嗨,我是 Django 的新手,我没有在直通模型中获取相关对象。
我的代码:
#models.py
class Candidate(models.Model):
user = models.OneToOneField(User, primary_key=True)
birth = models.CharField(max_length=50)
...
class Job(models.Model):
candidate = models.ManyToManyField('Candidate', through='CandidateToJob')
title = models.CharField(max_length=500)
...
class CandidateToJob(models.Model):
job = models.ForeignKey(Job, related_name='applied_to')
candidate = models.ForeignKey(Candidate, related_name='from_user')
STATUS_CHOICES = (
('1', 'Not approved'),
('2', 'Approved'),
('3', 'Hired')
)
status = models.CharField(max_length=2, choices=STATUS_CHOICES)
在我的观点中
#views.py
class Screening(generic.DetailView):
model = Job
template_name = 'dashboard/screening.html'
def get_context_data(self, **kwargs):
context = super(Screening, self).get_context_data(**kwargs)
context['candidate_list'] = self.object.candidate.select_related().annotate
return context
我有的模板:
#url.py
url(r'^dashboard/job/(?P<pk>\d+)/screening/$', views.Screening.as_view(), name='screening'),
#HTML
{% for candidate in candidate_list %}
{{ candidate.user.get_full_name }} #this works
{% for candidatetojob in job.candidatetojob_set.all %}
{{ candidatetojob.get_status_display }}
{% endfor %}
{% endfor %}
问题是我无法获得与特定工作的候选人相关的状态。我怎么才能得到它?
在不重新加载整个页面的情况下更新此状态的最佳方法是什么?
提前致谢