我有一个场景，我从我的地图服务器获取了一些图块（例如 12 个）。现在对于缓冲和离线功能，我需要将它们全部重新加入，这样我们就必须处理 1 个单个图像对象而不是 12 个。我尝试在没有 JAI 的情况下执行此操作，我的代码如下。
package imagemerge;
import java.awt.*;
import java.awt.image.*;
import java.awt.event.*;
public class ImageSticher extends WindowAdapter {
Image tile1;
Image tile2;
Image result;
ColorModel colorModel;
int width,height,widthr,heightr;
//int t1,t2;
int t12[];
public ImageSticher()
{
}
public ImageSticher (Image img1,Image img2,int w,int h)
{
tile1=img1;
tile2=img2;
width=w;
height=h;
colorModel=ColorModel.getRGBdefault();
}
public Image horizontalStich() throws Exception
{
widthr=width*2;
heightr=height;
t12=new int[widthr * heightr];
int t1[]=new int[width*height];
PixelGrabber p1 =new PixelGrabber(tile1, 0, 0, width, height, t1, 0, width);
p1.grabPixels();
int t2[]=new int[width*height];
PixelGrabber p2 =new PixelGrabber(tile2, 0, 0, width, height, t1, 0, width);
p2.grabPixels();
int y, x, rp, rpi;
int red1, red2, redr;
int green1, green2, greenr;
int blue1, blue2, bluer;
int alpha1, alpha2, alphar;
for(y=0;y<heightr;y++)
{
for(x=0;x<widthr;x++)
{
//System.out.println(x);
rpi=y*widthr+x; // index of resulting pixel;
rp=0; //initializing resulting pixel
System.out.println(rpi);
if(x<(widthr/2)) // x is less than width , copy first tile
{
//System.out.println("tile1="+x);
blue1 = t1[rpi] & 0x00ff; // ERROR occurs here
green1=(t1[rpi] >> 8) & 0x00ff;
red1=(t1[rpi] >> 16) & 0x00ff;
alpha1 = (t1[rpi] >> 24) & 0x00ff;
redr = (int)(red1 * 1.0); // copying red band pixel into redresult,,,,1.0 is the alpha valye
redr = (redr < 0)?(0):((redr>255)?(255):(redr));
greenr = (int)(green1 * 1.0); //
redr = (int)(red1 * 1.0); //
greenr = (greenr < 0)?(0):((greenr>255)?(255):(greenr));
bluer = (int)(blue1 * 1.0);
bluer = (bluer < 0)?(0):((bluer>255)?(255):(bluer));
alphar = 255;
//resulting pixel computed
rp = (((((alphar << 8) + (redr & 0x0ff)) << 8) + (greenr & 0x0ff)) << 8) + (bluer & 0x0ff);
}
else // index is ahead of half way...copy second tile
{
blue2 = t2[rpi] & 0x00ff; // blue band bit of first tile
green2=(t2[rpi] >> 8) & 0x00ff;
red2=(t2[rpi] >> 16) & 0x00ff;
alpha2 = (t2[rpi] >> 24) & 0x00ff;
redr = (int)(red2 * 1.0); // copying red band pixel into redresult,,,,1.0 is the alpha valye
redr = (redr < 0)?(0):((redr>255)?(255):(redr));
greenr = (int)(green2 * 1.0); //
redr = (int)(red2 * 1.0); //
greenr = (greenr < 0)?(0):((greenr>255)?(255):(greenr));
bluer = (int)(blue2 * 1.0);
bluer = (bluer < 0)?(0):((bluer>255)?(255):(bluer));
alphar = 255;
//resulting pixel computed
rp = (((((alphar << 8) + (redr & 0x0ff)) << 8) + (greenr & 0x0ff)) << 8) + (bluer & 0x0ff);
}
t12[rpi] = rp; // copying resulting pixel in the result int array which will be converted to image
}
}
MemoryImageSource mis;
if (t12!=null) {
mis = new MemoryImageSource(widthr, heightr, colorModel, t12, 0, widthr);
result = Toolkit.getDefaultToolkit().createImage(mis);
return result;
}
return null;
}
}
现在检查我的理论我m trying to join or stich two tiles horizontaly but i得到了错误：
java.lang.ArrayIndexOutOfBoundsException: 90000 at imagemerge.ImageSticher.horizontalStich(ImageSticher.java:69) at imageStream.ImageStream.getImage(ImageStream.java:75) at imageStream.ImageStream.main(ImageStream.java:28)
是否存在某种限制，因为当水平拼接两个 300 x 300 的图像时，这意味着生成的图像将是 600 x 300 ...这将使索引大小为 180000，但它在 90000 时给出错误，我在这里做错了什么