在我的算法中，我需要创建一个信息输出。我需要将布尔矩阵写入 bmp 文件。它必须是单色图像，如果此类元素上的矩阵为真，则像素为白色。主要问题是 bmp 标头以及如何编写。
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171100 次
12 回答
62
看看这是否适合你...在这段代码中，我有 3 个二维数组，分别称为红色、绿色和蓝色。每个元素的大小为 [宽度] [高度]，每个元素对应一个像素 - 我希望这是有道理的！
FILE *f;
unsigned char *img = NULL;
int filesize = 54 + 3*w*h; //w is your image width, h is image height, both int
img = (unsigned char *)malloc(3*w*h);
memset(img,0,3*w*h);
for(int i=0; i<w; i++)
{
for(int j=0; j<h; j++)
{
x=i; y=(h-1)-j;
r = red[i][j]*255;
g = green[i][j]*255;
b = blue[i][j]*255;
if (r > 255) r=255;
if (g > 255) g=255;
if (b > 255) b=255;
img[(x+y*w)*3+2] = (unsigned char)(r);
img[(x+y*w)*3+1] = (unsigned char)(g);
img[(x+y*w)*3+0] = (unsigned char)(b);
}
}
unsigned char bmpfileheader[14] = {'B','M', 0,0,0,0, 0,0, 0,0, 54,0,0,0};
unsigned char bmpinfoheader[40] = {40,0,0,0, 0,0,0,0, 0,0,0,0, 1,0, 24,0};
unsigned char bmppad[3] = {0,0,0};
bmpfileheader[ 2] = (unsigned char)(filesize );
bmpfileheader[ 3] = (unsigned char)(filesize>> 8);
bmpfileheader[ 4] = (unsigned char)(filesize>>16);
bmpfileheader[ 5] = (unsigned char)(filesize>>24);
bmpinfoheader[ 4] = (unsigned char)( w );
bmpinfoheader[ 5] = (unsigned char)( w>> 8);
bmpinfoheader[ 6] = (unsigned char)( w>>16);
bmpinfoheader[ 7] = (unsigned char)( w>>24);
bmpinfoheader[ 8] = (unsigned char)( h );
bmpinfoheader[ 9] = (unsigned char)( h>> 8);
bmpinfoheader[10] = (unsigned char)( h>>16);
bmpinfoheader[11] = (unsigned char)( h>>24);
f = fopen("img.bmp","wb");
fwrite(bmpfileheader,1,14,f);
fwrite(bmpinfoheader,1,40,f);
for(int i=0; i<h; i++)
{
fwrite(img+(w*(h-i-1)*3),3,w,f);
fwrite(bmppad,1,(4-(w*3)%4)%4,f);
}
free(img);
fclose(f);
于 2010-04-16T17:07:47.777 回答
37
用于位图 (BMP) 图像生成的清洁 C 代码
此代码不使用stdio.h以外的任何库。因此，它可以很容易地融入 C 系列的其他语言中，如 C++、C#、Java。
#include <stdio.h>
const int BYTES_PER_PIXEL = 3; /// red, green, & blue
const int FILE_HEADER_SIZE = 14;
const int INFO_HEADER_SIZE = 40;
void generateBitmapImage(unsigned char* image, int height, int width, char* imageFileName);
unsigned char* createBitmapFileHeader(int height, int stride);
unsigned char* createBitmapInfoHeader(int height, int width);
int main ()
{
int height = 361;
int width = 867;
unsigned char image[height][width][BYTES_PER_PIXEL];
char* imageFileName = (char*) "bitmapImage.bmp";
int i, j;
for (i = 0; i < height; i++) {
for (j = 0; j < width; j++) {
image[i][j][2] = (unsigned char) ( i * 255 / height ); ///red
image[i][j][1] = (unsigned char) ( j * 255 / width ); ///green
image[i][j][0] = (unsigned char) ( (i+j) * 255 / (height+width) ); ///blue
}
}
generateBitmapImage((unsigned char*) image, height, width, imageFileName);
printf("Image generated!!");
}
void generateBitmapImage (unsigned char* image, int height, int width, char* imageFileName)
{
int widthInBytes = width * BYTES_PER_PIXEL;
unsigned char padding[3] = {0, 0, 0};
int paddingSize = (4 - (widthInBytes) % 4) % 4;
