2

我有这样的字段：

-----------------
   id    |  name  
-----------------
   1     |  name123  
-----------------
   2     |  name  
-----------------
   3     |  name456  
-----------------
   4     |  name

我想提取名称中有数字的行和包含这样的数字的字段

------------------------------
   id    |  name     | number
-----------------------------
   1     |  name123  |  123
-----------------------------
   3     |  name456  |  456

我们如何找到具有数字的记录并将数字提取为新字段？

4

3 回答 3

3

Here is another way to do with mysql

SELECT 
  id,
  name,
  SUBSTRING( 
    name,LEAST (
      if (Locate('0',name) >0,Locate('0',name),999),
      if (Locate('1',name) >0,Locate('1',name),999),
      if (Locate('2',name) >0,Locate('2',name),999),
      if (Locate('3',name) >0,Locate('3',name),999),
      if (Locate('4',name) >0,Locate('4',name),999),
      if (Locate('5',name) >0,Locate('5',name),999),
      if (Locate('6',name) >0,Locate('6',name),999),
      if (Locate('7',name) >0,Locate('7',name),999),
      if (Locate('8',name) >0,Locate('8',name),999),
      if (Locate('9',name) >0,Locate('9',name),999)
    ),LENGTH(name)
  ) as number
from users 
having number <> '' ;
于 2014-10-22T17:19:59.260 回答
3

您可以在 int 上使用 MySQL 的字符串转换来像这样去除名称

SELECT 
    t.id, 
    t.name, 
    REVERSE(REVERSE(t.name)+ 0) AS num,
    REPLACE(t.name,REVERSE(REVERSE(t.name)+ 0),'') AS actualname
FROM foobar t
HAVING num <> 0

诀窍是通过添加一个 0 mysql 比较名称中的数值...但是名称必须以数字开头...所以我反转它进行计算然后再次反转...注意所有您的姓名必须以姓名开头并以数字结尾，这样才能适用于所有人

小提琴演示

编辑：

因为您说有些可以以数字开头，而有些可以以数字结尾..然后试试这个

SELECT 
    t.id, 
    t.name, 
    REVERSE(REVERSE(t.name)+ 0) AS num,
    REPLACE(t.name,REVERSE(REVERSE(t.name)+ 0),'') AS actualname
FROM foobar t
HAVING num <> 0
UNION ALL
SELECT 
    t.id, 
    t.name, 
    t.name + 0 AS num,
    REPLACE(t.name,t.name + 0,'') AS actualname
FROM foobar t
HAVING num <> 0

另一个演示

于 2014-10-22T17:14:54.480 回答
0

Another way, assuming the number you want is at the end of the string. REVERSE() to put the number part in front, then CONVERT() to make it a number and strip off the text, then REVERSE() again WHERE name ends in a number. Feels like a kludge though:

select id, name, reverse(convert(reverse(name),signed ))
from tbl
where name REGEXP '[0-9]+$';

SQL Fiddle Example

于 2014-11-28T18:59:32.467 回答