTP 请求信息。我想知道是否有一种方法可以根据特定的“路径”值找到响应最多的“测功机”。例如对于“random_path_users”，对于这种特定类型的请求，我想找到其计数优于其他 dyno 的“dyno”值。

{"_id"=>BSON::ObjectId('54738b3ff572e27e6b4b2a3b'), "method"=>"GET", "path"=>"users_count_pending_msg", "dyno"=>"web.1", "connect"=>1, "service"=>10}
{"_id"=>BSON::ObjectId('54738b3ff572e27e6b4b2a3c'), "method"=>"GET", "path"=>"users_count_pending_msg", "dyno"=>"web.1", "connect"=>6, "service"=>13}
{"_id"=>BSON::ObjectId('54738b3ff572e27e6b4b2a3d'), "method"=>"GET", "path"=>"users_get_score", "dyno"=>"web.5", "connect"=>3, "service"=>155}
{"_id"=>BSON::ObjectId('54738b3ff572e27e6b4b2a3e'), "method"=>"GET", "path"=>"users_get_msg", "dyno"=>"web.10", "connect"=>1, "service"=>32}
{"_id"=>BSON::ObjectId('54738b3ff572e27e6b4b2a53'), "method"=>"POST", "path"=>"random_path_users", "dyno"=>"web.3", "connect"=>3, "service"=>55}
{"_id"=>BSON::ObjectId('54738b3ff572e27e6b4b2a54'), "method"=>"GET", "path"=>"random_path_users", "dyno"=>"web.10", "connect"=>1, "service"=>45}
{"_id"=>BSON::ObjectId('54738b3ff572e27e6b4b2a55'), "method"=>"GET", "path"=>"users_get_msg", "dyno"=>"web.10", "connect"=>2, "service"=>41}
{"_id"=>BSON::ObjectId('54738b3ff572e27e6b4b2a56'), "method"=>"POST", "path"=>"random_path_users", "dyno"=>"web.3", "connect"=>2, "service"=>31}
{"_id"=>BSON::ObjectId('54738b3ff572e27e6b4b2a57'), "method"=>"GET", "path"=>"users_count_pending_msg", "dyno"=>"web.11", "connect"=>1, "service"=>232}
{"_id"=>BSON::ObjectId('54738b3ff572e27e6b4b2a58'), "method"=>"POST", "path"=>"api_users", "dyno"=>"web.4", "connect"=>3, "service"=>37}
{"_id"=>BSON::ObjectId('54738b3ff572e27e6b4b2a59'), "method"=>"GET", "path"=>"users_count_pending_msg", "dyno"=>"web.6", "connect"=>0, "service"=>10}
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1 回答 1

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使用聚合框架：

db.events.aggregate([
    { "$match" : { "path" : "random_path_users" } },
    { "$group" : { "_id" : "$dyno", "count" : { "$sum" : 1 } } },
    { "$sort" : { "count" : -1 } },
    { "$limit" : 1 }
])

这将返回等于“random_path_users”dyno的所有请求中请求数最多的值。path

于 2014-11-25T01:40:21.937 回答