我正在尝试使用普林斯顿提供的 LZW 代码并对其进行修改以将代码字的大小从 9 位更改为 16 位。我不确定如何做到这一点,但正在考虑使用循环,因为在使用之前大小的所有码字时需要增加大小。我只是在寻找一个有用的方向,因为这是一项我无法开始的任务。
public class LZW {
private static final int R = 256; // number of input chars
private static final int L = 4096; // number of codewords = 2^W
private static final int W = 12; // codeword width
public static void compress() {
String input = BinaryStdIn.readString();
TST<Integer> st = new TST<Integer>();
for (int i = 0; i < R; i++)
st.put("" + (char) i, i);
int code = R+1; // R is codeword for EOF
while (input.length() > 0) {
String s = st.longestPrefixOf(input); // Find max prefix match s.
BinaryStdOut.write(st.get(s), W); // Print s's encoding.
int t = s.length();
if (t < input.length() && code < L) // Add s to symbol table.
st.put(input.substring(0, t + 1), code++);
input = input.substring(t); // Scan past s in input.
}
BinaryStdOut.write(R, W);
BinaryStdOut.close();
}
public static void expand() {
String[] st = new String[L];
int i; // next available codeword value
// initialize symbol table with all 1-character strings
for (i = 0; i < R; i++)
st[i] = "" + (char) i;
st[i++] = ""; // (unused) lookahead for EOF
int codeword = BinaryStdIn.readInt(W);
if (codeword == R) return; // expanded message is empty string
String val = st[codeword];
while (true) {
BinaryStdOut.write(val);
codeword = BinaryStdIn.readInt(W);
if (codeword == R) break;
String s = st[codeword];
if (i == codeword) s = val + val.charAt(0); // special case hack
if (i < L) st[i++] = val + s.charAt(0);
val = s;
}
BinaryStdOut.close();
}
public static void main(String[] args) {
if (args[0].equals("-")) compress();
else if (args[0].equals("+")) expand();
else throw new IllegalArgumentException("Illegal command line argument");
}
}