int stride = (widthInBytes) + paddingSize;
FILE* imageFile = fopen(imageFileName, "wb");
unsigned char* fileHeader = createBitmapFileHeader(height, stride);
fwrite(fileHeader, 1, FILE_HEADER_SIZE, imageFile);
unsigned char* infoHeader = createBitmapInfoHeader(height, width);
fwrite(infoHeader, 1, INFO_HEADER_SIZE, imageFile);
int i;
for (i = 0; i < height; i++) {
fwrite(image + (i*widthInBytes), BYTES_PER_PIXEL, width, imageFile);
fwrite(padding, 1, paddingSize, imageFile);
}
fclose(imageFile);
}
unsigned char* createBitmapFileHeader (int height, int stride)
{
int fileSize = FILE_HEADER_SIZE + INFO_HEADER_SIZE + (stride * height);
static unsigned char fileHeader[] = {
0,0, /// signature
0,0,0,0, /// image file size in bytes
0,0,0,0, /// reserved
0,0,0,0, /// start of pixel array
};
fileHeader[ 0] = (unsigned char)('B');
fileHeader[ 1] = (unsigned char)('M');
fileHeader[ 2] = (unsigned char)(fileSize );
fileHeader[ 3] = (unsigned char)(fileSize >> 8);
fileHeader[ 4] = (unsigned char)(fileSize >> 16);
fileHeader[ 5] = (unsigned char)(fileSize >> 24);
fileHeader[10] = (unsigned char)(FILE_HEADER_SIZE + INFO_HEADER_SIZE);
return fileHeader;
}
unsigned char* createBitmapInfoHeader (int height, int width)
{
static unsigned char infoHeader[] = {
0,0,0,0, /// header size
0,0,0,0, /// image width
0,0,0,0, /// image height
0,0, /// number of color planes
0,0, /// bits per pixel
0,0,0,0, /// compression
0,0,0,0, /// image size
0,0,0,0, /// horizontal resolution
0,0,0,0, /// vertical resolution
0,0,0,0, /// colors in color table
0,0,0,0, /// important color count
};
infoHeader[ 0] = (unsigned char)(INFO_HEADER_SIZE);
infoHeader[ 4] = (unsigned char)(width );
infoHeader[ 5] = (unsigned char)(width >> 8);
infoHeader[ 6] = (unsigned char)(width >> 16);
infoHeader[ 7] = (unsigned char)(width >> 24);
infoHeader[ 8] = (unsigned char)(height );
infoHeader[ 9] = (unsigned char)(height >> 8);
infoHeader[10] = (unsigned char)(height >> 16);
infoHeader[11] = (unsigned char)(height >> 24);
infoHeader[12] = (unsigned char)(1);
infoHeader[14] = (unsigned char)(BYTES_PER_PIXEL*8);
return infoHeader;
}
于 2017-12-13T04:45:15.700 回答
29
无需使用任何其他库，您就可以查看BMP 文件格式。我过去已经实现了它，它可以在没有太多工作的情况下完成。
位图文件结构
每个位图文件包含一个位图文件头、一个位图信息头、一个颜色表和一个定义位图位的字节数组。该文件具有以下形式：
位图文件头 bmfh;
BITMAPINFOHEADER bmih;
RGBQUAD aColors[];
字节 aBitmapBits[];
...查看文件格式了解更多详情
于 2010-04-16T16:13:19.100 回答
12
这是从 https://en.wikipedia.org/wiki/User:Evercat/Buddhabrot.c复制的示例代码
void drawbmp (char * filename) {
unsigned int headers[13];
FILE * outfile;
int extrabytes;
int paddedsize;
int x; int y; int n;
int red, green, blue;
extrabytes = 4 - ((WIDTH * 3) % 4); // How many bytes of padding to add to each
// horizontal line - the size of which must
// be a multiple of 4 bytes.
if (extrabytes == 4)
extrabytes = 0;
paddedsize = ((WIDTH * 3) + extrabytes) * HEIGHT;
// Headers...
