有什么方法可以在 Django 中获取后端中性字典光标?这将是一个字典而不是元组的游标。我被迫在我正在从事的学校项目中使用 Oracle。
在 Python 的 MySQLDb 模块中,它被称为 DictCursor。
有了 WoLpH 的鼓舞人心的建议,我知道我非常接近..
def dict_cursor(cursor):
for row in cursor:
yield dict(zip(cursor.description, row))
迭代并打印用于导致的每一行游标:
(482072, 602592, 1)
(656680, 820855, 2)
(574968, 718712, 4)
(557532, 696918, 3))
但是使用 dict_cursor 我得到:
{('NET_SPENT', <type 'cx_Oracle.NUMBER'>, 127, 22, 0, 0, 1): 482072, ('LOT', <type 'cx_Oracle.NUMBER'>, 12, 22, 11, 0, 0): 1, ('NET_COLLECTED', <type 'cx_Oracle.NUMBER'>, 127, 22, 0, 0, 1): 602592}
{('NET_SPENT', <type 'cx_Oracle.NUMBER'>, 127, 22, 0, 0, 1): 656680, ('LOT', <type 'cx_Oracle.NUMBER'>, 12, 22, 11, 0, 0): 2, ('NET_COLLECTED', <type 'cx_Oracle.NUMBER'>, 127, 22, 0, 0, 1): 820855}
{('NET_SPENT', <type 'cx_Oracle.NUMBER'>, 127, 22, 0, 0, 1): 574968, ('LOT', <type 'cx_Oracle.NUMBER'>, 12, 22, 11, 0, 0): 4, ('NET_COLLECTED', <type 'cx_Oracle.NUMBER'>, 127, 22, 0, 0, 1): 718712}
{('NET_SPENT', <type 'cx_Oracle.NUMBER'>, 127, 22, 0, 0, 1): 557532, ('LOT', <type 'cx_Oracle.NUMBER'>, 12, 22, 11, 0, 0): 3, ('NET_COLLECTED', <type 'cx_Oracle.NUMBER'>, 127, 22, 0, 0, 1): 696918}
我只希望它使用密钥,例如“NET SPENT”。
在对其进行进一步改进后,这似乎可行:
def dict_cursor(cursor):
for row in cursor:
out = {}
for i,col in enumerate(cursor.description):
out[col[0]] = row[i]
yield out
-
{'NET_COLLECTED': 602592, 'NET_SPENT': 482072, 'LOT': 1}
{'NET_COLLECTED': 820855, 'NET_SPENT': 656680, 'LOT': 2}
{'NET_COLLECTED': 718712, 'NET_SPENT': 574968, 'LOT': 4}
{'NET_COLLECTED': 696918, 'NET_SPENT': 557532, 'LOT': 3}