jsf-2 - 如何在jsf中从bean抛出404

Question

我需要抛出 404 并将访问者带到特定页面。我正在尝试使用以下代码：

            FacesContext facesContext = FacesContext.getCurrentInstance();
            ExternalContext externalContext = facesContext.getExternalContext();                
            externalContext.setResponseStatus(HttpServletResponse.SC_NOT_FOUND);
            externalContext.setResponseHeader(Common.LOCATION, "browse_by_category.xhtml?category=CATEGORY_ALL");
            facesContext.responseComplete();

404 发生，但不会发生重定向到 browse_by_category.xhtml 页面。任何帮助将不胜感激。

Answer 1

根据您的评论，请尝试以下操作：

FacesContext facesContext = FacesContext.getCurrentInstance();
        ExternalContext externalContext = facesContext.getExternalContext();                
        externalContext.setResponseStatus(HttpServletResponse.SC_NOT_FOUND);
        //externalContext.setResponseHeader(Common.LOCATION, "browse_by_category.xhtml?category=CATEGORY_ALL");
        externalContext.dispatch("browse_by_category.xhtml");
        facesContext.responseComplete();