// Note that the "BM" identifier in bytes 0 and 1 is NOT included in these "headers".
headers[0] = paddedsize + 54; // bfSize (whole file size)
headers[1] = 0; // bfReserved (both)
headers[2] = 54; // bfOffbits
headers[3] = 40; // biSize
headers[4] = WIDTH; // biWidth
headers[5] = HEIGHT; // biHeight
// Would have biPlanes and biBitCount in position 6, but they're shorts.
// It's easier to write them out separately (see below) than pretend
// they're a single int, especially with endian issues...
headers[7] = 0; // biCompression
headers[8] = paddedsize; // biSizeImage
headers[9] = 0; // biXPelsPerMeter
headers[10] = 0; // biYPelsPerMeter
headers[11] = 0; // biClrUsed
headers[12] = 0; // biClrImportant
outfile = fopen(filename, "wb");
//
// Headers begin...
// When printing ints and shorts, we write out 1 character at a time to avoid endian issues.
//
fprintf(outfile, "BM");
for (n = 0; n <= 5; n++)
{
fprintf(outfile, "%c", headers[n] & 0x000000FF);
fprintf(outfile, "%c", (headers[n] & 0x0000FF00) >> 8);
fprintf(outfile, "%c", (headers[n] & 0x00FF0000) >> 16);
fprintf(outfile, "%c", (headers[n] & (unsigned int) 0xFF000000) >> 24);
}
// These next 4 characters are for the biPlanes and biBitCount fields.
fprintf(outfile, "%c", 1);
fprintf(outfile, "%c", 0);
fprintf(outfile, "%c", 24);
fprintf(outfile, "%c", 0);
for (n = 7; n <= 12; n++)
{
fprintf(outfile, "%c", headers[n] & 0x000000FF);
fprintf(outfile, "%c", (headers[n] & 0x0000FF00) >> 8);
fprintf(outfile, "%c", (headers[n] & 0x00FF0000) >> 16);
fprintf(outfile, "%c", (headers[n] & (unsigned int) 0xFF000000) >> 24);
}
//
// Headers done, now write the data...
//
for (y = HEIGHT - 1; y >= 0; y--) // BMP image format is written from bottom to top...
{
for (x = 0; x <= WIDTH - 1; x++)
{
red = reduce(redcount[x][y] + COLOUR_OFFSET) * red_multiplier;
green = reduce(greencount[x][y] + COLOUR_OFFSET) * green_multiplier;
blue = reduce(bluecount[x][y] + COLOUR_OFFSET) * blue_multiplier;
if (red > 255) red = 255; if (red < 0) red = 0;
if (green > 255) green = 255; if (green < 0) green = 0;
if (blue > 255) blue = 255; if (blue < 0) blue = 0;
// Also, it's written in (b,g,r) format...
fprintf(outfile, "%c", blue);
fprintf(outfile, "%c", green);
fprintf(outfile, "%c", red);
}
if (extrabytes) // See above - BMP lines must be of lengths divisible by 4.
