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我尝试了 BLE 的 android 示例应用程序,但我无法获得所需的输出。需要知道如何专门扫描 UUID 并获取设备正在传输的消息。

对于 BLE 发射器,我使用我的 macbook 作为发射器,使用 MacRadius 使其充当信标。

我只想检测我的 mac 的 uuid,然后从中获取一些信息。

需要代码示例

谢谢

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1 回答 1

-1

可以使用以下代码段从scanRecord传递给的参数解析主服务 UUID :BluetoothAdapter.LeScanCallback#onLeScan()

public static List<UUID> parseServiceUuids(final byte[] advertisedData)
    {
        List<UUID> uuids = new ArrayList<UUID>();

         if( advertisedData == null )  return uuids;

        int offset = 0;
        while(offset < (advertisedData.length - 2))
        {
            int len = advertisedData[offset++];
            if(len == 0)
                break;

            int type = advertisedData[offset++];
            switch(type)
            {
                case 0x02: // Partial list of 16-bit UUIDs
                case 0x03: // Complete list of 16-bit UUIDs
                    while(len > 1)
                    {
                        int uuid16 = advertisedData[offset++];
                        uuid16 += (advertisedData[offset++] << 8);
                        len -= 2;
                        uuids.add(UUID.fromString(String.format("%08x-0000-1000-8000-00805f9b34fb", uuid16)));
                    }
                    break;
                case 0x06:// Partial list of 128-bit UUIDs
                case 0x07:// Complete list of 128-bit UUIDs
                      // Loop through the advertised 128-bit UUID's.
                    while(len >= 16)
                    {
                        try
                        {
                            // Wrap the advertised bits and order them.
                            ByteBuffer buffer = ByteBuffer.wrap(advertisedData, offset++, 16).order(ByteOrder.LITTLE_ENDIAN);
                            long mostSignificantBit = buffer.getLong();
                            long leastSignificantBit = buffer.getLong();
                            uuids.add(new UUID(leastSignificantBit, mostSignificantBit));
                        }
                        catch(IndexOutOfBoundsException e)
                        {
                            // Defensive programming.
                            Log.e(TAG, e.toString());
                            continue;
                        }
                        finally
                        {
                            // Move the offset to read the next uuid.
                            offset += 15;
                            len -= 16;
                        }
                    }
                    break;
                default:
                    offset += (len - 1);
                    break;
            }
        }

        return uuids;
    }

然后,您必须scanRecord进一步解析自己以从中获取更多信息。

于 2014-11-13T19:34:03.770 回答