0

我实现了对字符串中的子字符串的搜索，我想让这个搜索“重音自然”或者它可能被称为粗糙 - 如果我在“rábano”中开始搜索“aba”，我应该会成功。

在Find substring in string using locale中有一个有效的答案：

#include <locale>
#include <string>
#include <boost/locale.hpp>    
std::string NormalizeString(const std::string & input)
{
    std::locale loc =  boost::locale::generator()("");
    const boost::locale::collator<char>& collator = std::use_facet<boost::locale::collator<char> >(loc);      
    std::string result = collator.transform(boost::locale::collator_base::primary, input);
    return result;
}

此解决方案的唯一问题 - 转换将几个字节添加到字符串的末尾。在我的情况下，它是“\x1\x1\x1\x1\x0\x0\x0”。四个字节，一个 1 和几个零字节。当然，擦除这些字节很容易，但我不想依赖这种微妙的实现细节。（代码应该是跨平台的）

有没有更靠谱的方法？

4

2 回答 2

0

作为@R。Martinho Fernandes 表示，通过 boost 实现这样的搜索似乎是不可能的。我在 chrome 资源中找到了解决方案。它使用ICU。

// This class is for speeding up multiple StringSearchIgnoringCaseAndAccents()
// with the same |find_this| argument. |find_this| is passed as the constructor
// argument, and precomputation for searching is done only at that timing.
class CStringSearchIgnoringCaseAndAccents 
{
public:
    explicit CStringSearchIgnoringCaseAndAccents(std::u16string find_this);
    ~CStringSearchIgnoringCaseAndAccents();
    // Returns true if |in_this| contains |find_this|. If |match_index| or
    // |match_length| are non-NULL, they are assigned the start position and total
    // length of the match.
    bool SearchIn(const std::u16string& in_this, size_t* match_index = nullptr, size_t* match_length = nullptr);

private:
    std::u16string _find_this;
    UStringSearch* _search_handle;
};

CStringSearchIgnoringCaseAndAccents::CStringSearchIgnoringCaseAndAccents(std::u16string find_this) : 
    _find_this(std::move(find_this)),
_search_handle(nullptr)
{
    // usearch_open requires a valid string argument to be searched, even if we
    // want to set it by usearch_setText afterwards. So, supplying a dummy text.
    const std::u16string& dummy = _find_this;
    UErrorCode status = U_ZERO_ERROR;
    _search_handle = usearch_open((const UChar*)_find_this.data(), _find_this.size(),
    (const UChar*)dummy.data(), dummy.size(), uloc_getDefault(), NULL, &status);
    if (U_SUCCESS(status)) {
        UCollator* collator = usearch_getCollator(_search_handle);
        ucol_setStrength(collator, UCOL_PRIMARY);
        usearch_reset(_search_handle);
    }
}
CStringSearchIgnoringCaseAndAccents::~CStringSearchIgnoringCaseAndAccents() 
{
    if (_search_handle) usearch_close(_search_handle);
}
bool CStringSearchIgnoringCaseAndAccents::SearchIn(const std::u16string& in_this, size_t* match_index, size_t* match_length) 
{
    UErrorCode status = U_ZERO_ERROR;
    usearch_setText(_search_handle, (const UChar*) in_this.data(), in_this.size(), &status);
    // Default to basic substring search if usearch fails. According to
    // http://icu-project.org/apiref/icu4c/usearch_8h.html, usearch_open will fail
    // if either |find_this| or |in_this| are empty. In either case basic
    // substring search will give the correct return value.
    if (!U_SUCCESS(status)) {
        size_t index = in_this.find(_find_this);
        if (index == std::u16string::npos) {
            return false;
        }
        else {
            if (match_index)
                *match_index = index;
            if (match_length)
                *match_length = _find_this.size();
            return true;
        }
    }
    int32_t index = usearch_first(_search_handle, &status);

    if (!U_SUCCESS(status) || index == USEARCH_DONE) return false;
    if (match_index)
    {
        *match_index = static_cast<size_t>(index);
    }
    if (match_length)
    {
        *match_length = static_cast<size_t>(usearch_getMatchedLength(_search_handle));
    }
    return true;
}

用法：

CStringSearchIgnoringCaseAndAccents searcher(a_utf16_string_what.c_str()));
searcher.SearchIn(a_utf16_string_where)
于 2014-11-27T12:47:18.950 回答
0

即使这是一个老问题，我还是决定发布我的解决方案，因为它可能会帮助某人（或者有人可以告诉我我是否错了）。我使用了boost 文本转换方法。首先，我应用了归一化形式分解 (NFD)，它给了我分离的字符。然后我只是过滤了那些代码低于 255 的代码。然后是一个简单的小写转换。它适用于您的问题（也适用于我的问题），但我不确定它是否适用于所有情况。这是解决方案：

#include <iostream>
#include <algorithm>
#include <string>
#include <locale>
#include <boost/locale.hpp>

static std::locale loc =  boost::locale::generator()("en_US.UTF-8");

std::string NormalizeString(const std::string & input)
{
    std::string s_norm = boost::locale::normalize(input, boost::locale::norm_nfd, loc);

    std::string s;
    std::copy_if(s_norm.begin(), s_norm.end(), std::back_inserter(s), [](unsigned int ch){return ch<256;} );

    return boost::locale::to_lower(s, loc);
}

void find_norm(const std::string& input, const std::string& query) {
    if (NormalizeString(input).find(NormalizeString(query)) != std::string::npos)
        std::cout << query << " found in " << input << std::endl;
    else
        std::cout << query << " not found in " << input << std::endl;
}

int main(int argc, char *argv[])
{
    find_norm("rábano", "aba");
    find_norm("rábano", "aaa");

    return EXIT_SUCCESS;
}
于 2017-10-03T18:42:33.657 回答