4

So I got an exception from my app as follows:

android.content.ActivityNotFoundException: No Activity found to handle Intent { act=android.intent.action.VIEW dat=http://google.com (has extras) }
    at  android.app.Instrumentation.checkStartActivityResult(Instrumentation.java:1512)
    at  android.app.Instrumentation.execStartActivity(Instrumentation.java:1384)
    at  android.app.Activity.startActivityForResult(Activity.java:3248)
    at  android.support.v4.app.FragmentActivity.startActivityForResult(FragmentActivity.java:839)
    at  android.app.Activity.startActivity(Activity.java:3359)
    at  android.text.style.URLSpan.onClick(URLSpan.java:62)
    at  android.text.method.LinkMovementMethod.onTouchEvent(LinkMovementMethod.java:212)
    at  android.widget.TextView.onTouchEvent(TextView.java:8704)
    at  android.view.View.dispatchTouchEvent(View.java:5556)
    at  android.view.ViewGroup.dispatchTransformedTouchEvent(ViewGroup.java:1957)
    at  android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:1726)
    at  android.view.ViewGroup.dispatchTransformedTouchEvent(ViewGroup.java:1957)
    at  android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:1726)
    at  android.view.ViewGroup.dispatchTransformedTouchEvent(ViewGroup.java:1957)
    at  android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:1726)
    at  android.view.ViewGroup.dispatchTransformedTouchEvent(ViewGroup.java:1957)
    at  android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:1726)
    at  android.view.ViewGroup.dispatchTransformedTouchEvent(ViewGroup.java:1957)
    at  android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:1726)
    at  android.view.ViewGroup.dispatchTransformedTouchEvent(ViewGroup.java:1957)
    at  android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:1726)
    at  com.android.internal.policy.impl.PhoneWindow$DecorView.superDispatchTouchEvent(PhoneWindow.java:1940)
    at  com.android.internal.policy.impl.PhoneWindow.superDispatchTouchEvent(PhoneWindow.java:1390)
    at  android.app.Activity.dispatchTouchEvent(Activity.java:2414)
    at  com.android.internal.policy.impl.PhoneWindow$DecorView.dispatchTouchEvent(PhoneWindow.java:1888)
    at  android.view.View.dispatchPointerEvent(View.java:5736)
    at  android.view.ViewRootImpl.deliverPointerEvent(ViewRootImpl.java:3017)
    at  android.view.ViewRootImpl.handleMessage(ViewRootImpl.java:2582)
    at  android.view.ViewRootImpl.processInputEvents(ViewRootImpl.java:887)
    at  android.view.ViewRootImpl.handleMessage(ViewRootImpl.java:2591)
    at  android.os.Handler.dispatchMessage(Handler.java:99)
    at  android.os.Looper.loop(Looper.java:137)
    at  android.app.ActivityThread.main(ActivityThread.java:4697)
    at  java.lang.reflect.Method.invokeNative(Native Method)
    at  java.lang.reflect.Method.invoke(Method.java:511)
    at  com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:787)
    at  com.android.internal.os.ZygoteInit.main(ZygoteInit.java:554)
    at  dalvik.system.NativeStart.main(Native Method)

This doesn't lead to my code. I assume this happens when user clicks URL in the text (and there are texts with URLs in app). What it's about? How could it be that Android device doesn't have a browser? How to bypass this or at least to catch (I need URLs be clickable in text)?

UPDATE
Actually I found that this exception happens in TextView which is intended to be an empty list view stub:

listView = (ListView) findViewById(R.id.listView);
// empty pass list with clickable url inside
final TextView listEmptyView = (TextView) findViewById(R.id.txtNoPasses);
listEmptyView.setMovementMethod(LinkMovementMethod.getInstance());
listView.setEmptyView(listEmptyView);

So I tried this (following CommonsWare's article) but my URL remains completely unclickable in this case:

    listView = (ListView) findViewById(R.id.listView);
    // empty pass list with clickable url inside
    final TextView listEmptyView = (TextView) findViewById(R.id.txtNoPasses);
    fixTextView(listEmptyView);
    listView.setEmptyView(listEmptyView);
}

private void fixTextView(TextView textView) {
    final SpannableString current = new SpannableString(textView.getText());
    final URLSpan[] spans = current.getSpans(0, current.length(), URLSpan.class);
    int start, end;
    for (URLSpan span : spans) {
        start = current.getSpanStart(span);
        end = current.getSpanEnd(span);
        current.removeSpan(span);
        current.setSpan(new DefensiveURLSpan(span.getURL()), start, end, 0);
    }
}

private static class DefensiveURLSpan extends URLSpan {
      public DefensiveURLSpan(String url) {
        super(url);
      }

      @Override
      public void onClick(View widget) {
        try {
          android.util.Log.d(getClass().getSimpleName(), "Got here!");
          super.onClick(widget);
        }
        catch (ActivityNotFoundException e) {
          // do something useful here
          // android.text.SpannedString cannot be cast to android.text.SpannableString
        }
      }
}

And TextView:

<TextView
        android:id="@+id/txtNoPasses"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_centerHorizontal="true"
        android:layout_centerVertical="true"
        android:visibility="gone"
        android:gravity="center"
        android:padding="15dp"
        android:text="@string/no_passes"
        android:textAppearance="?android:attr/textAppearanceMedium"/>

And no_passes string is following:

<string name="no_passes">Currently you have no cards to use.\n<a href="http://cardz.website.com">You could add some cards from our website</a></string>
4

2 回答 2

5

我假设这是一个带有android:autolinkset 的 TextView，或者以其他方式显示 HTML（例如，使用Html.fromHtml()）。

问题是这会URLSpan为嵌入式 URI 创建实例，并且此类“盲目地”startActivity()使用提供的 URI 调用。只要 URI 与任何注册的活动不匹配，就会崩溃。对于“http” URL，当设备没有浏览器应用程序时，或者（更有可能）使用阻止访问它的受限配置文件时，可能会发生这种情况。

这个 CommonsWare 帖子中很好地解释了这个问题及其解决方案。您可以将实例替换为拦截以避免异常URLSpan的自定义派生类。onClick()

另请参阅此答案以了解相关问题。

于 2014-11-04T23:33:18.797 回答
2

Android 设备可能没有浏览器。据说，这不是必需的，但显然非常罕见。我想到了像 Kindles 这样的 Android 设备，尽管它们仍然会有浏览器......

尽管如此，您可以禁用 URL 链接，TextView如下所示：

textView.setLinksClickable(false);

另外，相关问题。

编辑

看到这个答案：

String url = "http://www.example.com";
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setData(Uri.parse(url));
PackageManager manager = mContext.getPackageManager();
List<ResolveInfo> list = manager.queryIntentActivities(intent, 0);

if (list != null && list.size() > 0) {
    //You have at least one activity to handle the intent
} else {
    //No activity to handle the intent.
}

使用 url创建一个新意图，ACTION_VIEW并使用此模式来确定设备是否有任何可以处理 url 的应用程序。如果没有，则禁用单击TextView该用户的链接。

于 2014-11-04T22:37:53.403 回答