{
for (n = 1; n <= extrabytes; n++)
{
fprintf(outfile, "%c", 0);
}
}
}
fclose(outfile);
return;
}
drawbmp(filename);
于 2015-08-15T17:33:42.930 回答
9
这是适用于我的代码的 C++ 变体。请注意，我必须更改大小计算以考虑行填充。
// mimeType = "image/bmp";
unsigned char file[14] = {
'B','M', // magic
0,0,0,0, // size in bytes
0,0, // app data
0,0, // app data
40+14,0,0,0 // start of data offset
};
unsigned char info[40] = {
40,0,0,0, // info hd size
0,0,0,0, // width
0,0,0,0, // heigth
1,0, // number color planes
24,0, // bits per pixel
0,0,0,0, // compression is none
0,0,0,0, // image bits size
0x13,0x0B,0,0, // horz resoluition in pixel / m
0x13,0x0B,0,0, // vert resolutions (0x03C3 = 96 dpi, 0x0B13 = 72 dpi)
0,0,0,0, // #colors in pallete
0,0,0,0, // #important colors
};
int w=waterfallWidth;
int h=waterfallHeight;
int padSize = (4-(w*3)%4)%4;
int sizeData = w*h*3 + h*padSize;
int sizeAll = sizeData + sizeof(file) + sizeof(info);
file[ 2] = (unsigned char)( sizeAll );
file[ 3] = (unsigned char)( sizeAll>> 8);
file[ 4] = (unsigned char)( sizeAll>>16);
file[ 5] = (unsigned char)( sizeAll>>24);
info[ 4] = (unsigned char)( w );
info[ 5] = (unsigned char)( w>> 8);
info[ 6] = (unsigned char)( w>>16);
info[ 7] = (unsigned char)( w>>24);
info[ 8] = (unsigned char)( h );
info[ 9] = (unsigned char)( h>> 8);
info[10] = (unsigned char)( h>>16);
info[11] = (unsigned char)( h>>24);
info[20] = (unsigned char)( sizeData );
info[21] = (unsigned char)( sizeData>> 8);
info[22] = (unsigned char)( sizeData>>16);
info[23] = (unsigned char)( sizeData>>24);
stream.write( (char*)file, sizeof(file) );
stream.write( (char*)info, sizeof(info) );
unsigned char pad[3] = {0,0,0};
for ( int y=0; y<h; y++ )
{
for ( int x=0; x<w; x++ )
{
long red = lround( 255.0 * waterfall[x][y] );
if ( red < 0 ) red=0;
if ( red > 255 ) red=255;
long green = red;
long blue = red;
unsigned char pixel[3];
pixel[0] = blue;
pixel[1] = green;
pixel[2] = red;
stream.write( (char*)pixel, 3 );
}
stream.write( (char*)pad, padSize );
}
于 2013-09-07T17:06:31.493 回答
9
请注意，这些行是从下到上保存的，而不是相反。
此外，扫描线的字节长度必须是四的倍数，您应该在行尾插入填充字节以确保这一点。
于 2010-04-16T16:18:06.283 回答
7
我编辑了 ralf 的 htp 代码，以便它可以编译（在 gcc 上，运行 ubuntu 16.04 lts）。这只是初始化变量的问题。
int w = 100; /* Put here what ever width you want */
int h = 100; /* Put here what ever height you want */
int red[w][h];
int green[w][h];
int blue[w][h];
FILE *f;
unsigned char *img = NULL;
int filesize = 54 + 3*w*h; //w is your image width, h is image height, both int
if( img )
free( img );
img = (unsigned char *)malloc(3*w*h);
memset(img,0,sizeof(img));
int x;
int y;
int r;
int g;
int b;
for(int i=0; i<w; i++)
{
for(int j=0; j<h; j++)
{
x=i; y=(h-1)-j;
r = red[i][j]*255;
g = green[i][j]*255;
b = blue[i][j]*255;
if (r > 255) r=255;
if (g > 255) g=255;
if (b > 255) b=255;
img[(x+y*w)*3+2] = (unsigned char)(r);
img[(x+y*w)*3+1] = (unsigned char)(g);
img[(x+y*w)*3+0] = (unsigned char)(b);
}
}
unsigned char bmpfileheader[14] = {'B','M', 0,0,0,0, 0,0, 0,0, 54,0,0,0};
unsigned char bmpinfoheader[40] = {40,0,0,0, 0,0,0,0, 0,0,0,0, 1,0, 24,0};
unsigned char bmppad[3] = {0,0,0};
bmpfileheader[ 2] = (unsigned char)(filesize );
bmpfileheader[ 3] = (unsigned char)(filesize>> 8);
bmpfileheader[ 4] = (unsigned char)(filesize>>16);
