3

我有一个 3 维的 boost::multi_array

 boost::multi_array<Struct, 3>* newArr = new boost::multi_array<Struct, 3>(boost::extents[x][y][z], boost::fortran_storage_order())

有没有方法来计算 newArr 的大小或者我应该只使用

sizeof(Struct)*x*y*z ?

他们会一样吗?(我希望 multi_array 有一点控制器数据)

4

1 回答 1

5

你应该可以使用

sizeof(Struct)*x*y*z + sizeof(boost::multi_array<Struct, 3>)

让我搜索一下文档是否揭示了一种更简单/更通用的方法。

另外,我喜欢不打扰并使用 eg 的输出valgrind --tool=massif来确切知道分配在哪里。如果你有,这也会给出相关的结果,例如

struct Struct {
    std::string x;
    char const* my_data;
};

下面是 Massif 使用仅包含一个std::string成员的 Struct 时的示例输出:

#include <boost/multi_array.hpp>
struct Struct {
    std::string x;
};

int main() {
    int x=300,y=400,z=400;
    boost::multi_array<Struct, 3>* newArr = new boost::multi_array<Struct, 3>(boost::extents[x][y][z], boost::fortran_storage_order());
}

这导致例如在我的系统上384,000,160 bytes,这正是您添加时打印的内容std::cout << 300*400*400*sizeof(Struct)+sizeof(*newArr);

/tmp$ valgrind --tool=massif --detailed-freq=1 ./test
/tmp$ ms_print massif.out.32149 
--------------------------------------------------------------------------------
Command:            ./test
Massif arguments:   --detailed-freq=1
ms_print arguments: massif.out.32149
--------------------------------------------------------------------------------


    MB
366.2^                                                                       @
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   0 +----------------------------------------------------------------------->Mi
     0                                                                   1.273

Number of snapshots: 3
 Detailed snapshots: [0, 1, 2]

--------------------------------------------------------------------------------
  n        time(i)         total(B)   useful-heap(B) extra-heap(B)    stacks(B)
--------------------------------------------------------------------------------
  0              0                0                0             0            0
00.00% (0B) (heap allocation functions) malloc/new/new[], --alloc-fns, etc.

--------------------------------------------------------------------------------
  n        time(i)         total(B)   useful-heap(B) extra-heap(B)    stacks(B)
--------------------------------------------------------------------------------
  1      1,332,810              168              160             8            0
95.24% (160B) (heap allocation functions) malloc/new/new[], --alloc-fns, etc.
->95.24% (160B) 0x400ADA: main (test.cpp:8)

--------------------------------------------------------------------------------
  n        time(i)         total(B)   useful-heap(B) extra-heap(B)    stacks(B)
--------------------------------------------------------------------------------
  2      1,334,836      384,004,208      384,000,160         4,048            0
100.00% (384,000,160B) (heap allocation functions) malloc/new/new[], --alloc-fns, etc.
->100.00% (384,000,000B) 0x401722: __gnu_cxx::new_allocator<Struct>::allocate(unsigned long, void const*) (new_allocator.h:94)
| ->100.00% (384,000,000B) 0x40138D: boost::multi_array<Struct, 3ul, std::allocator<Struct> >::allocate_space() (multi_array.hpp:474)
|   ->100.00% (384,000,000B) 0x400E52: boost::multi_array<Struct, 3ul, std::allocator<Struct> >::multi_array(boost::detail::multi_array::extent_gen<3ul> const&, boost::general_storage_order<3ul> const&) (multi_array.hpp:195)
|     ->100.00% (384,000,000B) 0x400AEB: main (test.cpp:8)
|       
->00.00% (160B) in 1+ places, all below ms_print's threshold (01.00%)
于 2014-11-23T20:29:29.110 回答