所以我正在尝试制作一个显示三个数字的基本程序，然后用户必须重新输入它们以测试他们的注意力。这可能只是因为我正在使用的编译器，但这似乎很奇怪。我在 main 结束时返回的地方遇到了解析错误。继承人的错误：
----jGRASP exec: gcc -g -o Concentration.exe Concentration.c
Concentration.c: In function `main':
Concentration.c:28: error: parse error before "cYesNo"
Concentration.c: At top level:
Concentration.c:53: error: parse error before string constant
Concentration.c:53: warning: conflicting types for built-in function `printf'
Concentration.c:53: warning: data definition has no type or storage class
Concentration.c:54: warning: data definition has no type or storage class
Concentration.c:55: error: parse error before "return"
----jGRASP wedge2: exit code for process is 1.
这也是代码：该文件称为Concetraion.c btw。
Pastebin：http://pastebin.com/GYmhefDE — 标记为私有，因此无法访问
Mediafire 下载：http ://www.mediafire.com/view/kf73fzfsifqfuzj
删减评论，但几乎不是 MCVE：
#include <stdio.h>
#include <conio.h>
#include <stdlib.h>
#include <time.h>
int main()
{
char cYesNo = 'z';
int guessNum1 = 0;
int guessNum2 = 0, guessNum3 = 0;
int randNuml = 0, randNum2 = 0, randNum3 = 0;
int elapsedTime = 0;
int currentTime = 0;
int counter = 0;
srand(time(NULL));
printf("Play a game of Concentration? (y or n): ");
scanf("%c", &cYesNo);
if(cYesNo == 'y' cYesNo == 'Y') // Line 28
{
randNuml = rand() % 100;
randNum2 = rand() % 100;
randNum3 = rand() % 100;
printf("\nConcentrate on the next three numbers\n");
printf("\n\t%d %d %d\n\n", randNuml , randNum2, randNum3);
currentTime = time(NULL);
do{
elapsedTime = time(NULL);
}while ((elapsedTime - currentTime) < 3);
system("cls");
printf("\nEnter each # separated with one space: ");
scanf("%d%d%d", &guessNum1, &guessNum2, &guessNum3);
if(randNuml == guessNum1 && randNum2 == guessNum2 && randNum3 == guessNum3)
printf("\nCongratulations!\n");
else
printf("\nSorry, correct numbers were: %d %d %d\n", randNuml, randNum2, randNum3);
}
printf("\nPress any key to quit"); // Line 53
getch();
return 0;
}