bmpfileheader[ 5] = (unsigned char)(filesize>>24);
bmpinfoheader[ 4] = (unsigned char)( w );
bmpinfoheader[ 5] = (unsigned char)( w>> 8);
bmpinfoheader[ 6] = (unsigned char)( w>>16);
bmpinfoheader[ 7] = (unsigned char)( w>>24);
bmpinfoheader[ 8] = (unsigned char)( h );
bmpinfoheader[ 9] = (unsigned char)( h>> 8);
bmpinfoheader[10] = (unsigned char)( h>>16);
bmpinfoheader[11] = (unsigned char)( h>>24);
f = fopen("img.bmp","wb");
fwrite(bmpfileheader,1,14,f);
fwrite(bmpinfoheader,1,40,f);
for(int i=0; i<h; i++)
{
fwrite(img+(w*(h-i-1)*3),3,w,f);
fwrite(bmppad,1,(4-(w*3)%4)%4,f);
}
fclose(f);
于 2017-05-22T21:06:51.693 回答
7
我只是想分享一个改进版的 Minhas Kamal 的代码，因为尽管它对大多数应用程序都足够好，但我仍然遇到了一些问题。要记住两件非常重要的事情：
- 代码（在撰写本文时）在两个静态数组上调用 free()。这将导致您的程序崩溃。所以我注释掉了这些行。
- 永远不要假设您的像素数据的间距始终为 (Width*BytesPerPixel)。最好让用户指定音高值。示例：在 Direct3D 中操作资源时，永远不能保证 RowPitch 是正在使用的字节深度的偶数倍。这可能会导致生成的位图中出现错误（尤其是在奇怪的分辨率下，例如 1366x768）。
下面，你可以看到我对他的代码的修改：
const int bytesPerPixel = 4; /// red, green, blue
const int fileHeaderSize = 14;
const int infoHeaderSize = 40;
void generateBitmapImage(unsigned char *image, int height, int width, int pitch, const char* imageFileName);
unsigned char* createBitmapFileHeader(int height, int width, int pitch, int paddingSize);
unsigned char* createBitmapInfoHeader(int height, int width);
void generateBitmapImage(unsigned char *image, int height, int width, int pitch, const char* imageFileName) {
unsigned char padding[3] = { 0, 0, 0 };
int paddingSize = (4 - (/*width*bytesPerPixel*/ pitch) % 4) % 4;
unsigned char* fileHeader = createBitmapFileHeader(height, width, pitch, paddingSize);
unsigned char* infoHeader = createBitmapInfoHeader(height, width);
FILE* imageFile = fopen(imageFileName, "wb");
fwrite(fileHeader, 1, fileHeaderSize, imageFile);
fwrite(infoHeader, 1, infoHeaderSize, imageFile);
int i;
for (i = 0; i < height; i++) {
fwrite(image + (i*pitch /*width*bytesPerPixel*/), bytesPerPixel, width, imageFile);
fwrite(padding, 1, paddingSize, imageFile);
}
fclose(imageFile);
//free(fileHeader);
//free(infoHeader);
}
unsigned char* createBitmapFileHeader(int height, int width, int pitch, int paddingSize) {
int fileSize = fileHeaderSize + infoHeaderSize + (/*bytesPerPixel*width*/pitch + paddingSize) * height;
static unsigned char fileHeader[] = {
0,0, /// signature
0,0,0,0, /// image file size in bytes
0,0,0,0, /// reserved
0,0,0,0, /// start of pixel array
};
fileHeader[0] = (unsigned char)('B');
fileHeader[1] = (unsigned char)('M');
fileHeader[2] = (unsigned char)(fileSize);
fileHeader[3] = (unsigned char)(fileSize >> 8);
fileHeader[4] = (unsigned char)(fileSize >> 16);
fileHeader[5] = (unsigned char)(fileSize >> 24);
fileHeader[10] = (unsigned char)(fileHeaderSize + infoHeaderSize);
return fileHeader;
}
unsigned char* createBitmapInfoHeader(int height, int width) {
static unsigned char infoHeader[] = {
0,0,0,0, /// header size
0,0,0,0, /// image width
0,0,0,0, /// image height
0,0, /// number of color planes
0,0, /// bits per pixel
0,0,0,0, /// compression
0,0,0,0, /// image size
0,0,0,0, /// horizontal resolution
0,0,0,0, /// vertical resolution
0,0,0,0, /// colors in color table
0,0,0,0, /// important color count
