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Angular Js 向我返回此错误链接

 [1]http://errors.angularjs.org/1.2.10/$parse/lexerr?p0=Unterminated%20quote&p1=s%2013-14%20%5B'%5D&p2=recipe.ID%20!%3D%3D'

我不知道如何应用该解决方案。请帮我。谢谢我的javascript：

var app = angular.module('sample', [])

app.directive("otcDynamic", function ($compile) {// compile Json data return and wrap inside html
    return {
    link: function (scope, element) {
        var template = global.userhtml;
        var linkFn = $compile(template);
        var content = linkFn(scope);
        element.append(content);
     }
   }
});

从 web api 返回的 Json 数据

var global {
userhtml ='<table class="recipe-table" cellspacing="0" cellpadding="0"><tbody><tr class="recipe-list" data-ng-repeat="recipe in recipe_data" ng-if="recipe.Keyword == keyw.Keyword" ><td  id="td-img{{recipe.CodeListe}}" rowspan="2"><center><span id="img{{recipe.ID}}X"><a id="{{recipe.ID}}" href="javascript:void(0);"> <img  ng-if="recipe.ID !==''" fallback-src="images/default.png" ng-src="{{recipe.Pictures}}" class="images" id="img{{recipe.ID}}"/><img  ng-if="recipe.Pictures===''" class="images" src="images/default.png" id="img1"/></a></span></center></td><td class="recipes"><div id="drn" class="div-recipe-name"><strong>{{recipe.Name}}</strong></div><br /><div id="drd" class="div-recipe-desc">{{recipe.desc}}</div><div class="div-recipe-allergen">{{recipe.allergen}}</div><div class="div-recipe-cost">{{recipe.cost}}</div></td></tr></tbody></table>' 
}

我的HTML：

  <accordion close-others="false">
  <div>
    <accordion-group class="div-recipe-header">
      <accordion-heading></accordion-heading>
        <my-directive></my-directive>
          <div otc-dynamic></div>   
    </accordion-group>
  </div>
</accordion>
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1 回答 1

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您的 web api 应该返回如下内容：

{ 
  global: {
    userhtml: 'your html code in a string' 
  }
}

但请注意，您还有其他方法（更好的方法）可以做到这一点。您可以接收纯 json 数据并使用 html 模板呈现它。

还有一件事：global在许多语言和框架中是保留字，它不是变量或哈希键的好名称。考虑将其更改为更合适的内容。

于 2016-01-07T17:07:50.017 回答