KINWebBrowser是一个用于 iOS 应用程序的开源 Web 浏览器模块。我最近升级了 KINWebBrowser 以使用WKWebView开始逐步淘汰 UIWebView。这产生了显着的改进，但是：
问题：WKWebView 不允许用户启动包含电话号码、电子邮件地址、地图等 URL 的链接。
当从显示的页面作为链接启动时，如何配置 WKWebView 以启动这些备用 URL 的标准 iOS 行为？
关于WKWebKit的更多信息
问问题
22134 次
7 回答
27
通过将此功能添加到您的 KINWebBrowserViewController.m，我能够使其适用于 Google 地图链接（似乎与 target="_blank" 相关）和电话：
- (void)webView:(WKWebView *)webView decidePolicyForNavigationAction:(WKNavigationAction *)navigationAction decisionHandler:(void (^)(WKNavigationActionPolicy))decisionHandler
{
if(webView != self.wkWebView) {
decisionHandler(WKNavigationActionPolicyAllow);
return;
}
UIApplication *app = [UIApplication sharedApplication];
NSURL *url = navigationAction.request.URL;
if (!navigationAction.targetFrame) {
if ([app canOpenURL:url]) {
[app openURL:url];
decisionHandler(WKNavigationActionPolicyCancel);
return;
}
}
if ([url.scheme isEqualToString:@"tel"])
{
if ([app canOpenURL:url])
{
[app openURL:url];
decisionHandler(WKNavigationActionPolicyCancel);
return;
}
}
decisionHandler(WKNavigationActionPolicyAllow);
}
于 2014-10-22T19:13:09.100 回答
11
适用于 xcode 8.1、Swift 2.3。
对于 target="_blank"，电话号码 (tel:) 和电子邮件 (mailto:) 链接。
func webView(webView: WKWebView, decidePolicyForNavigationAction navigationAction: WKNavigationAction, decisionHandler: (WKNavigationActionPolicy) -> Void) {
if webView != self.webview {
decisionHandler(.Allow)
return
}
let app = UIApplication.sharedApplication()
if let url = navigationAction.request.URL {
// Handle target="_blank"
if navigationAction.targetFrame == nil {
if app.canOpenURL(url) {
app.openURL(url)
decisionHandler(.Cancel)
return
}
}
// Handle phone and email links
if url.scheme == "tel" || url.scheme == "mailto" {
if app.canOpenURL(url) {
app.openURL(url)
decisionHandler(.Cancel)
return
}
}
decisionHandler(.Allow)
}
}
为 swift 4.0 更新
func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
if webView != self.webView {
decisionHandler(.allow)
return
}
let app = UIApplication.shared
if let url = navigationAction.request.url {
// Handle target="_blank"
if navigationAction.targetFrame == nil {
if app.canOpenURL(url) {
app.open(url)
decisionHandler(.cancel)
return
}
}
// Handle phone and email links
if url.scheme == "tel" || url.scheme == "mailto" {
if app.canOpenURL(url) {
app.open(url)
}
decisionHandler(.cancel)
return
}
decisionHandler(.allow)
}
}
于 2016-11-22T13:02:05.843 回答
9
您需要实现另一个回调才能做到这一点（Swift 5.0）：
// Gets called if webView cant handle URL
func webView(_ webView: WKWebView, didFailProvisionalNavigation navigation: WKNavigation!, withError error: Error) {
guard let failingUrlStr = (error as NSError).userInfo["NSErrorFailingURLStringKey"] as? String else { return }
let failingUrl = URL(string: failingUrlStr)!
switch failingUrl {
// Needed to open Facebook
case _ where failingUrlStr.hasPrefix("fb:"):
if #available(iOS 10.0, *) {
UIApplication.shared.open(failingUrl, options: [:], completionHandler: nil)
return
} // Else: Do nothing, iOS 9 and earlier will handle this
// Needed to open Mail-app
case _ where failingUrlStr.hasPrefix("mailto:"):
if UIApplication.shared.canOpenURL(failingUrl) {
UIApplication.shared.open(failingUrl, options: [:], completionHandler: nil)
return
}
// Needed to open Appstore-App
case _ where failingUrlStr.hasPrefix("itmss://itunes.apple.com/"):
if UIApplication.shared.canOpenURL(failingUrl) {
UIApplication.shared.open(failingUrl, options: [:], completionHandler: nil)
return
}
default: break
}
}
现在 Facebook、Mail、Appstore 等可以直接从您的应用程序调用，而无需打开 Safari
编辑：用标准的 hasPrefix() 方法替换了自定义的 startsWith() 方法。
于 2017-03-28T09:21:07.950 回答
0
这对 Xcode 8 WKWebview 有帮助
func webView(_ webView: WKWebView, createWebViewWith configuration: WKWebViewConfiguration, for navigationAction: WKNavigationAction, windowFeatures: WKWindowFeatures) -> WKWebView? {
if navigationAction.targetFrame == nil {
let url = navigationAction.request.url
if url?.description.range(of: "http://") != nil || url?.description.range(of: "https://") != nil || url?.description.range(of: "mailto:") != nil || url?.description.range(of: "tel:") != nil {
UIApplication.shared.openURL(url!)
}
}
return nil
}
编辑：
在链接中必须是属性target="_blank"。
于 2016-10-03T09:06:42.797 回答
0
斯威夫特 4.2 更新
很抱歉挖掘了一篇旧帖子，但我遇到了同样的问题，并更新了 Swift 4.2 的解决方案。我已将我的解决方案放在这里，以便它可以帮助其他人，如果没有，我希望下次我使用 WKWebView 时能找到它！
func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
let url = navigationAction.request.url?.absoluteString
let urlElements = url?.components(separatedBy: ":") ?? []
switch urlElements[0] {
case "tel":
UIApplication.shared.openURL(navigationAction.request.url!)
decisionHandler(.cancel)
case "mailto":
UIApplication.shared.openURL(navigationAction.request.url!)
decisionHandler(.cancel)
default:
decisionHandler(.allow)
}
}
我使用以下网站作为灵感：
SubzDesignz iOS Swift 4 WKWebview – 检测 tel、mailto、target=”_blank” 和 CheckConnection
于 2018-11-26T11:49:03.620 回答
0
我来到这里寻找如何在 wkwebview 上打开 gmail 附件。
我的解决方案很简单：
func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
if navigationAction.targetFrame == nil, let redirect = navigationAction.request.url {
if UIApplication.shared.canOpenURL(redirect) {
self.webViewMail?.load(navigationAction.request)
decisionHandler(.cancel)
return
}
}
decisionHandler(.allow)
}
于 2018-04-11T13:15:31.533 回答
-1
上面的答案对我有用，但我需要它来重写 swift 2.3
if navigationAction.targetFrame == nil {
let url = navigationAction.request.mainDocumentURL
if url?.description.rangeOfString("mailto:")?.startIndex != nil ||
url?.description.rangeOfString("tel:")?.startIndex != nil
{
if #available(iOS 10, *) {
UIApplication.sharedApplication().openURL(url!,options: [:], completionHandler: nil)
} else {
UIApplication.sharedApplication().openURL(url!) // deprecated
}
}
}
于 2016-11-07T12:44:27.263 回答