};
infoHeader[0] = (unsigned char)(infoHeaderSize);
infoHeader[4] = (unsigned char)(width);
infoHeader[5] = (unsigned char)(width >> 8);
infoHeader[6] = (unsigned char)(width >> 16);
infoHeader[7] = (unsigned char)(width >> 24);
infoHeader[8] = (unsigned char)(height);
infoHeader[9] = (unsigned char)(height >> 8);
infoHeader[10] = (unsigned char)(height >> 16);
infoHeader[11] = (unsigned char)(height >> 24);
infoHeader[12] = (unsigned char)(1);
infoHeader[14] = (unsigned char)(bytesPerPixel * 8);
return infoHeader;
}
于 2019-04-03T21:16:34.943 回答
2
如果使用上面的 C++ 函数在图像中间出现奇怪的颜色切换。确保以二进制模式打开外流：
imgFile.open(filename, std::ios_base::out | std::ios_base::binary);
否则 Windows 会在文件中间插入不需要的字符！（已经在这个问题上敲了几个小时）
在此处查看相关问题：为什么 ofstream 在 0x0A 之前插入一个 0x0D 字节？
于 2015-05-25T09:19:33.953 回答
2
最好的位图编码器不是您自己编写的。文件格式比人们预期的要复杂得多。事实证明，所有建议的答案都不会创建单色 (1bpp) 位图，而是写出 24bpp 文件，而这些文件恰好只使用 2 种颜色。
以下是使用Windows 映像组件的仅限 Windows 的解决方案。它不依赖于任何外部/第三方库，除了 Windows 附带的库。
像每个 C++ 程序一样，我们需要包含几个头文件。并在我们使用它时链接到Windowscodecs.lib ：
#include <Windows.h>
#include <comdef.h>
#include <comip.h>
#include <comutil.h>
#include <wincodec.h>
#include <vector>
#pragma comment(lib, "Windowscodecs.lib")
接下来，我们声明我们的容器（一个向量，向量！的bool！），以及一些方便的智能指针：
using _com_util::CheckError;
using container = std::vector<std::vector<bool>>;
_COM_SMARTPTR_TYPEDEF(IWICImagingFactory, __uuidof(IWICImagingFactory));
_COM_SMARTPTR_TYPEDEF(IWICBitmapEncoder, __uuidof(IWICBitmapEncoder));
_COM_SMARTPTR_TYPEDEF(IWICBitmapFrameEncode, __uuidof(IWICBitmapFrameEncode));
_COM_SMARTPTR_TYPEDEF(IWICStream, __uuidof(IWICStream));
_COM_SMARTPTR_TYPEDEF(IWICPalette, __uuidof(IWICPalette));
一切都解决了，我们可以直接进入实施。需要进行一些设置才能获得工厂、编码器、框架，并准备好一切：
void write_bitmap(wchar_t const* pathname, container const& data)
{
// Create factory
IWICImagingFactoryPtr sp_factory { nullptr };
CheckError(sp_factory.CreateInstance(CLSID_WICImagingFactory, nullptr,
CLSCTX_INPROC_SERVER));
// Create encoder
IWICBitmapEncoderPtr sp_encoder { nullptr };
CheckError(sp_factory->CreateEncoder(GUID_ContainerFormatBmp, nullptr, &sp_encoder));
// Create stream
IWICStreamPtr sp_stream { nullptr };
CheckError(sp_factory->CreateStream(&sp_stream));
CheckError(sp_stream->InitializeFromFilename(pathname, GENERIC_WRITE));
// Initialize encoder with stream
CheckError(sp_encoder->Initialize(sp_stream, WICBitmapEncoderNoCache));
// Create new frame
IWICBitmapFrameEncodePtr sp_frame { nullptr };
IPropertyBag2Ptr sp_properties { nullptr };
CheckError(sp_encoder->CreateNewFrame(&sp_frame, &sp_properties));
// Initialize frame with default properties
CheckError(sp_frame->Initialize(sp_properties));
// Set pixel format
// SetPixelFormat() requires a pointer to non-const
auto pf { GUID_WICPixelFormat1bppIndexed };
CheckError(sp_frame->SetPixelFormat(&pf));
if (!::IsEqualGUID(pf, GUID_WICPixelFormat1bppIndexed))
{
// Report unsupported pixel format
CheckError(WINCODEC_ERR_UNSUPPORTEDPIXELFORMAT);
}
// Set size derived from data argument
auto const width { static_cast<UINT>(data.size()) };
auto const height { static_cast<UINT>(data[0].size()) };
CheckError(sp_frame->SetSize(width, height));
// Set palette on frame. This is required since we use an indexed pixel format.
