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我在 Delphi XE3 上使用 DCEF3。

任务是:为不同的 TChromium 实例创建不同的 cookie 存储。
问题:我正在为每个 TChromium 实例创建不同的 ICefCookieManager 实例,并在 GetCookieManager 事件中返回。

示例代码:

type
  TForm1 = class(TForm)
    Button1: TButton;
    Button2: TButton;
    Chromium1: TChromium;
    Chromium2: TChromium;
    procedure Button1Click(Sender: TObject);
    procedure Button2Click(Sender: TObject);
    procedure FormCreate(Sender: TObject);
    procedure Chromium1GetCookieManager(Sender: TObject;
      const browser: ICefBrowser; const mainUrl: ustring;
      out Result: ICefCookieManager);
    procedure Chromium2GetCookieManager(Sender: TObject;
      const browser: ICefBrowser; const mainUrl: ustring;
      out Result: ICefCookieManager);
  private
    { Private declarations }
      CookieManager: ICefCookieManager;
      CookieManager2: ICefCookieManager;
  public
    { Public declarations }
  end;

var
  Form1: TForm1;

procedure TForm1.FormCreate(Sender: TObject);
begin
    CookieManager:=TCefCookieManagerRef.New('C:\Cookies\1');
    CookieManager2:=TCefCookieManagerRef.New('C:\Cookies\2');
end;

procedure TForm1.Chromium1GetCookieManager(Sender: TObject;
  const browser: ICefBrowser; const mainUrl: ustring;
  out Result: ICefCookieManager);
begin
    Result:=CookieManager;
end;

procedure TForm1.Chromium2GetCookieManager(Sender: TObject;
  const browser: ICefBrowser; const mainUrl: ustring;
  out Result: ICefCookieManager);
begin
    Result:=CookieManager2;
end;

procedure TForm1.Button1Click(Sender: TObject);
begin
    Chromium1.Load('http://somesite.com');
end;

procedure TForm1.Button2Click(Sender: TObject);
begin
    Chromium2.Load('http://somesite.com');
end;

如果我添加ShowMessage('First')Chromium1GetCookieManagerevent 和ShowMessage('Second')to Chromium2GetCookieManager,无论我按下 button1 还是 button2,总是会显示消息“First”。
换句话说,两个实例都会调用 Chromium1GetCookieManager。

4

1 回答 1

1

问题解决了,谢谢大家。

如何解决问题?
只需在 project1.dpr 中关闭 cefsingleprocess 变量即可。
例子:

program Project1;

uses
  Forms,
  cefvcl,
  ceflib,
  Unit1 in 'Unit1.pas' {Form1};

{$R *.res}

begin
  CefSingleProcess := False;//this what i'm talking about
  Application.Initialize;
  Application.CreateForm(TForm1, Form1);
  Application.Run;
end.
于 2014-11-11T18:48:34.817 回答