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我一直在努力解决这个问题——我在这里广泛搜索了答案，但没有找到任何答案（如果我错过了一个解决方案，请道歉）。我正在实现“使用 Google 登录”按钮/逻辑，除了更改设备方向外，一切正常。在这种情况下，我会看到 Google 权限对话框的多个副本。（因此，如果我更改了 3 次方向，则在返回到原始屏幕之前，我必须取消权限对话框的三个副本）。（可以在此处找到权限对话框的示例）。

我以为我的代码过于复杂，所以我做了一个新活动，只使用了 Google 教程页面（入门/登录）中的代码，但我仍然遇到同样的问题。（代码如下）

（FWIW，我还尝试使用 IntelliJ 的“New --> Activity --> Login Activity”选项创建一个新的 Activity，结果相同。）

除此之外，我尝试运行 Google 的“快速入门”应用程序，是的，同样的问题仍在发生！

有没有其他人在没有这种行为的情况下成功实现了“使用 Google 登录”？我想作为最后的手段，我可​​以强制我的身份验证活动始终以纵向显示，但我正在尝试查看是否有除此之外的解决方案。

先感谢您！

以下是我的“简化”活动中的代码：

package com.myapp.test.view.housekeeping;

import android.content.Intent;
import android.content.IntentSender;
import android.os.Bundle;
import android.support.v7.app.ActionBarActivity;
import android.view.View;
import android.widget.Toast;
import com.myapp.test.R;
import com.google.android.gms.common.ConnectionResult;
import com.google.android.gms.common.api.GoogleApiClient;
import com.google.android.gms.plus.Plus;

public class AuthenticateActivity_BareBones extends ActionBarActivity
        implements GoogleApiClient.ConnectionCallbacks, GoogleApiClient.OnConnectionFailedListener {

    /* Request code used to invoke sign in user interactions. */
    private static final int RC_SIGN_IN = 1;

    /* Client used to interact with Google APIs. */
    private GoogleApiClient mGoogleApiClient;

    /* A flag indicating that a PendingIntent is in progress and prevents
     * us from starting further intents.
     */
    private boolean mIntentInProgress;

    /* Track whether the sign-in button has been clicked so that we know to resolve
     * all issues preventing sign-in without waiting.
     */
    private boolean mSignInClicked;

    /* Store the connection result from onConnectionFailed callbacks so that we can
     * resolve them when the user clicks sign-in.
     */
    private ConnectionResult mConnectionResult;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_authenticate);

        mGoogleApiClient = new GoogleApiClient.Builder(this)
                .addConnectionCallbacks(this)
                .addOnConnectionFailedListener(this)
                .addApi(Plus.API)
                .addScope(Plus.SCOPE_PLUS_LOGIN)
                .build();
    }

    @Override
    protected void onStart() {
        super.onStart();
        mGoogleApiClient.connect();
    }

    @Override
    protected void onStop() {
        super.onStop();
        if (mGoogleApiClient.isConnected()) {
            mGoogleApiClient.disconnect();
        }
    }

    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);
        switch (requestCode) {
            case RC_SIGN_IN:
                if (resultCode != RESULT_OK) {
                    mSignInClicked = false;
                }

                mIntentInProgress = false;

                if (!mGoogleApiClient.isConnecting()) {
                    mGoogleApiClient.connect();
                }
                break;
        }
    }

    public void onButtonClick(View view) {
        int id = view.getId();
        switch (id) {
            case R.id.login_authenticate_google_button:
                if (!mGoogleApiClient.isConnecting()) {
                    mSignInClicked = true;
                    resolveSignInError();
                }
                break;
        }
    }

    @Override
    public void onConnected(Bundle connectionHint) {
        // We've resolved any connection errors.  mGoogleApiClient can be used to
        // access Google APIs on behalf of the user.
        mSignInClicked = false;
        Toast.makeText(this, "Connected to Google!", Toast.LENGTH_SHORT).show();
    }

    @Override
    public void onConnectionSuspended(int cause) {
        mGoogleApiClient.connect();
    }

    @Override
    public void onConnectionFailed(ConnectionResult result) {
        if (!mIntentInProgress) {
            // Store the ConnectionResult so that we can use it later when the user clicks
            // 'sign-in'.
            mConnectionResult = result;

            if (mSignInClicked) {
                // The user has already clicked 'sign-in' so we attempt to resolve all
                // errors until the user is signed in, or they cancel.
                resolveSignInError();
            }
        }
    }

    /* A helper method to resolve the current ConnectionResult error. */
    private void resolveSignInError() {
        if (mConnectionResult.hasResolution()) {
            try {
                mIntentInProgress = true;
                startIntentSenderForResult(mConnectionResult.getResolution().getIntentSender(),
                        RC_SIGN_IN, null, 0, 0, 0);
            } catch (IntentSender.SendIntentException e) {
                // The intent was canceled before it was sent.  Return to the default
                // state and attempt to connect to get an updated ConnectionResult.
                mIntentInProgress = false;
                mGoogleApiClient.connect();
            }
        }
    }
}
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1 回答 1

0

mSignInClicked 实际上在此代码中为您保护旋转案例，因此仅一次正确触发了分辨率。多次重新显示“帐户选择器”对话框时，我得到了相同的行为。

这看起来像是 Google Play 服务第 7 版中的一个错误 - 将在上游提交，并希望它应该在未来的版本中得到解决。

于 2015-04-15T16:40:12.577 回答