// Only GIF files support global palettes, so make sure to set it on the frame
// rather than the encoder.
IWICPalettePtr sp_palette { nullptr };
CheckError(sp_factory->CreatePalette(&sp_palette));
CheckError(sp_palette->InitializePredefined(WICBitmapPaletteTypeFixedBW, FALSE));
CheckError(sp_frame->SetPalette(sp_palette));
那时一切都设置好了，我们有一个框架可以将我们的数据转储到其中。对于 1bpp 文件，每个字节存储 8 个像素的信息。最左边的像素存储在 MSB 中，像素一直向下到最右边的像素存储在 LSB 中。
代码并不完全重要。当您替换输入的数据布局时，您将用适合您需要的任何内容替换它：
// Write data to frame
auto const stride { (width * 1 + 7) / 8 };
auto const size { height * stride };
std::vector<unsigned char> buffer(size, 127u);
// Convert data to match required layout. Each byte stores 8 pixels, with the
// MSB being the leftmost, the LSB the right-most.
for (size_t x { 0 }; x < data.size(); ++x)
{
for (size_t y { 0 }; y < data[x].size(); ++y)
{
auto shift { x % 8 };
auto mask { 0x80 >> shift };
auto bit { mask * data[x][y] };
auto& value { buffer[y * stride + x / 8] };
value &= ~mask;
value |= bit;
}
}
CheckError(sp_frame->WritePixels(height, stride,
static_cast<UINT>(buffer.size()), buffer.data()));
剩下的是将更改提交到帧和编码器，最终将图像文件写入磁盘：
// Commit frame
CheckError(sp_frame->Commit());
// Commit image
CheckError(sp_encoder->Commit());
}
这是一个测试程序，将图像写入作为第一个命令行参数传递的文件：
#include <iostream>
int wmain(int argc, wchar_t* argv[])
try
{
if (argc != 2)
{
return -1;
}
CheckError(::CoInitializeEx(nullptr, COINIT_APARTMENTTHREADED));
// Create 64x64 matrix
container data(64, std::vector<bool>(64, false));
// Fill with arrow pointing towards the upper left
for (size_t i { 0 }; i < data.size(); ++i)
{
data[0][i] = true;
data[i][0] = true;
data[i][i] = true;
}
::write_bitmap(argv[1], data);
::CoUninitialize();
}
catch (_com_error const& e)
{
std::wcout << L"Error!\n" << L" Message: " << e.ErrorMessage() << std::endl;
}
它产生以下图像（真正的 1bpp，大小为 574 字节）：
于 2020-01-14T23:23:56.413 回答
2
这是一个简单的 c++ bmp 图像文件类。
class bmp_img {
public:
constexpr static int header_size = 14;
constexpr static int info_header_size = 40;
bmp_img(size_t width, size_t height, size_t bpp = 3) :
bytes_per_pixel{ bpp }, image_px_width{ width }, image_px_height{ height }, row_width{ image_px_width * bytes_per_pixel },
row_padding{ (4 - row_width % 4) % 4 }, row_stride{ row_width + row_padding }, file_size{ header_size + info_header_size + (image_px_height * row_stride) },
image(image_px_height, std::vector<unsigned char>(row_width))
{
//header file type
file_header[0] = 'B';
file_header[1] = 'M';
//header file size info
file_header[2] = static_cast<unsigned char>(file_size);
file_header[3] = static_cast<unsigned char>(file_size >> 8);
file_header[4] = static_cast<unsigned char>(file_size >> 16);
file_header[5] = static_cast<unsigned char>(file_size >> 24);
//header offset to pixel data
file_header[10] = header_size + info_header_size;
//info header size
info_header[0] = info_header_size;
//info header image width
