linux - 如何在启动每个服务之前执行命令

Question

我想为 /etc/init.d 中的每个服务设置安全限制说

ulimit -c unlimited

但这应该在发出“ service <process> start”或“ /etc/init.d/<process> start”时执行。

是否有通用路径，所以如果我们在那里写，它将适用于“启动”服务时的所有服务。

Answer 1

如果您创建这样的文件：

/etc/init.d/.commonStuff

并将您希望对所有脚本通用的命令放入其中：（没有 '#!/usr/bin/bash' 行）

# This code is meant to be included by another script.
ulimit -c unlimited
umask 027
THIS_VARIABLE="will exist once the include is completed"
export THIS_VALIABLE    # And now it is exportable too

然后在每个脚本中，您可以添加这些行（在方便的地方）：

# Include the common settings
. /etc/init.d/.commonStuff

前导点是“包含其他文件”指示器。

确保新文件受到保护（即由 root 拥有），并从中删除可执行标志，以明确它不打算单独执行。（访问权限不应超过 644）。

Answer 2

The files in /etc/init.d/ are pretty much all bash shell scripts. So this is a bit dirty but you could replace /bin/sh with a script but you have to be very careful how you do it so you don't bork your system in the process.

First create a file sh.wrap in the current directory with these contents:

#/bin/sh.real
ulimit -c unlimited
/bin/sh.real "$@"

Then install it like this:

chmod +x sh.wrap
sudo cp /bin/sh /bin/sh.real
sudo mv sh.wrap /bin/sh

This is a dirty hack but it could work for what you want to do.

I recommend you figure out why using /etc/security/limits.conf is not working for you and use this instead but I really hate "why would you do that?" answers.