74

更新:我认为它工作正常。但经过一些测试后问题仍然存在*嗅探*

然后我做了一个更简单的版本来看看到底发生了什么,我知道应该被分离的令人耳目一新的片段仍然留在那里。或者确切地说,旧片段的视图留在新片段的顶部。由于我原来的app的RecyclerView的背景是不透明的,所以原来是我之前说的。

更新结束


我有一个MainActivity这样的布局:

<android.support.v4.widget.DrawerLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools" android:id="@+id/drawer_layout"
android:layout_width="match_parent" android:layout_height="match_parent">

    <!-- As the main content view, the view below consumes the entire
         space available using match_parent in both dimensions. -->
    <FrameLayout android:id="@+id/container" android:layout_width="match_parent"
        android:layout_height="match_parent" />

    <!-- android:layout_gravity="start" tells DrawerLayout to treat
         this as a sliding drawer on the left side for left-to-right
         languages and on the right side for right-to-left languages.
         If you're not building against API 17 or higher, use
         android:layout_gravity="left" instead. -->
    <!-- The drawer is given a fixed width in dp and extends the full height of
         the container. -->
    <fragment android:id="@+id/navigation_drawer"
        android:layout_width="@dimen/navigation_drawer_width" android:layout_height="match_parent"
        android:layout_gravity="start" tools:layout="@layout/fragment_navigation_drawer" />

</android.support.v4.widget.DrawerLayout>

ContentView我用来填充的片段@id/container配置为:

<android.support.v4.widget.SwipeRefreshLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/contentView"
android:layout_width="match_parent"
android:layout_height="match_parent">

<android.support.v7.widget.RecyclerView
    android:id="@+id/tweet_list"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:background="@color/grey_300"/>

</android.support.v4.widget.SwipeRefreshLayout>

这里onCreateView()ContentView

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {
    // Inflate the layout for this fragment
    View inflatedView = inflater.inflate(R.layout.fragment_content, container, false);

    mRecyclerView = (RecyclerView) inflatedView.findViewById(R.id.tweet_list);
    mRecyclerView.setHasFixedSize(false);

    mLinearLayoutManager = new LinearLayoutManager(getActivity().getApplicationContext());
    mRecyclerView.setLayoutManager(mLinearLayoutManager);

    mTweetList = new ArrayList<Tweet>;
    mAdapter = new TweetAdapter(mTweetList);
    mRecyclerView.setAdapter(mAdapter);
    mRecyclerView.setItemAnimator(new DefaultItemAnimator());

    mSwipeRefreshLayout = (SwipeRefreshLayout) inflatedView.findViewById(R.id.contentView);
    mSwipeRefreshLayout.setOnRefreshListener(
        ...
    );
    return inflatedView;
}

然后在MainActivity我通过切换不同的内容来切换要显示的内容ContentView。一切看起来都不错,除了一件事:当我在导航抽屉刷新期间切换ContentView片段时,内容会冻结。但实际上所有事情都照常工作,除了你看不到它。

4

8 回答 8

106

嗯......经过一番挣扎,我最终以一种棘手的方式自己解决了这个问题......

我只需要添加这些onPause()

@Override
public void onPause() {
    super.onPause();
    ...

    if (mSwipeRefreshLayout!=null) {
        mSwipeRefreshLayout.setRefreshing(false);
        mSwipeRefreshLayout.destroyDrawingCache();
        mSwipeRefreshLayout.clearAnimation();
    }
}
于 2014-11-22T03:58:01.490 回答
76

appcompat 22.1.1 中似乎仍然存在此问题。将 SwipeRefreshLayout 包装在 FrameLayout 中为我解决了这个问题

<FrameLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent">

<android.support.v4.widget.SwipeRefreshLayout

    android:id="@+id/contentView"
    android:layout_width="match_parent"
    android:layout_height="match_parent">

    <android.support.v7.widget.RecyclerView
        android:id="@+id/tweet_list"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:background="@color/grey_300" />

</android.support.v4.widget.SwipeRefreshLayout>
</FrameLayout>
于 2015-06-01T14:48:36.843 回答
3

除了@zlm2012 的回答,我注意到这个问题在支持库 21.0.0 下被复制,但现在似乎在 21.0.3 得到修复

于 2015-01-08T11:01:06.177 回答
1

该解决方案有效,但我认为最好将这些行放入自己的函数中,例如:

public void terminateRefreshing() {
    mSwipeRefreshLayout.setRefreshing(false);
    mSwipeRefreshLayout.destroyDrawingCache();
    mSwipeRefreshLayout.clearAnimation();
}

并在切换片段时调用。

Fragment prevFrag = fragmentManager.findFragmentById(drawerContainerId);

if(prevFrag instanceof SwipeRefreshFragment) {
    ((SwipeRefreshFragment)prevFrag).terminateRefreshing();
}

fragmentManager.beginTransaction().replace(drawerContainerId, fragment).commit();
于 2015-06-02T23:17:42.643 回答
1

有用!只需从片段替换中删除过渡,就我而言,我从代码中删除了以下内容:

.setTransition(FragmentTransaction.TRANSIT_FRAGMENT_OPEN)
于 2016-07-06T19:40:08.367 回答
1

设置clickable="true"在顶级父布局中......它可能会解决问题。

于 2017-02-18T12:29:41.910 回答
0

目前,您可以通过以下方式避免该问题:

public class FixedRefreshLayout extends SwipeRefreshLayout {

    private static final String TAG = "RefreshTag";
    private boolean selfCancelled = false;

    public FixedRefreshLayout(Context context) {
        super(context);
    }

    public FixedRefreshLayout(Context context, AttributeSet attrs) {
        super(context, attrs);
    }

    @Override
    protected Parcelable onSaveInstanceState()
    {
        if(isRefreshing()) {
            clearAnimation();
            setRefreshing(false);
            selfCancelled = true;
            Log.d(TAG, "For hide refreshing");
        }
        return super.onSaveInstanceState();
    }

    @Override
    public void setRefreshing(boolean refreshing) {
        super.setRefreshing(refreshing);
        selfCancelled = false;
    }

    @Override
    public void onWindowFocusChanged(boolean hasWindowFocus) {
        super.onWindowFocusChanged(hasWindowFocus);
        if(hasWindowFocus && selfCancelled) {
            setRefreshing(true);
            Log.d(TAG, "Force show refreshing");
        }
    }
}

如果您决定不切换片段(来自某个菜单),这具有恢复动画的额外优势。它还与内部动画相关联,以确保如果网络刷新已经完成,刷新动画不会返回。

于 2016-02-22T04:32:35.723 回答
0

每当单击导航菜单项时终止 SwipeRefresh。有效。

private void selectItem(int position) {

       mSwipeRefreshLayout.setRefreshing(false);

       /*
        Other part of the function
       */
}
于 2016-08-13T13:12:53.013 回答