info_header[4] = static_cast<unsigned char>(image_px_width);
info_header[5] = static_cast<unsigned char>(image_px_width >> 8);
info_header[6] = static_cast<unsigned char>(image_px_width >> 16);
info_header[7] = static_cast<unsigned char>(image_px_width >> 24);
//info header image height
info_header[8] = static_cast<unsigned char>(image_px_height);
info_header[9] = static_cast<unsigned char>(image_px_height >> 8);
info_header[10] = static_cast<unsigned char>(image_px_height >> 16);
info_header[11] = static_cast<unsigned char>(image_px_height >> 24);
//info header planes
info_header[12] = 1;
//info header bits per pixel
info_header[14] = 8 * bytes_per_pixel;
}
size_t width() const {
return image_px_width;
}
size_t height() const {
return image_px_height;
}
void set_pixel(size_t x, size_t y, int r, int g, int b) {
image[y][x * bytes_per_pixel + 2] = r;
image[y][x * bytes_per_pixel + 1] = g;
image[y][x * bytes_per_pixel + 0] = b;
}
void fill(int r, int g, int b) {
for (int y = 0; y < image_px_height; ++y) {
for (int x = 0; x < image_px_width; ++x) {
set_pixel(x, y, r, g, b);
}
}
}
void write_to_file(const char* file_name) const {
std::ofstream img_file(file_name, std::ios_base::binary | std::ios_base::out);
img_file.write((char*)file_header, header_size);
img_file.write((char*)info_header, info_header_size);
std::vector<char> allignment(row_padding);
for (int y = image_px_height - 1; y >= 0; --y) {
img_file.write((char*)image[y].data(), row_width);
img_file.write(allignment.data(), row_padding);
}
img_file.close();
}
private:
size_t bytes_per_pixel;
size_t image_px_width;
size_t image_px_height;
size_t row_width;
size_t row_padding;
size_t row_stride;
size_t file_size;
unsigned char file_header[header_size] = { 0 };
unsigned char info_header[info_header_size] = { 0 };
std::vector<std::vector<unsigned char>> image;
};
于 2021-08-14T04:09:37.640 回答
1
C++ 答案，灵活的 API，假设 little-endian 系统对其进行编码。请注意，这使用 bmp 原生 y 轴（底部为 0）。
#include <vector>
#include <fstream>
struct image
{
image(int width, int height)
: w(width), h(height), rgb(w * h * 3)
{}
uint8_t & r(int x, int y) { return rgb[(x + y*w)*3 + 2]; }
uint8_t & g(int x, int y) { return rgb[(x + y*w)*3 + 1]; }
uint8_t & b(int x, int y) { return rgb[(x + y*w)*3 + 0]; }
int w, h;
std::vector<uint8_t> rgb;
};
template<class Stream>
Stream & operator<<(Stream & out, image const& img)
{
uint32_t w = img.w, h = img.h;
uint32_t pad = w * -3 & 3;
uint32_t total = 54 + 3*w*h + pad*h;
uint32_t head[13] = {total, 0, 54, 40, w, h, (24<<16)|1};
char const* rgb = (char const*)img.rgb.data();
out.write("BM", 2);
out.write((char*)head, 52);
for(uint32_t i=0 ; i<h ; i++)
{ out.write(rgb + (3 * w * i), 3 * w);
out.write((char*)&pad, pad);
}
return out;
}
int main()
{
image img(100, 100);
for(int x=0 ; x<100 ; x++)
{ for(int y=0 ; y<100 ; y++)
{ img.r(x,y) = x;
img.g(x,y) = y;
img.b(x,y) = 100-x;
}
}
std::ofstream("/tmp/out.bmp") << img;
}
于 2020-07-17T02:51:02.750 回答