8

我刚刚在 virtualenv 上设置了一个 django 应用程序，使用结构脚本进行了顺利部署，但是现在 .wsgi 无法正常工作，我已经尝试了互联网上的所有变体，但没有运气。我的 .wsgi 文件是：

import os
import sys
import django.core.handlers.wsgi

# put the Django project on sys.path
root_path = os.path.abspath(os.path.dirname(__file__) + '../')
sys.path.insert(0, os.path.join(root_path, 'kcdf'))
sys.path.insert(0, root_path)

os.environ['DJANGO_SETTINGS_MODULE'] = 'kcdf.settings'

application = django.core.handlers.wsgi.WSGIHandler()

我不断收到同样的错误：

[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] mod_wsgi (pid=16938): Exception occurred processing WSGI script '/home/kcdfweb/webapps/kcdf.web/releases/current/kcdf/apache/kcdf.wsgi'.
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] Traceback (most recent call last):
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]   File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/wsgi.py", line 230, in __call__
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]     self.load_middleware()
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]   File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py", line 33, in load_middleware
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]     for middleware_path in settings.MIDDLEWARE_CLASSES:
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]   File "/usr/local/lib/python2.6/dist-packages/django/utils/functional.py", line 269, in __getattr__
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]     self._setup()
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]   File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 40, in _setup
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]     self._wrapped = Settings(settings_module)
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]   File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 75, in __init__
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]     raise ImportError, "Could not import settings '%s' (Is it on sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE, e)
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] ImportError: Could not import settings 'kcdf.settings' (Is it on sys.path? Does it have syntax errors?): No module named kcdf.settings

我的虚拟环境在 /home/user/webapps/kcdfweb 我的应用程序是 /home/user/webapps/kcdf.web/releases/current/project_name 我的 wsgi 文件 home/user/webapps/kcdf.web/releases/current/project_name /apache/project_name.wsgi

4

4 回答 4

7

我建议您查看将 Virtualenv 与 mod_wsgi 结合使用的文档。他们提供了一些替代方法来连接您的 virtualenv，这可能对您更有效。

于 2010-04-19T14:34:19.453 回答
1

您需要从 wsgi 文件中添加两个向上的目录，而不是：

root_path = os.path.abspath(os.path.dirname(__file__) + '../')

你应该有

root_path = os.path.abspath(os.path.join(os.path.dirname(__file__), '../', '../'))

apache...因为您的 wsgi 文件位于项目文件夹下名为 的目录中。

于 2010-04-18T13:55:04.303 回答
0

__init__.py您的“kcdf”目录中有文件吗？否则，您的设置文件将无法导入。

此外，如果您希望能够从 virtualenv 导入内容，则应该在 virtualenv 的 site-packages 目录上调用 site.addsitedir()。有关详细信息，请参阅mod_wsgi 文档。虽然如果它甚至无法导入您的设置，我认为这不是您当前的问题。

于 2010-04-19T13:28:30.883 回答
0

如果您使用的是 virtualenv，则需要在 WSGI 脚本中激活它以正确设置路径。

root_path = os.path.abspath(os.path.dirname(__file__) + '../')
activate_this = os.path.join(root_path, "bin/activate_this.py")
execfile(activate_this, dict(__file__=activate_this))
于 2010-04-18T16:56:12.490 回答